Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 5, Problem 38A

(a)

Interpretation Introduction

Interpretation: The maximum number of electrons present in the 2s sublevels needs to be determined.

Concept Introduction: An atomic orbital explains the position of an electron in an atom. An atomic orbital can be occupied by a maximum of two electrons with opposite spins. The four basic atomic orbitals are s, p, d, and f . The number of electrons in each orbital can be explained with the help of quantum numbers. For any given shell, the number of subshells can be calculated as 2l+1 . Here, l is an azimuthal quantum number. In each subshell maximum of two electrons (opposite spin) can be occupied. Thus, the maximum number of electrons in a subshell can be calculated using the following formula:

  X=22l+1=4l+2

Here, l is an azimuthal quantum number.

(a)

Expert Solution
Check Mark

Answer to Problem 38A

2

Explanation of Solution

The given orbital is 2s. For s orbital, the value of the azimuthal quantum number is 0. Thus, the maximum number of electrons present in it can be calculated as follows:

  X2s=4l+2=40+2=2

Therefore, the maximum number of electrons present in the 2s sublevel is 2.

(b)

Interpretation Introduction

Interpretation: The maximum number of electrons present in the 4s sublevels needs to be determined.

Concept Introduction: An atomic orbital explains the position of an electron in an atom. An atomic orbital can be occupied by a maximum of two electrons with opposite spins. The four basic atomic orbitals are s, p, d, and f . The number of electrons in each orbital can be explained with the help of quantum numbers. For any given shell, the number of subshells can be calculated as 2l+1 here, l is an azimuthal quantum number. In each subshell maximum of two electrons (opposite spin) can be occupied. Thus, the maximum number of electrons in a subshell can be calculated using the following formula:

  X=22l+1=4l+2

Here, l is an azimuthal quantum number.

(b)

Expert Solution
Check Mark

Answer to Problem 38A

2

Explanation of Solution

The given orbital is 4s. For s orbital, the value of an azimuthal quantum number is 0. Thus, the maximum number of electrons present in it can be calculated as follows:

  X4s=4l+2=40+2=2

Therefore, the maximum number of electrons present in the 4s sublevel is 2.

(c)

Interpretation Introduction

Interpretation: The maximum number of electrons present in the 4p sublevels needs to be determined.

Concept Introduction: An atomic orbital explains the position of an electron in an atom. An atomic orbital can be occupied by a maximum of two electrons with opposite spins. The four basic atomic orbitals are s, p, d, and f . The number of electrons in each orbital can be explained with the help of quantum numbers. For any given shell, the number of subshells can be calculated as 2l+1 . Here, l is an azimuthal quantum number. In each subshell maximum of two electrons (opposite spin) can be occupied. Thus, the maximum number of electrons in a subshell can be calculated using the following formula:

  X=22l+1=4l+2

Here, l is an azimuthal quantum number.

(c)

Expert Solution
Check Mark

Answer to Problem 38A

6

Explanation of Solution

The given orbital is 4p. For p orbital, the value of an azimuthal quantum number is 1. Thus, the maximum number of electrons present in it can be calculated as follows:

  X4p=4l+2=41+2=6

Therefore, the maximum number of electrons present in the 4p sublevel is 6.

(d)

Interpretation Introduction

Interpretation: The maximum number of electrons present in the 4f sublevels needs to be determined.

Concept Introduction: An atomic orbital explains the position of an electron in an atom. An atomic orbital can be occupied by a maximum of two electrons with opposite spins. The four basic atomic orbitals are s, p, d, and f . The number of electrons in each orbital can be explained with the help of quantum numbers. For any given shell, the number of subshells can be calculated as 2l+1 . Here, l is an azimuthal quantum number. In each subshell maximum of two electrons (opposite spin) can be occupied. Thus, the maximum number of electrons in a subshell can be calculated using the following formula:

  X=22l+1=4l+2

Here, l is an azimuthal quantum number.

(d)

Expert Solution
Check Mark

Answer to Problem 38A

14

Explanation of Solution

The given orbital is 4f. For f orbital, the value of an azimuthal quantum number is 3. Thus, the maximum number of electrons present in it can be calculated as follows:

  X4f=4l+2=43+2=12+2=14

Therefore, the maximum number of electrons present in the 4f sublevel is 14.

