The alkyl bromide shown is 1-bromo-1-ethyl-3-methylcyclohexane. The structures of three different alkenes that will yield this alkyl bromide on adding HBr are to be identified. Concept introduction: In electrophilic addition reactions, the first step is the attack of the π electrons of the double bond on the hydrogen of the hydrogen halide to yield a carbocation. One of the carbon in C = C gets attached to hydrogen while the other acquires a positive charge. In the second step, the carbocation produced reacts with a halide ion to give the alkyl halide . In the three alkenes therefore, the double bonds should be in a position to yield a carbocation on C 1 of the ring.

Question

Part 1. Draw monomer units of the following products and draw their reaction mechanism 1) Bakelite like polymer Using: Resorcinol + NaOH + Formalin 2) Polyester fiber Using a) pthalic anhydride + anhydrous sodium acetate + ethylene glycol B)pthalic anhydride + anhydrous sodium acetate + glycerol 3) Temporary cross-linked polymer Using: 4% polyvinyl alcohol+ methyl red + 4% sodium borate

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Chapter 7.SE, Problem 25VC

Interpretation Introduction

Interpretation:

The alkyl bromide shown is 1-bromo-1-ethyl-3-methylcyclohexane. The structures of three different alkenes that will yield this alkyl bromide on adding HBr are to be identified.

Concept introduction:

In electrophilic addition reactions, the first step is the attack of the π electrons of the double bond on the hydrogen of the hydrogen halide to yield a carbocation. One of the carbon in C = C gets attached to hydrogen while the other acquires a positive charge. In the second step, the carbocation produced reacts with a halide ion to give the alkyl halide. In the three alkenes therefore, the double bonds should be in a position to yield a carbocation on C₁ of the ring.

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