Chapter U1, Problem 2STP

Interpretation Introduction

Interpretation:

The volume of a pure gold crown needs to be calculated given that its density and mass are 19.3 g/cm³ and 1.2 kg respectively.

Concept introduction:

The density of a substance is the mass occupied by it per unit volume i.e.

$\text{Density(D) = }\frac{\text{Mass (m)}}{\text{Volume (V)}}\text{ -----(1)}$

Answer to Problem 2STP

(B) 62.2 cm³

Explanation of Solution

Given:

Mass of gold = 1.2 kg

Density of gold = 19.3 g/cm³

Calculation:

Based on equation (1):

$\begin{array}{l}\text{Volume (V) = }\frac{\text{Mass (m)}}{\text{Density(D)}}\\ =\frac{\raisebox{1ex}{$(1.2\text{ kg}\times \text{1000 g)}$}\!\left/ \!\raisebox{-1ex}{$1\text{ kg}$}\right.}{19.3{\text{ g/cm}}^3}=\text{62}{\text{.2 cm}}^{\text{3}}\end{array}$

Conclusion

The volume of a pure gold crown of density 19.3 g/cm³ and mass 1.2 kg is 62.2 cm³.