(e)

Interpretation Introduction

Interpretation: The maximum number of electrons present in the 3p sublevels needs to be determined.

Concept Introduction: An atomic orbital explains the position of an electron in an atom. An atomic orbital can be occupied by a maximum of two electrons with opposite spins. The four basic atomic orbitals are s, p, d, and f . The number of electrons in each orbital can be explained with the help of quantum numbers. For any given shell, the number of subshells can be calculated as 2l+1 . Here, l is an azimuthal quantum number. In each subshell maximum of two electrons (opposite spin) can be occupied. Thus, the maximum number of electrons in a subshell can be calculated using the following formula:

  X=22l+1=4l+2

Here, l is an azimuthal quantum number.

(e)

Expert Solution
Check Mark

Answer to Problem 38A

6

Explanation of Solution

The given orbital is 3p. For p orbital, the value of an azimuthal quantum number is 1. Thus, the maximum number of electrons present in it can be calculated as follows:

  X3p=4l+2=41+2=6

Therefore, the maximum number of electrons present in the 3p sublevel is 6.

(f)

Interpretation Introduction

Interpretation: The maximum number of electrons present in the 3d sublevels needs to be determined.

Concept Introduction: An atomic orbital explains the position of an electron in an atom. An atomic orbital can be occupied by a maximum of two electrons with opposite spins. The four basic atomic orbitals are s, p, d, and f . The number of electrons in each orbital can be explained with the help of quantum numbers. For any given shell, the number of subshells can be calculated as 2l+1 . Here, l is an azimuthal quantum number. In each subshell maximum of two electrons (opposite spin) can be occupied. Thus, the maximum number of electrons in a subshell can be calculated using the following formula:

  X=22l+1=4l+2

Here, l is an azimuthal quantum number.

(f)

Expert Solution
Check Mark

Answer to Problem 38A

10

Explanation of Solution

The given orbital is 3d. For d orbital, the value of an azimuthal quantum number is 2. Thus, the maximum number of electrons present in it can be calculated as follows:

  X3d=4l+2=42+2=10

Therefore, the maximum number of electrons present in the 3d sublevel is 10.

(g)

Interpretation Introduction

Interpretation: The maximum number of electrons present in the 5s sublevels needs to be determined.

Concept Introduction: An atomic orbital explains the position of an electron in an atom. An atomic orbital can be occupied by a maximum of two electrons with opposite spins. The four basic atomic orbitals are s, p, d, and f . The number of electrons in each orbital can be explained with the help of quantum numbers. For any given shell, the number of subshells can be calculated as 2l+1 . Here, l is an azimuthal quantum number. In each subshell maximum of two electrons (opposite spin) can be occupied. Thus, the maximum number of electrons in a subshell can be calculated using the following formula:

  X=22l+1=4l+2

Here, l is an azimuthal quantum number.

(g)

Expert Solution
Check Mark

Answer to Problem 38A

2

Explanation of Solution

The given orbital is 5s. For s orbital, the value of an azimuthal quantum number is 0. Thus, the maximum number of electrons present in it can be calculated as follows:

  X5s=4l+2=40+2=2

Therefore, the maximum number of electrons present in the 5s sublevel is 2.

(h)

Interpretation Introduction

Interpretation: The maximum number of electrons present in the 5p sublevels needs to be determined.

Concept Introduction: An atomic orbital explains the position of an electron in an atom. An atomic orbital can be occupied by a maximum of two electrons with opposite spins. The four basic atomic orbitals are s, p, d, and f . The number of electrons in each orbital can be explained with the help of quantum numbers. For any given shell, the number of subshells can be calculated as 2l+1 . Here, l is an azimuthal quantum number. In each subshell maximum of two electrons (opposite spin) can be occupied. Thus, the maximum number of electrons in a subshell can be calculated using the following formula:

  X=22l+1=4l+2

Here, l is an azimuthal quantum number.

