Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 5, Problem 69A

a)

Interpretation Introduction

Interpretation : The electron transitions emit energy or require the absorption of energy to be indicated.

Concept Introduction: The energies or energy levels that an electron can have are determined by the Schrodinger equation's solution. The atomic orbital, which is derived from the Schrodinger equation for each energy level, expresses the probability that an electron will be found at a particular place around the nucleus.

a)

Expert Solution
Check Mark

Answer to Problem 69A

The electron transition for 3p to 3s emits energy.

Explanation of Solution

Each energy sublevel has an associated orbital or orbitals with a variety of forms. In which an electron is most likely to be found is described by its orbitals.

When atoms absorb energy, their electrons move to higher energy levels. These electrons lose energy by emitting light when they return to lower energy levels.

The order of orbital filling of the atoms is given as:

  1s,2s,3p,3s,3p,4s,3d,4p,5s,4d,5p,6s,4f,5d,6p,7s,5f,6d,7p

Where, s orbitals accommodate 2 electrons, p orbitals 6 electrons, d orbitals 10 electrons, and f orbitals 14 electrons.

In the given electronic transition 3p to 3s , the electrons are lost by emitting energy.

Since the transition is from a higher energy level to a lower energy level.

b)

Interpretation Introduction

Interpretation : The electron transitions emit energy or require the absorption of energy to be indicated.

Concept Introduction: The energies or energy levels that an electron can have are determined by the Schrodinger equation's solution. The atomic orbital, which is derived from the Schrodinger equation for each energy level, expresses the probability that an electron will be found at a particular place around the nucleus.

b)

Expert Solution
Check Mark

Answer to Problem 69A

The electron transition for 3p to 4p absorbs energy.

Explanation of Solution

Each energy sublevel has an associated orbital or orbitals with a variety of forms. In which an electron is most likely to be found is described by its orbitals.

When atoms absorb energy, their electrons move to higher energy levels. These electrons lose energy by emitting light when they return to lower energy levels.

The order of orbital filling of the atoms is given as

  1s,2s,3p,3s,3p,4s,3d,4p,5s,4d,5p,6s,4f,5d,6p,7s,5f,6d,7p

Where, s orbitals accommodate 2 electrons, p orbitals 6 electrons, d orbitals 10 electrons, and f orbitals 14 electrons.

In the given electronic transition 3p to 4p , the electrons absorb energy.

Since the transition is from a lower energy level to a higher energy level.

c)

Interpretation Introduction

Interpretation : The electron transitions emit energy or require the absorption of energy to be indicated.

Concept Introduction: The energies or energy levels that an electron can have are determined by the Schrodinger equation's solution. The atomic orbital, which is derived from the Schrodinger equation for each energy level, expresses the probability that an electron will be found at a particular place around the nucleus.

c)

Expert Solution
Check Mark

Answer to Problem 69A

The electron transition for 2s to 2p absorbs energy.

Explanation of Solution

Each energy sublevel has an associated orbital or orbitals with a variety of forms. In which an electron is most likely to be found is described by its orbitals.

When atoms absorb energy, their electrons move to higher energy levels. These electrons lose energy by emitting light when they return to lower energy levels.

The order of orbital filling of the atoms is given as

  1s,2s,3p,3s,3p,4s,3d,4p,5s,4d,5p,6s,4f,5d,6p,7s,5f,6d,7p

Where, s orbitals accommodate 2 electrons, p orbitals 6 electrons, d orbitals 10 electrons, and f orbitals 14 electrons.

In the given electronic transition 2s to 2p , the electrons absorb energy.

Since the transition is from a lower energy level to a higher energy level.

d)

Interpretation Introduction

Interpretation : The electron transitions emit energy or require the absorption of energy to be indicated.

Concept Introduction: The energies or energy levels that an electron can have are determined by the Schrodinger equation's solution. The atomic orbital, which is derived from the Schrodinger equation for each energy level, expresses the probability that an electron will be found at a particular place around the nucleus.

d)

Expert Solution
Check Mark

Answer to Problem 69A

The electron transition for 1s to 2s absorbs energy.

Explanation of Solution

Each energy sublevel has an associated orbital or orbitals with a variety of forms. In which an electron is most likely to be found is described by its orbitals.

When atoms absorb energy, their electrons move to higher energy levels. These electrons lose energy by emitting light when they return to lower energy levels.

