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Interpretation: From the given options, the essential part of Dalton's atomic model is to be explained.
Concept Introduction: John Dalton, an English physicist, and chemist, proposed his atomic theory in
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Answer to Problem 104A
Dalton's atomic theory includes five postulates regarding atoms and their characteristics and behavior but none regarding electrons, neutrons, or atomic nuclei. Hence the correct answer is a) indivisible atoms.
Explanation of Solution
Reason for true statement:
Dalton's atomic model has five postulates:
- All matter is composed of tiny particles known as atoms.
- Atoms are both indivisible and indestructible.
- All atoms of a specific element possess the same attributes, including weight.
- Atoms of various elements have varying masses.
- When atoms of various elements combine to create compounds, these combinations always occur in the same whole-number proportions.
Therefore, the correct answer is a) indivisible atoms.
Dalton's atomic theory includes five postulates regarding atoms and their characteristics and behavior but none regarding electrons, neutrons, or atomic nuclei. Hence the correct answer is a) indivisible atoms.
Reason for false statements:
According to the first part of his theory, all matter is constructed from indivisible atoms, which are the fundamental building blocks of all matter
Chapter 5 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
- 2' P17E.6 The oxidation of NO to NO 2 2 NO(g) + O2(g) → 2NO2(g), proceeds by the following mechanism: NO + NO → N₂O₂ k₁ N2O2 NO NO K = N2O2 + O2 → NO2 + NO₂ Ко Verify that application of the steady-state approximation to the intermediate N2O2 results in the rate law d[NO₂] _ 2kk₁[NO][O₂] = dt k+k₁₂[O₂]arrow_forwardPLEASE ANSWER BOTH i) and ii) !!!!arrow_forwardE17E.2(a) The following mechanism has been proposed for the decomposition of ozone in the atmosphere: 03 → 0₂+0 k₁ O₁₂+0 → 03 K →> 2 k₁ Show that if the third step is rate limiting, then the rate law for the decomposition of O3 is second-order in O3 and of order −1 in O̟.arrow_forward
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