Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 5, Problem 56A
Interpretation Introduction

Interpretation: The symbol for the atoms that correspond to electron configuration is to be represented.

Concept Introduction: Electronic configurations refer to the arrangements of electrons in different orbitals around atoms' nuclei.

Expert Solution
Check Mark

Answer to Problem 56A

The symbol for the atoms that correspond to electron configuration is Ar .

The element is Argon.

Explanation of Solution

Electronic configurations refer to the arrangements of electrons in different orbitals around atoms' nuclei.

The Aufbau principle, the Pauli exclusion principle, and Hund's rule are three rules that can be used to determine the electronic configuration of atoms.

The energy levels and symbols for each sub-level occupied by an electron are written for an atom's electrical configuration.

Each sub-level is superscripted with the number of electrons occupied. The number of electrons in an atom is equal to the sum of the superscripts.

The order of orbital filling of the atoms is given as

  1s,2s,3p,3s,3p,4s,3d,4p,5s,4d,5p,6s,4f,5d,6p,7s,5f,6d,7p

Where, s orbitals accommodate 2 electrons, p orbitals 6 electrons, d orbitals 10 electrons, and f orbitals 14 electrons.

The given electronic configuration is 1s22s22p63s23p6 .

To find the symbol of the atom, add on the superscripts of the electronic configuration.

  1s22s22p63s23p6=2+2+6+2+6=18

The element with atomic number 18 is Argon. Its symbol is Ar .

Interpretation Introduction

Interpretation: The symbol for the atoms that correspond to electron configuration is to be represented.

Concept Introduction: Electronic configurations refer to the arrangements of electrons in different orbitals around atoms' nuclei.

Expert Solution
Check Mark

Answer to Problem 56A

The symbol for the atoms that correspond to electron configuration is Ru .

The element is Ruthenium.

Explanation of Solution

Electronic configurations refer to the arrangements of electrons in different orbitals around atoms' nuclei.

The Aufbau principle, the Pauli exclusion principle, and Hund's rule are three rules that can be used to determine the electronic configuration of atoms.

The energy levels and symbols for each sub-level occupied by an electron are written for an atom's electrical configuration.

Each sub-level is superscripted with the number of electrons occupied. The number of electrons in an atom is equal to the sum of the superscripts.

The order of orbital filling of the atoms is given as

  1s,2s,3p,3s,3p,4s,3d,4p,5s,4d,5p,6s,4f,5d,6p,7s,5f,6d,7p

Where, s orbitals accommodate 2 electrons, p orbitals 6 electrons, d orbitals 10 electrons, and f orbitals 14 electrons.

The given electronic configuration is 1s22s22p63s23p63d104s24p64d75s1 .

To find the symbol of the atom, add on the superscripts of the electronic configuration.

  1s22s22p63s23p63d104s24p64d75s1=2+2+6+2+6+10+2+6+7+1=44

The element with atomic number 44 is Ruthenium. Its symbol is Ru .

Interpretation Introduction

Interpretation: The symbol for the atoms that correspond to electron configuration is to be represented.

Concept Introduction: Electronic configurations refer to the arrangements of electrons in different orbitals around atoms' nuclei.

Expert Solution
Check Mark

Answer to Problem 56A

The symbol for the atoms that correspond to electron configuration is Gd .

The element is Gadolinium.

Explanation of Solution

Electronic configurations refer to the arrangements of electrons in different orbitals around atoms' nuclei.

The Aufbau principle, the Pauli exclusion principle, and Hund's rule are three rules that can be used to determine the electronic configuration of atoms.

The energy levels and symbols for each sub-level occupied by an electron are written for an atom's electrical configuration.

Each sub-level is superscripted with the number of electrons occupied. The number of electrons in an atom is equal to the sum of the superscripts.

The order of orbital filling of the atoms is given as

  1s,2s,3p,3s,3p,4s,3d,4p,5s,4d,5p,6s,4f,5d,6p,7s,5f,6d,7p

Where, s orbitals accommodate 2 electrons, p orbitals 6 electrons, d orbitals 10 electrons, and f orbitals 14 electrons.

The given electronic configuration is 1s22s22p63s23p63d104s24p64d104f75s25p65d16s2 .

To find the symbol of the atom, add on the superscripts of the electronic configuration.