(h)

Expert Solution
Check Mark

Answer to Problem 38A

6

Explanation of Solution

The given orbital is 5p. For p orbital, the value of an azimuthal quantum number is 1. Thus, the maximum number of electrons present in it can be calculated as follows:

  X5p=4l+2=41+2=6

Therefore, the maximum number of electrons present in the 5p sublevel is 6.

Chapter 5 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 5.2 - Prob. 11LCCh. 5.2 - Prob. 12LCCh. 5.2 - Prob. 13LCCh. 5.2 - Prob. 14LCCh. 5.3 - Prob. 15SPCh. 5.3 - Prob. 16SPCh. 5.3 - Prob. 17SPCh. 5.3 - Prob. 18SPCh. 5.3 - Prob. 19LCCh. 5.3 - Prob. 20LCCh. 5.3 - Prob. 21LCCh. 5.3 - Prob. 22LCCh. 5.3 - Prob. 23LCCh. 5.3 - Prob. 24LCCh. 5.3 - Prob. 25LCCh. 5.3 - Prob. 26LCCh. 5 - Prob. 27ACh. 5 - Prob. 28ACh. 5 - Prob. 29ACh. 5 - Prob. 30ACh. 5 - Prob. 31ACh. 5 - Prob. 32ACh. 5 - Prob. 33ACh. 5 - Prob. 34ACh. 5 - Prob. 35ACh. 5 - Prob. 36ACh. 5 - Prob. 37ACh. 5 - Prob. 38ACh. 5 - Prob. 39ACh. 5 - Prob. 40ACh. 5 - Prob. 41ACh. 5 - Prob. 42ACh. 5 - Prob. 43ACh. 5 - Prob. 44ACh. 5 - Prob. 45ACh. 5 - Prob. 46ACh. 5 - Prob. 47ACh. 5 - Prob. 48ACh. 5 - Prob. 49ACh. 5 - Prob. 50ACh. 5 - Prob. 51ACh. 5 - Prob. 52ACh. 5 - Prob. 53ACh. 5 - Prob. 54ACh. 5 - Prob. 55ACh. 5 - Prob. 56ACh. 5 - Prob. 57ACh. 5 - Prob. 58ACh. 5 - Prob. 59ACh. 5 - Prob. 60ACh. 5 - Prob. 61ACh. 5 - Prob. 62ACh. 5 - Prob. 63ACh. 5 - Prob. 64ACh. 5 - Prob. 65ACh. 5 - Prob. 66ACh. 5 - Prob. 67ACh. 5 - Prob. 68ACh. 5 - Prob. 69ACh. 5 - Prob. 70ACh. 5 - Prob. 71ACh. 5 - Prob. 72ACh. 5 - Prob. 73ACh. 5 - Prob. 74ACh. 5 - Prob. 75ACh. 5 - Prob. 77ACh. 5 - Prob. 78ACh. 5 - Prob. 79ACh. 5 - Prob. 80ACh. 5 - Prob. 81ACh. 5 - Prob. 82ACh. 5 - Prob. 83ACh. 5 - Prob. 85ACh. 5 - Prob. 86ACh. 5 - Prob. 88ACh. 5 - Prob. 89ACh. 5 - Prob. 90ACh. 5 - Prob. 91ACh. 5 - Prob. 92ACh. 5 - Prob. 93ACh. 5 - Prob. 94ACh. 5 - Prob. 95ACh. 5 - Prob. 96ACh. 5 - Prob. 97ACh. 5 - Prob. 98ACh. 5 - Prob. 99ACh. 5 - Prob. 100ACh. 5 - Prob. 101ACh. 5 - Prob. 102ACh. 5 - Prob. 103ACh. 5 - Prob. 104ACh. 5 - Prob. 105ACh. 5 - Prob. 106ACh. 5 - Prob. 1STPCh. 5 - Prob. 2STPCh. 5 - Prob. 3STPCh. 5 - Prob. 4STPCh. 5 - Prob. 5STPCh. 5 - Prob. 6STPCh. 5 - Prob. 7STPCh. 5 - Prob. 8STPCh. 5 - Prob. 9STPCh. 5 - Prob. 10STPCh. 5 - Prob. 11STPCh. 5 - Prob. 12STPCh. 5 - Prob. 13STPCh. 5 - Prob. 14STPCh. 5 - Prob. 15STP
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