The order of orbital filling of the atoms is given as

  1s,2s,3p,3s,3p,4s,3d,4p,5s,4d,5p,6s,4f,5d,6p,7s,5f,6d,7p

Where, s orbitals accommodate 2 electrons, p orbitals 6 electrons, d orbitals 10 electrons, and f orbitals 14 electrons.

In the given electronic transition 1s to 2s , the electrons absorb energy.

Since the transition is from a lower energy level to a higher energy level.

Chapter 5 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 5.2 - Prob. 11LCCh. 5.2 - Prob. 12LCCh. 5.2 - Prob. 13LCCh. 5.2 - Prob. 14LCCh. 5.3 - Prob. 15SPCh. 5.3 - Prob. 16SPCh. 5.3 - Prob. 17SPCh. 5.3 - Prob. 18SPCh. 5.3 - Prob. 19LCCh. 5.3 - Prob. 20LCCh. 5.3 - Prob. 21LCCh. 5.3 - Prob. 22LCCh. 5.3 - Prob. 23LCCh. 5.3 - Prob. 24LCCh. 5.3 - Prob. 25LCCh. 5.3 - Prob. 26LCCh. 5 - Prob. 27ACh. 5 - Prob. 28ACh. 5 - Prob. 29ACh. 5 - Prob. 30ACh. 5 - Prob. 31ACh. 5 - Prob. 32ACh. 5 - Prob. 33ACh. 5 - Prob. 34ACh. 5 - Prob. 35ACh. 5 - Prob. 36ACh. 5 - Prob. 37ACh. 5 - Prob. 38ACh. 5 - Prob. 39ACh. 5 - Prob. 40ACh. 5 - Prob. 41ACh. 5 - Prob. 42ACh. 5 - Prob. 43ACh. 5 - Prob. 44ACh. 5 - Prob. 45ACh. 5 - Prob. 46ACh. 5 - Prob. 47ACh. 5 - Prob. 48ACh. 5 - Prob. 49ACh. 5 - Prob. 50ACh. 5 - Prob. 51ACh. 5 - Prob. 52ACh. 5 - Prob. 53ACh. 5 - Prob. 54ACh. 5 - Prob. 55ACh. 5 - Prob. 56ACh. 5 - Prob. 57ACh. 5 - Prob. 58ACh. 5 - Prob. 59ACh. 5 - Prob. 60ACh. 5 - Prob. 61ACh. 5 - Prob. 62ACh. 5 - Prob. 63ACh. 5 - Prob. 64ACh. 5 - Prob. 65ACh. 5 - Prob. 66ACh. 5 - Prob. 67ACh. 5 - Prob. 68ACh. 5 - Prob. 69ACh. 5 - Prob. 70ACh. 5 - Prob. 71ACh. 5 - Prob. 72ACh. 5 - Prob. 73ACh. 5 - Prob. 74ACh. 5 - Prob. 75ACh. 5 - Prob. 77ACh. 5 - Prob. 78ACh. 5 - Prob. 79ACh. 5 - Prob. 80ACh. 5 - Prob. 81ACh. 5 - Prob. 82ACh. 5 - Prob. 83ACh. 5 - Prob. 85ACh. 5 - Prob. 86ACh. 5 - Prob. 88ACh. 5 - Prob. 89ACh. 5 - Prob. 90ACh. 5 - Prob. 91ACh. 5 - Prob. 92ACh. 5 - Prob. 93ACh. 5 - Prob. 94ACh. 5 - Prob. 95ACh. 5 - Prob. 96ACh. 5 - Prob. 97ACh. 5 - Prob. 98ACh. 5 - Prob. 99ACh. 5 - Prob. 100ACh. 5 - Prob. 101ACh. 5 - Prob. 102ACh. 5 - Prob. 103ACh. 5 - Prob. 104ACh. 5 - Prob. 105ACh. 5 - Prob. 106ACh. 5 - Prob. 1STPCh. 5 - Prob. 2STPCh. 5 - Prob. 3STPCh. 5 - Prob. 4STPCh. 5 - Prob. 5STPCh. 5 - Prob. 6STPCh. 5 - Prob. 7STPCh. 5 - Prob. 8STPCh. 5 - Prob. 9STPCh. 5 - Prob. 10STPCh. 5 - Prob. 11STPCh. 5 - Prob. 12STPCh. 5 - Prob. 13STPCh. 5 - Prob. 14STPCh. 5 - Prob. 15STP
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