Organic Chemistry
Organic Chemistry
9th Edition
ISBN: 9781305080485
Author: John E. McMurry
Publisher: Cengage Learning
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Chapter 7.5, Problem 12P
Interpretation Introduction

a) -CH3, -OH, -H, -Cl

Interpretation:

The substituents in the set, -CH3, -OH, -H, -Cl, are to be ranked according to the sequence rules.

Concept introduction:

The member that ranks higher can be determined by considering the atomic number of the first atom in each substituent. The atom with highest atomic number gets the higher rank. If a decision cannot be made by considering the atomic number of the first atom in each substituent then the second, third, fourth atoms can be considered until the first difference is found. Multiple bonded atoms are considered as equivalent to the same number of single bonded atoms.

To rank:

The substituents in the set, -CH3, -OH, -H, -Cl, according to the sequence rules.

Interpretation Introduction

b) -CH3, -CH2CH3, -CH=CH2, -CH2OH

Interpretation:

The substituents in the set, -CH3, -CH2CH3, -CH=CH2, -CH2OH, are to be ranked according to the sequence rules.

Concept introduction:

The member that ranks higher can be determined by considering the atomic number of the first atom in each substituent. The atom with highest atomic number gets the higher rank. If a decision cannot be made by considering the atomic number of the first atom in each substituent then the second, third, fourth atoms can be considered until the first difference is found. Multiple bonded atoms are considered as equivalent to the same number of single bonded atoms.

To rank:

The substituents in the set, -CH3, -CH2CH3, -CH=CH2, -CH2OH, according to the sequence rules.

Interpretation Introduction

Organic Chemistry, Chapter 7.5, Problem 12P , additional homework tip  1

Interpretation:

The substituents in the given set are to be ranked according to the sequence rules.

Concept introduction:

The member that ranks higher can be determined by considering the atomic number of the first atom in each substituent. The atom with highest atomic number gets the higher rank. If a decision cannot be made by considering the atomic number of the first atom in each substituent then the second, third, fourth atoms can be considered until the first difference is found. Multiple bonded atoms are considered as equivalent to the same number of single bonded atoms.

To rank:

The substituents in the given set according to the sequence rules.

Interpretation Introduction

Organic Chemistry, Chapter 7.5, Problem 12P , additional homework tip  2

Interpretation:

The substituents in the given set are to be ranked according to the sequence rules.

Concept introduction:

The member that ranks higher can be determined by considering the atomic number of the first atom in each substituent. The atom with highest atomic number gets the higher rank. If a decision cannot be made by considering the atomic number of the first atom in each substituent then the second, third, fourth atoms can be considered until the first difference is found. Multiple bonded atoms are considered as equivalent to the same number of single bonded atoms.

To rank:

The substituents in the given set according to the sequence rules.

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Chapter 7 Solutions

Organic Chemistry

Ch. 7.5 - Which member in each of the following sets ranks...Ch. 7.5 - Prob. 12PCh. 7.5 - Prob. 13PCh. 7.5 - Prob. 14PCh. 7.6 - Prob. 15PCh. 7.8 - Prob. 16PCh. 7.8 - Prob. 17PCh. 7.9 - Show the structures of the carbocation...Ch. 7.9 - Draw a skeletal structure of the following...Ch. 7.10 - Prob. 20PCh. 7.11 - On treatment with HBr, vinylcyclohexane undergoes...Ch. 7.SE - Prob. 22VCCh. 7.SE - Prob. 23VCCh. 7.SE - The following carbocation is an intermediate in...Ch. 7.SE - Prob. 25VCCh. 7.SE - Predict the major product and show the complete...Ch. 7.SE - Prob. 27MPCh. 7.SE - When 1, 3-butadiene reacts with one mole of HBr,...Ch. 7.SE - When methyl vinyl ether reacts with a strong acid,...Ch. 7.SE - Addition of HCl to 1-isopropylcyclohexene yields a...Ch. 7.SE - Addition of HCl to...Ch. 7.SE - Limonene, a fragrant hydrocarbon found in lemons...Ch. 7.SE - Prob. 33MPCh. 7.SE - Calculate the degree of unsaturation in the...Ch. 7.SE - Prob. 35APCh. 7.SE - Prob. 36APCh. 7.SE - Name the following alkenes:Ch. 7.SE - Draw structures corresponding to the following...Ch. 7.SE - Prob. 39APCh. 7.SE - Prob. 40APCh. 7.SE - Prob. 41APCh. 7.SE - Prob. 42APCh. 7.SE - Prob. 43APCh. 7.SE - Draw and name the 17 alkene isomers, C6H12,...Ch. 7.SE - Prob. 45APCh. 7.SE - Prob. 46APCh. 7.SE - Which of the following E, Z designations are...Ch. 7.SE - Prob. 48APCh. 7.SE - trans-2-Butene is more stable than cis-2-butene by...Ch. 7.SE - Prob. 50APCh. 7.SE - Normally, a trans alkene is more stable than its...Ch. 7.SE - trans-Cyclooctene is less stable than...Ch. 7.SE - Prob. 53APCh. 7.SE - Prob. 54APCh. 7.SE - Use Hammond’s Postulate to determine which...Ch. 7.SE - Prob. 56APCh. 7.SE - Predict the major product in each of the following...Ch. 7.SE - Prob. 58APCh. 7.SE - Prob. 59APCh. 7.SE - Prob. 60APCh. 7.SE - Allene (1,2-propadiene), H2C=C=CH2, has two...Ch. 7.SE - The heat of hydrogenation for allene (Problem...Ch. 7.SE - Retin A, or retinoic acid, is a medication...Ch. 7.SE - Prob. 64APCh. 7.SE - tert-Butyl esters [RC02C(CH3)3] are converted into...Ch. 7.SE - Vinylcyclopropane reacts with HBr to yield a...Ch. 7.SE - Prob. 67APCh. 7.SE - Prob. 68APCh. 7.SE - Prob. 69APCh. 7.SE - Prob. 70APCh. 7.SE - Prob. 71APCh. 7.SE - Reaction of 2, 3-dimethyl-l-butene with HBr leads...
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