Concept explainers
a)
Interpretation:
All the resonance forms that would stabilize the carbocation given are to be drawn.
Concept introduction:
Different resonance forms that stabilize a molecule differ only in the placement of their bonding or nonbonding electrons. Neither the position nor the hybridization of any atom changes from one resonance form to another.
To draw:
All the resonance forms that would stabilize the carbocation given.
b)
Interpretation:
All the resonance forms that would stabilize the carbocation given are to be drawn.
Concept introduction:
Different resonance forms that stabilize a molecule differ only in the placement of their bonding or nonbonding electrons. Neither the position nor the hybridization of any atom changes from one resonance form to another.
To draw:
All the resonance forms that would stabilize the carbocation given.
c)
Interpretation:
All the resonance forms that would stabilize the carbocation given are to be drawn.
Concept introduction:
Different resonance forms that stabilize a molecule differ only in the placement of their bonding or nonbonding electrons. Neither the position nor the hybridization of any atom changes from one resonance form to another.
To draw:
All the resonance forms that would stabilize the carbocation given.
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Chapter 7 Solutions
Organic Chemistry
- Zaitsev's rule is useful in selecting which carbon adjacent to a carbocation will form the double bond in the alkene product. True or Falsearrow_forwardWhich of the following concepts explains why a tertiary carbocation is more stable than a primary carbocation? a. Hyperconjugation b. Resonance c. Electronegativity T d. he octet rulearrow_forwardExplain well with important point and type The Answer.arrow_forward
- 5. For each of the following pairs, circle the most stable alkene and provide the name for each of them. X VS. 2.0 VS. VS.arrow_forward6. Use arrow pushing to draw the product of the resulting reaction. If no reaction occurs, then write in NR. OH Na₂Cr₂O7 H₂SO4, H₂Oarrow_forward"Nucleophilic substitution reaction"" When does the bond between the leaving group and C break? Does it break at the same time that the new bond between the nucleophile and C forms? Or Does the bond to the leaving group break first.arrow_forward
- CHCHS CH, CH CH CHCH, A D Which is the most stable alkene? Choose. Which is the least stable alkene? Choose.arrow_forwardDraw the two addition products formed when the alkene shown below reacts with HCl and circle the one which would be the major product according to Markovnikov’s rule.arrow_forwardWhat carbon radical is formed by homolysis of the C–Hb bond inpropylbenzene? Draw all reasonable resonance structures for thisradical.arrow_forward
- Which of the following statement is false about conjugated systems? A conjugated system is more stable than an unconjugated A system. The s-trans isomer is favored over the s-cis isomer. A conjugated system has C multiple resonance structures. A conjugated system can only D contain two alkenes.arrow_forwardQuestion 5 1). Draw all resonance structures for the carbocation intermediate formed by para attack; circle the resonance structure that is particularly unstable. N- N Cl₂ AICI 3 H 2). Draw all resonance structures for the carbocation intermediate formed by ortho attack; circle the extra resonance structure that is particularly stable. H a Aer ANSAS C HNO3 H₂SO4arrow_forwardUsing Zaitsev's rule, choose the most stable alkene among the following. Draw out the structures of each of the options then select the correct answer. Recall that Zaitsev's Rule is about alkene stability. The trend for this is similar to the trend for carbocation stability. Either more or fewer groups on the alkene (and the carbocation) make it more stable. This question is wanting you to remember if it's more or fewer. A) 1,2-dimethylcyclohexene B) 1,6-dimethylcyclohexene C) cis-3,4-dimethylcyclohexene D) They are all of equal stability according to Zaitsev's rule. Provide the major dehydration product of the following reaction. Recall which of the four substitution and elimination reactions a dehydration is. Before you do your S# or EF mechanism, remember what heteroatoms do in the presence of an acid (aka-the-OH is a bad leaving group, but protonating it might turn it into a good one). Don't forget to apply the concept from the previous question. OH Ht Aarrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning