Chapter 5, Problem 94A

Interpretation Introduction

Interpretation:

The volume of the silver bar is to be determined.

Concept Introduction :

The relation between density and volume is as shown:

  $\text{volume}=\frac{\text{mass}}{\text{density}}$

Answer to Problem 94A

  $18.8{\text{cm}}^3$

Explanation of Solution

The mass of the silver bar is $368\text{g}$ and its density is $19.5{\text{g/cm}}^3.$

Substitute $368\text{g}$ for mass and $19.5{\text{g/cm}}^3$ for density in the above formula.

  $\begin{array}{c}\text{volume}=\frac{368\text{g}}{19.5{\text{g/cm}}^3}\\ =18.8{\text{cm}}^3\end{array}$

The volume of the silver bar is $18.8{\text{cm}}^3$