Chapter U1, Problem 14STP

Interpretation Introduction

Interpretation:

The radiations whose exposure can be protected with the help of sheet of aluminum needs to be identified.

Concept introduction:

A radioactive substance can be defined as the substance which can radiate certain radiations and form new daughter nuclei.

The radiations which emit during radioactive emission are called as radioactive radiations. Some common examples of radioactive radiations are alpha rays, beta rays and gamma rays.

Answer to Problem 14STP

option (B) is correct.

Explanation of Solution

Reason for correct option: Alpha, beta and gamma rays can differentiate on the basis of their ionization power and penetration power.

Gamma rays have high penetration power, therefore they can pass through paper, aluminum sheet and also lead brick. On the contrary, alpha and beta rays cannot pass through aluminum sheet. Alpha rays have, the less penetration power, therefore, it cannot even penetrate the paper sheet. Beta rays have medium penetration power, therefore, they can penetrate paper sheet, but not aluminum sheet.

Conclusion

Reasons for incorrect options: Due to less penetrating power, alpha and beta rays cannot penetrate an aluminum sheet.