Interpretation: The number of paired electrons in an atom of each element is to be determined.
Concept Introduction: Electronic configurations refer to the arrangements of electrons in different orbitals around atoms' nuclei.
Answer to Problem 58A
There are two paired electrons in the helium element.
Explanation of Solution
Electronic configurations refer to the arrangements of electrons in different orbitals around atoms' nuclei.
The Aufbau principle, the Pauli exclusion principle, and Hund's rule are three rules that can be used to determine the electronic configuration of atoms.
The energy levels and symbols for each sub-level occupied by an electron are written for an atom's electrical configuration.
The given element is helium.
The electronic configuration of helium is
There is only one orbital that can accommodate only two electrons. So, the atoms are filled.
Hence, there are two paired electrons in helium.
Interpretation: The number of paired electrons in an atom of each element is to be determined.
Concept Introduction: Electronic configurations refer to the arrangements of electrons in different orbitals around atoms' nuclei.
Answer to Problem 58A
There are ten paired electrons in the sodium element.
Explanation of Solution
Electronic configurations refer to the arrangements of electrons in different orbitals around atoms' nuclei.
The Aufbau principle, the Pauli exclusion principle, and Hund's rule are three rules that can be used to determine the electronic configuration of atoms.
The energy levels and symbols for each sub-level occupied by an electron are written for an atom's electrical configuration.
The given element is helium.
The electronic configuration of sodium is
There are 3 s orbitals and 1 p orbital. There are paired electrons in 1s, 2s, and 2p orbitals.
The pairing of sodium atoms is given as:
Hence, there are ten paired electrons in helium.
Interpretation: The number of paired electrons in an atom of each element is to be determined.
Concept Introduction: Electronic configurations refer to the arrangements of electrons in different orbitals around atoms' nuclei.
Answer to Problem 58A
There are four paired electrons in the boron element.
Explanation of Solution
Electronic configurations refer to the arrangements of electrons in different orbitals around atoms' nuclei.
The Aufbau principle, the Pauli exclusion principle, and Hund's rule are three rules that can be used to determine the electronic configuration of atoms.
The energy levels and symbols for each sub-level occupied by an electron are written for an atom's electrical configuration.
The given element is boron.
The electronic configuration of boron is
There are 2 s orbitals and 1 p orbital. There are paired electrons in 1s and 2s orbitals.
The pairing of boron atom is given as
Hence, there are four paired electrons in boron.
Interpretation: The number of paired electrons in an atom of each element is to be determined.
Concept Introduction: Electronic configurations refer to the arrangements of electrons in different orbitals around atoms' nuclei.
Answer to Problem 58A
There are six paired electrons in the oxygen element.
Explanation of Solution
Electronic configurations refer to the arrangements of electrons in different orbitals around atoms' nuclei.
The Aufbau principle, the Pauli exclusion principle, and Hund's rule are three rules that can be used to determine the electronic configuration of atoms.
The energy levels and symbols for each sub-level occupied by an electron are written for an atom's electrical configuration.
The given element is oxygen.
The electronic configuration of oxygen is
There are 2 s orbitals and 1 p orbital. There are paired electrons in 1s, 2s, and 2p orbitals.
The pairing of oxygen atoms is given as
Hence, there are six paired electrons in oxygen.
Chapter 5 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
- Devise electrochemical cells in which the following reactions could be made to occur. If liquid junctions are necessary, note them in the cell schematic appropriately, but neglect their effects. (a) H2OH + OH¯ (b) 2H2O2 H₂O (c) 2PbSO4 + 2H2O (d) An TMPD PыO₂+ Pb + 4H+ + 20%¯¯ An + TMPD (in acetonitrile, where An and An are anthracene and its anion radical, and TMPD and TMPD are N,N,N',N'-tetramethyl-p-phenylenediamine and its cation radical. Use anthracene potentials for DMF solutions given in Appendix C.3). (e) 2Ce3+ + 2H + BQ 2Ce4+ + H2Q (aqueous, where BQ is p-benzoquinone and H₂Q is p- hydroquinone) (f) Ag +Agl (aqueous) (g) Fe3+ + Fe(CN)6 Fe²+ + Fe(CN) (aqueous)arrow_forwardConsider each of the following electrode-solution interfaces, and write the equation for the elec- trode reaction that occurs first when the potential is moved in (1) a negative direction and (2) a posi- tive direction from the open-circuit potential. Next to each reaction write the approximate potential for the reaction in V vs. SCE (assuming the reaction is reversible). (a) Pt/Cu2+ (0.01 M), Cd2+ (0.01 M), H2SO4(1 M) (b) Pt/Sn2+ (0.01 M), Sn4+ (0.01 M), HCl(1 M) (c) Hg/Cd2+ (0.01 M), Zn2+ (0.01 M), HCl(1 M)arrow_forwardWhat are the major products of both of the organic reactions. Please be sure to use wedge and dash bonds to show the stereochemistry of the products if it is needed. Please include the final product as well as a digram/drawing to show the mechanism of the reaction.arrow_forward
- K Problem 16 of 24 Submit Draw the starting structure that would yield this product under these conditions. Select to Draw 1. NH4Cl, NaCN 2. HCI, H2O, A NH3 + 0arrow_forwardGive detailed me detailed mechanism Solution with explanation needed. Don't give Ai generated solution. avoid handwritten Solutionarrow_forwardShow work with explanation needed. don't give Ai generated solutionarrow_forward
- K Problem 21 of 24 Submit Draw the missing organic structures in the following multistep synthesis. Show the final product at physiological pH (pH = 7.4). Ignore any inorganic byproducts formed. H 0 NH3 Select to Draw HCN H+, H2O Select to Draw Select to Draw Δarrow_forwardShow work with explanation needed. Don't give Ai generated solution. Give correct solutionarrow_forwardK Problem 23 of 24 Submit Draw the product of the reaction shown below at physiological pH (pH = 7.4). Ignore inorganic byproducts. S O 1. NH3, 2. HCN 3. H+, H₂O, A Select to Drawarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY