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Consider the two-dimensional rectangular plate of Problem 4.2 having a thermal conductivity of
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Fundamentals of Heat and Mass Transfer
- Do fast i will give you good ratearrow_forwardA 1-D conduction heat transfer problem with internal energy generation is governed by the following equation: +-= dx2 =0 W where è = 5E5 and k = 32 If you are given the following node diagram with a spacing of Ax = .02m and know that m-K T = 611K and T, = 600K, write the general equation for these internal nodes in finite difference form and determine the temperature at nodes 3 and 4. Insulated Ar , T For the answer window, enter the temperature at node 4 in Kelvin (K). Your Answer: EN SORN Answer units Pri qu) 232 PM 4/27/2022 99+ 66°F Sunny a . 20 ENLARGED oW TEXTURE PRT SCR IOS DEL F8 F10 F12 BACKSPACE num - %3D LOCK HOME PGUP 170arrow_forwardA hollow infinite cylinder has internal radius 0.5 and exterior radius 2.0. The external surface is maintained at 0°C and the internal surface at 100°C. Initially the cylinder has a uniform temperature of 15°C and it is required to compute the distribution of temperature across the radius as time progresses. Use an explicit method with a suitable time step to compute the temperature for r = 0.5(0.25)2.0 for the first few time steps.arrow_forward
- Hi, can you solve this problem for me please ? The lesson name is Heat Transfer. I did not solve. Thanks!arrow_forwardAfter a thorough derivation by Doraemon to establish an equation for cylindrical fuel rod of a nuclear reactor. Here he was able to come up an equation of heat generated internally as shown below. 9G = 9. where qG is the local rate of heat generation per unit volume at radius r, ro is the outside radius, and qo is the rate of heat generation per unit volume at the centre line. Calculate the temperature drop from the centre line to the surface for a 2.5 cm outer diameter rod having k = 25 W/m K, if the rate of heat removal from the surface is 1650 kW/m² А) 619°C В 719 °C C) 819 °C D) 919 °C E 1019 °C F None of thesearrow_forward4.) A 4m steel pipe (35 W m-°C external diameter of 30mm. A 10mm thick layer of insulation W m-°C coats this pipe and there is a temperature difference of 10C between the internal and external temperature. Solve for the rate of heat transfer has 20mm internal diameter and has anarrow_forward
- Solve using the methodology : Known, Find, Schematic Diagram, Assumptions, Properties, Analysis and Comments.arrow_forwardThe subject is Mechanics of Deformable Bodiesarrow_forwardA two dimensional rectangular plate is subjected to prescribed boundary conditions. Using the results of the analytical solution for the heat equation presented in class, calculate the temperature at the midpoint (1,0.5) by considering the first five nonzero terms of the infinite series that must be evaluated. T₁ = 50°C y (m) 1 T₂ = 150°C T₁ = 50°C ►x (m) 2 -T₁ = 50°Carrow_forward
- You are asked to estimate the maximum human body temperature if the metabolic heat produced in your body could escape only by tissue conduction and later on the surface by convection. Simplify the human body as a cylinder of L=1.8 m in height and ro= 0.15 m in radius. Further, simplify the heat transfer process inside the human body as a 1-D situation when the temperature only depends on the radial coordinater from the centerline. The governing dT +q""=0 dr equation is written as 1 d k- r dr r = 0, dT dr =0 dT r=ro -k -=h(T-T) dr (k-0.5 W/m°C), ro is the radius of the cylinder (0.15 m), h is the convection coefficient at the skin surface (15 W/m² °C), Tair is the air temperature (30°C). q" is the average volumetric heat generation rate in the body (W/m³) and is defined as heat generated per unit volume per second. The 1-D (radial) temperature distribution can be derived as: T(r) = q"¹'r² qr qr. + 4k 2h + 4k +T , where k is thermal conductivity of tissue air (A) q" can be calculated…arrow_forward2. The slab shown is embedded in insulating materials on five sides, while the front face experiences convection off its face. Heat is generated inside the material by an exothermic reaction equal to 1.0 kW/m'. The thermal conductivity of the slab is 0.2 W/mk. a. Simplify the heat conduction equation and integrate the resulting ID steady form of to find the temperature distribution of the slab, T(x). b. Present the temperature of the front and back faces of the slab. n-20- 10 cm IT- 25°C) 100 cm 100 cmarrow_forward! Illustratearrow_forward
- Principles of Heat Transfer (Activate Learning wi...Mechanical EngineeringISBN:9781305387102Author:Kreith, Frank; Manglik, Raj M.Publisher:Cengage Learning