Chapter U1.23, Problem 4E

(a)

Interpretation Introduction

Interpretation:

Cation and anion of Copper (II) sulfate must be found out. Also, the correct chemical formula of the compound must be determined.

Concept introduction:

A compound is formed from atoms of different elements such that the overall charge on the compound is neutral.

Answer to Problem 4E

Cation is ${\text{Cu}}^{2+}$ (cupric) and the anion is ${\text{SO}}_4{}^{2-}$ (sulfate).

The formula of the compound is CuSO₄.

Explanation of Solution

As both copper has charge +2 and sulfate has charge − 2, so these will react 1:1 to produce copper sulfate ( ${\text{CuSO}}_{\text{4}}$ ).

(b)

Interpretation Introduction

Interpretation:

Cation and anion of Nickel (II) nitrate must be found out. Then correct chemical formula of the compound must be determined.

Concept introduction:

A compound is formed from atoms of different elements such that the overall charge on the compound is neutral.

Answer to Problem 4E

Cation is ${\text{Ni}}^{2+}$ (Nickel) and the anion is ${\text{NO}}_3{}^{-}$ (nitrate).

The formula of the compound is $\text{Ni }{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}$ .

Explanation of Solution

The nickel has charge +2 and nitrate has charge -1 so these will react in 1:2 ratio to produce nickel (II) nitrate $\text{Ni }{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}$ .

(c)

Interpretation Introduction

Interpretation:

Cation and anion of Iron (II) carbonate must be found out. Then correct chemical formula of the compound must be determined.

Concept introduction:

A compound is formed from atoms of different elements such that the overall charge on the compound is neutral.

Answer to Problem 4E

Cation is ${\text{Fe}}^{2+}$ (ferrous) and the anion is ${\text{CO}}_{\text{3}}{}^{2-}$ (carbonate).

The formula of the compound is ${\text{FeCO}}_{\text{3}}$ .

Explanation of Solution

As iron has charge +2 and carbonate has charge -2 so these will react in 1:1 ratio to produce ferrous (II) carbonate ${\text{FeCO}}_{\text{3}}$ .

(d)

Interpretation Introduction

Interpretation:

Cation and anion of cobalt (II) sulfate must be found out. Then correct chemical formula of the compound must be determined.

Concept introduction:

A compound is formed from atoms of different elements such that the overall charge on the compound is neutral.

Answer to Problem 4E

Cation is ${\text{Co}}^{2+}$ (cobalt) and the anion is ${\text{SO}}_4{}^{-2}$ (sulfate).

The formula of the compound is ${\text{CoSO}}_{\text{4}}$ .

Explanation of Solution

As cobalt has charge +2 and sulfate has charge -2 so these will react 1:1 to produce cobalt (II) sulfate

  ${\text{CoSO}}_{\text{4}}$ .

(e)

Interpretation Introduction

Interpretation:

Cation and anion of iron (III) carbonate must be found out. Then correct chemical formula of the compound must be determined.

Concept introduction:

A compound is formed from atoms of different elements such that the overall charge on the compound is neutral.

Answer to Problem 4E

Cation is ${\text{Fe}}^{3+}$ (ferric) and the anion is ${\text{CO}}_3{}^{-2}$ (carbonate).

The formula of the compound is ${\text{Fe}}_{\text{2}}{\left({\text{CO}}_{\text{3}}\right)}_{\text{3}}$ .

Explanation of Solution

As iron has charge +3 and carbonate has charge -2 so these will react 2:3 to produce iron (III) carbonate ${\text{Fe}}_{\text{2}}{\left({\text{CO}}_{\text{3}}\right)}_{\text{3}}$_.

(f)

Interpretation Introduction

Interpretation:

Cation and anion of chromium (VI) oxide must be found out. Then correct chemical formula of the compound must be determined.

Concept introduction:

A compound is formed from atoms of different elements such that the overall charge on the compound is neutral.

Answer to Problem 4E

Cation is ${\text{Cr}}^{6+}$ (chromium) and the anion is ${\text{O}}^{-2}$ (oxide).

The formula of the compound is ${\text{CrO}}_{\text{3}}$ .

Explanation of Solution

As chromium has +6 oxidation state and oxide has -2 oxidation state so these will react 1:3 to produce chromium (VI) oxide ${\text{CrO}}_{\text{3}}$_.