The compounds that will react with the Tollen’s solution has to be chosen from the given options. Concept Introduction: In organic chemistry , oxidation reaction is referred to the number C − O bonds increase and/or number of C − H bonds decrease. In organic chemistry, reduction reaction is referred to the number C − O bonds decrease and/or number of C − H bonds increase. Alcohols undergo oxidation reaction and reduction reaction. This depends upon the number of hydrogen atoms that is bonded to the alpha carbon atom. Primary and secondary alcohol undergoes oxidation reaction while tertiary alcohol does not undergo oxidation reaction. Primary alcohols undergo oxidation to give aldehyde and carboxylic acid as product. Secondary alcohol undergoes oxidation to give ketone as the product. Aldehyde undergoes oxidation to give carboxylic acid as the product while ketone does not undergo oxidation reaction. Tollen’s test: This is also known as silver mirror test. The reagent that is used in Tollen’s test is silver nitrate and ammonia in water. Aldehyde reacts with Tollen’s reagent, where the silver ion is reduced to silver metal and the aldehyde is oxidized to carboxylic acid. Ketone does not undergo Tollen’s test to deposit silver metal. Benedict’s test: This test is also similar to Tollen’s test. In this test, Cu 2+ metal ion is used as oxidizing agent. The Cu 2+ ion is reduced to Cu + ion while the aldehyde is oxidized to carboxylic acid. Cu 2 O is precipitated as brick-red solid. Ketone does not answer the Benedict’s test. This is because ketone are not oxidized.

Question

Lewis Structure, Hybridization & Molecular Geometry a) Draw the Lewis Structure of the molecules; Label the hybridization of each carbon atom; Predict the approximate molecular geometry around each carbon atom. CH3CHO CH3CN b) Draw the Lewis Structure of Nitromethane; Predict the approximate molecular geometry around the nitrogen atom. CH3NO2 c) Draw the Lewis Structure; Label the hybridization of the boron atom; Predict the approximate molecular geometry. BF3 BF4

Answer 1

Question

Chapter 4, Problem 4.81EP

Interpretation Introduction

Interpretation:

The compounds that will react with the Tollen’s solution has to be chosen from the given options.

Concept Introduction:

In organic chemistry, oxidation reaction is referred to the number C−O bonds increase and/or number of C−H bonds decrease.

In organic chemistry, reduction reaction is referred to the number C−O bonds decrease and/or number of C−H bonds increase.

Alcohols undergo oxidation reaction and reduction reaction. This depends upon the number of hydrogen atoms that is bonded to the alpha carbon atom. Primary and secondary alcohol undergoes oxidation reaction while tertiary alcohol does not undergo oxidation reaction. Primary alcohols undergo oxidation to give aldehyde and carboxylic acid as product. Secondary alcohol undergoes oxidation to give ketone as the product.

Aldehyde undergoes oxidation to give carboxylic acid as the product while ketone does not undergo oxidation reaction.

Tollen’s test:

This is also known as silver mirror test. The reagent that is used in Tollen’s test is silver nitrate and ammonia in water. Aldehyde reacts with Tollen’s reagent, where the silver ion is reduced to silver metal and the aldehyde is oxidized to carboxylic acid.

Ketone does not undergo Tollen’s test to deposit silver metal.

Benedict’s test:

This test is also similar to Tollen’s test. In this test, Cu2+ metal ion is used as oxidizing agent. The Cu2+ ion is reduced to Cu+ ion while the aldehyde is oxidized to carboxylic acid. Cu2O is precipitated as brick-red solid. Ketone does not answer the Benedict’s test. This is because ketone are not oxidized.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Students have asked these similar questions

Lewis Structure, Hybridization & Molecular Geometry a) Draw the Lewis Structure of the molecules; Label the hybridization of each carbon atom; Predict the approximate molecular geometry around each carbon atom. CH3CHO CH3CN b) Draw the Lewis Structure of Nitromethane; Predict the approximate molecular geometry around the nitrogen atom. CH3NO2 c) Draw the Lewis Structure; Label the hybridization of the boron atom; Predict the approximate molecular geometry. BF3 BF4

a. The structure of the bicarbonate (hydrogen carbonate) ion, HCO3-, HCO3 " is best described as a hybrid of several contributing resonance forms, two of which are shown here. HO :0: HO + :Ö: Bicarbonate is crucial for the control of body pH (for example, blood pH 7.4). A more self-indulgent use is in baking soda, where it serves as a source of CO2 CO2 gas, which gives bread and pastry their fluffy constituency. (i) Draw at least one additional resonance form. = (ii) Using curved "electron-pushing" arrows, show how these Lewis structures may be interconverted by movement of electron pairs. (iii) Determine which form or forms will be the major contributor(s) to the real structure of bicarbonate, explaining your answer on the basis of the criteria in Section 1-5.

Calibri 11 + BIL NAME: Jaylena M A student is investigating the ctect of volume on pressure during a lab activity. The student uses the following volumes (mL). 12, 13, 14, 16, 17, 18, 19, 20, 21, 22, 23, 24, 26, 28, 30, 33, 34, 35, 38, 40, 42, 44. 46, and 50. As the volume changed they measured the following pressures (atm) 11.0, 10.5, 10.0, 9.2. 8.5, 78, 75, 7.0, 6.8, 6.5, 6.0, 5.9, 5.5, 5.0, 4.8, 4.5, 4.2, 3.9, 3.8, 3.5, 3.3, 3.2, 3.0, 2.9. What is the independent variable? Volume Imla What is the dependent variable? Pressure Jatm Use the data and make a PROPER data table. Volume 1mL) Pressure latm 110