  1s22s22p63s23p63d104s24p64d104f75s25p65d16s2=2+2+6+2+6+10+2+6+10+7+2+6+1+2=64

The element with atomic number 64 is Gadolinium. Its symbol is Gd .

Chapter 5 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 5.2 - Prob. 11LCCh. 5.2 - Prob. 12LCCh. 5.2 - Prob. 13LCCh. 5.2 - Prob. 14LCCh. 5.3 - Prob. 15SPCh. 5.3 - Prob. 16SPCh. 5.3 - Prob. 17SPCh. 5.3 - Prob. 18SPCh. 5.3 - Prob. 19LCCh. 5.3 - Prob. 20LCCh. 5.3 - Prob. 21LCCh. 5.3 - Prob. 22LCCh. 5.3 - Prob. 23LCCh. 5.3 - Prob. 24LCCh. 5.3 - Prob. 25LCCh. 5.3 - Prob. 26LCCh. 5 - Prob. 27ACh. 5 - Prob. 28ACh. 5 - Prob. 29ACh. 5 - Prob. 30ACh. 5 - Prob. 31ACh. 5 - Prob. 32ACh. 5 - Prob. 33ACh. 5 - Prob. 34ACh. 5 - Prob. 35ACh. 5 - Prob. 36ACh. 5 - Prob. 37ACh. 5 - Prob. 38ACh. 5 - Prob. 39ACh. 5 - Prob. 40ACh. 5 - Prob. 41ACh. 5 - Prob. 42ACh. 5 - Prob. 43ACh. 5 - Prob. 44ACh. 5 - Prob. 45ACh. 5 - Prob. 46ACh. 5 - Prob. 47ACh. 5 - Prob. 48ACh. 5 - Prob. 49ACh. 5 - Prob. 50ACh. 5 - Prob. 51ACh. 5 - Prob. 52ACh. 5 - Prob. 53ACh. 5 - Prob. 54ACh. 5 - Prob. 55ACh. 5 - Prob. 56ACh. 5 - Prob. 57ACh. 5 - Prob. 58ACh. 5 - Prob. 59ACh. 5 - Prob. 60ACh. 5 - Prob. 61ACh. 5 - Prob. 62ACh. 5 - Prob. 63ACh. 5 - Prob. 64ACh. 5 - Prob. 65ACh. 5 - Prob. 66ACh. 5 - Prob. 67ACh. 5 - Prob. 68ACh. 5 - Prob. 69ACh. 5 - Prob. 70ACh. 5 - Prob. 71ACh. 5 - Prob. 72ACh. 5 - Prob. 73ACh. 5 - Prob. 74ACh. 5 - Prob. 75ACh. 5 - Prob. 77ACh. 5 - Prob. 78ACh. 5 - Prob. 79ACh. 5 - Prob. 80ACh. 5 - Prob. 81ACh. 5 - Prob. 82ACh. 5 - Prob. 83ACh. 5 - Prob. 85ACh. 5 - Prob. 86ACh. 5 - Prob. 88ACh. 5 - Prob. 89ACh. 5 - Prob. 90ACh. 5 - Prob. 91ACh. 5 - Prob. 92ACh. 5 - Prob. 93ACh. 5 - Prob. 94ACh. 5 - Prob. 95ACh. 5 - Prob. 96ACh. 5 - Prob. 97ACh. 5 - Prob. 98ACh. 5 - Prob. 99ACh. 5 - Prob. 100ACh. 5 - Prob. 101ACh. 5 - Prob. 102ACh. 5 - Prob. 103ACh. 5 - Prob. 104ACh. 5 - Prob. 105ACh. 5 - Prob. 106ACh. 5 - Prob. 1STPCh. 5 - Prob. 2STPCh. 5 - Prob. 3STPCh. 5 - Prob. 4STPCh. 5 - Prob. 5STPCh. 5 - Prob. 6STPCh. 5 - Prob. 7STPCh. 5 - Prob. 8STPCh. 5 - Prob. 9STPCh. 5 - Prob. 10STPCh. 5 - Prob. 11STPCh. 5 - Prob. 12STPCh. 5 - Prob. 13STPCh. 5 - Prob. 14STPCh. 5 - Prob. 15STP
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