Interpretation: The number of electrons in the second-highest occupied energy of the atoms are to be identified.
Concept Introduction: Electronic configurations refer to the arrangements of electrons in different orbitals around atoms' nuclei.
Answer to Problem 43A
The number of electrons in the second energy level of chlorine atom is
Explanation of Solution
Electronic configurations refer to the arrangements of electrons in different orbitals around atoms' nuclei.
The Aufbau principle, the Pauli exclusion principle, and Hund's rule are three rules that can be used to determine the electronic configuration of atoms.
To find the electrons in the highest energy level, the electronic configuration should be known.
The
The electronic configuration of the chlorine atom is written as follows:
The second energy level of chlorine is 2s and 2p orbitals and the number of electrons is found by adding the superscripts of 2s and 2p orbitals.
The chlorine has
Interpretation: The number of electrons in the second-highest occupied energy of the atoms are to be identified.
Concept Introduction: Electronic configurations refer to the arrangements of electrons in different orbitals around atoms' nuclei.
Answer to Problem 43A
The number of electrons in second energy level of phosphorous atom is
Explanation of Solution
Electronic configurations refer to the arrangements of electrons in different orbitals around atoms' nuclei.
The Aufbau principle, the Pauli exclusion principle, and Hund's rule are three rules that can be used to determine the electronic configuration of atoms.
To find the electrons in the highest energy level, the electronic configuration should be known.
The atomic number of the element phosphorous is 15.
The electronic configuration of the chlorine atom is written as follows:
The second energy level of phosphorous is 2s and 2p orbitals and the number of electrons is found by adding the superscripts of 2s and 2p orbitals.
The phosphorous has
Interpretation: The number of electrons in the second-highest occupied energy of the atoms are to be identified.
Concept Introduction: Electronic configurations refer to the arrangements of electrons in different orbitals around atoms' nuclei.
Answer to Problem 43A
The number of electrons in second energy level of potassium atom is
Explanation of Solution
Electronic configurations refer to the arrangements of electrons in different orbitals around atoms' nuclei.
The Aufbau principle, the Pauli exclusion principle, and Hund's rule are three rules that can be used to determine the electronic configuration of atoms.
To find the electrons in the highest energy level, the electronic configuration should be known.
The atomic number of element potassium is 19.
The electronic configuration of the chlorine atom is written as follows:
The second energy level of potassium is 3s and 3p orbitals and the number of electrons is found by adding the superscripts of 3s and 3p orbitals.
The potassium has
Chapter 5 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
- Devise electrochemical cells in which the following reactions could be made to occur. If liquid junctions are necessary, note them in the cell schematic appropriately, but neglect their effects. (a) H2OH + OH¯ (b) 2H2O2 H₂O (c) 2PbSO4 + 2H2O (d) An TMPD PыO₂+ Pb + 4H+ + 20%¯¯ An + TMPD (in acetonitrile, where An and An are anthracene and its anion radical, and TMPD and TMPD are N,N,N',N'-tetramethyl-p-phenylenediamine and its cation radical. Use anthracene potentials for DMF solutions given in Appendix C.3). (e) 2Ce3+ + 2H + BQ 2Ce4+ + H2Q (aqueous, where BQ is p-benzoquinone and H₂Q is p- hydroquinone) (f) Ag +Agl (aqueous) (g) Fe3+ + Fe(CN)6 Fe²+ + Fe(CN) (aqueous)arrow_forwardConsider each of the following electrode-solution interfaces, and write the equation for the elec- trode reaction that occurs first when the potential is moved in (1) a negative direction and (2) a posi- tive direction from the open-circuit potential. Next to each reaction write the approximate potential for the reaction in V vs. SCE (assuming the reaction is reversible). (a) Pt/Cu2+ (0.01 M), Cd2+ (0.01 M), H2SO4(1 M) (b) Pt/Sn2+ (0.01 M), Sn4+ (0.01 M), HCl(1 M) (c) Hg/Cd2+ (0.01 M), Zn2+ (0.01 M), HCl(1 M)arrow_forwardWhat are the major products of both of the organic reactions. Please be sure to use wedge and dash bonds to show the stereochemistry of the products if it is needed. Please include the final product as well as a digram/drawing to show the mechanism of the reaction.arrow_forward
- K Problem 16 of 24 Submit Draw the starting structure that would yield this product under these conditions. Select to Draw 1. NH4Cl, NaCN 2. HCI, H2O, A NH3 + 0arrow_forwardGive detailed me detailed mechanism Solution with explanation needed. Don't give Ai generated solution. avoid handwritten Solutionarrow_forwardShow work with explanation needed. don't give Ai generated solutionarrow_forward
- K Problem 21 of 24 Submit Draw the missing organic structures in the following multistep synthesis. Show the final product at physiological pH (pH = 7.4). Ignore any inorganic byproducts formed. H 0 NH3 Select to Draw HCN H+, H2O Select to Draw Select to Draw Δarrow_forwardShow work with explanation needed. Don't give Ai generated solution. Give correct solutionarrow_forwardK Problem 23 of 24 Submit Draw the product of the reaction shown below at physiological pH (pH = 7.4). Ignore inorganic byproducts. S O 1. NH3, 2. HCN 3. H+, H₂O, A Select to Drawarrow_forward
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