General, Organic, and Biological Chemistry
General, Organic, and Biological Chemistry
7th Edition
ISBN: 9781285853918
Author: H. Stephen Stoker
Publisher: Cengage Learning
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 16, Problem 16.7EP

(a)

Interpretation Introduction

Interpretation:

The “CZ” bond in the general formula of carboxylic derivative is polar or nonpolar has to be indicated.

Concept Introduction:

Carbonyl groups are the one which contain a double bond between carbon and oxygen atom.  Aldehydes and ketones possess this carbonyl functional group in it.  The structural representation of a carbonyl group can be given as shown below,

General, Organic, and Biological Chemistry, Chapter 16, Problem 16.7EP , additional homework tip  1

If a hydroxyl group is attached to a carbonyl group means it is known as carboxyl group.  This can be represented as shown below,

General, Organic, and Biological Chemistry, Chapter 16, Problem 16.7EP , additional homework tip  2

Carboxylic acid derivatives are the ones that are synthesized from or converted to a carboxylic acid.  The generalized structural representation of carboxylic acid derivatives is shown below,

General, Organic, and Biological Chemistry, Chapter 16, Problem 16.7EP , additional homework tip  3

In the carboxylic acid derivatives, if the carbonyl carbon atom is bonded to a more electronegative atom means, then the bond will be polar and is it is bonded to carbon atom means then it will be nonpolar.

(a)

Expert Solution
Check Mark

Answer to Problem 16.7EP

The “CZ bond is polar.

General, Organic, and Biological Chemistry, Chapter 16, Problem 16.7EP , additional homework tip  4

Explanation of Solution

The general structure of carboxylic acid derivatives is,

General, Organic, and Biological Chemistry, Chapter 16, Problem 16.7EP , additional homework tip  5

The atom in entity Z that is bonded to the carbonyl carbon atom is not a carbon atom.  It is a nitrogen atom.  As there is a polarity difference between carbon and nitrogen atom, the bond between carbon and nitrogen will be polar.  This can be shown as given below,

General, Organic, and Biological Chemistry, Chapter 16, Problem 16.7EP , additional homework tip  6

Conclusion

The “CZ” bond is polar or not is indicated.

(b)

Interpretation Introduction

Interpretation:

The “CZ” bond in the general formula of carboxylic derivative is polar or nonpolar has to be indicated.

Concept Introduction:

Carbonyl groups are the one which contain a double bond between carbon and oxygen atom.  Aldehydes and ketones possess this carbonyl functional group in it.  The structural representation of a carbonyl group can be given as shown below,

General, Organic, and Biological Chemistry, Chapter 16, Problem 16.7EP , additional homework tip  7

If a hydroxyl group is attached to a carbonyl group means it is known as carboxyl group.  This can be represented as shown below,

General, Organic, and Biological Chemistry, Chapter 16, Problem 16.7EP , additional homework tip  8

Carboxylic acid derivatives are the ones that are synthesized from or converted to a carboxylic acid.  The generalized structural representation of carboxylic acid derivatives is shown below,

General, Organic, and Biological Chemistry, Chapter 16, Problem 16.7EP , additional homework tip  9

In the carboxylic acid derivatives, if the carbonyl carbon atom is bonded to a more electronegative atom means, then the bond will be polar and is it is bonded to carbon atom means then it will be nonpolar.

(b)

Expert Solution
Check Mark

Answer to Problem 16.7EP

The “CZ bond is nonpolar.

General, Organic, and Biological Chemistry, Chapter 16, Problem 16.7EP , additional homework tip  10

Explanation of Solution

The general structure of carboxylic acid derivatives is,

General, Organic, and Biological Chemistry, Chapter 16, Problem 16.7EP , additional homework tip  11

The atom in entity Z that is bonded to the carbonyl carbon atom is a carbon atom.  As there is no polarity difference between carbon and carbon atom, the bond between carbon and carbon will be nonpolar.  This can be shown as given below,

General, Organic, and Biological Chemistry, Chapter 16, Problem 16.7EP , additional homework tip  12

Conclusion

The “CZ” bond is polar or not is indicated.

(c)

Interpretation Introduction

Interpretation:

The “CZ” bond in the general formula of carboxylic derivative is polar or nonpolar has to be indicated.

Concept Introduction:

Carbonyl groups are the one which contain a double bond between carbon and oxygen atom.  Aldehydes and ketones possess this carbonyl functional group in it.  The structural representation of a carbonyl group can be given as shown below,

General, Organic, and Biological Chemistry, Chapter 16, Problem 16.7EP , additional homework tip  13

If a hydroxyl group is attached to a carbonyl group means it is known as carboxyl group.  This can be represented as shown below,

General, Organic, and Biological Chemistry, Chapter 16, Problem 16.7EP , additional homework tip  14

Carboxylic acid derivatives are the ones that are synthesized from or converted to a carboxylic acid.  The generalized structural representation of carboxylic acid derivatives is shown below,

General, Organic, and Biological Chemistry, Chapter 16, Problem 16.7EP , additional homework tip  15

In the carboxylic acid derivatives, if the carbonyl carbon atom is bonded to a more electronegative atom means, then the bond will be polar and is it is bonded to carbon atom means then it will be nonpolar.

(c)

Expert Solution
Check Mark

Answer to Problem 16.7EP

The “CZ bond is polar.

General, Organic, and Biological Chemistry, Chapter 16, Problem 16.7EP , additional homework tip  16

Explanation of Solution

The general structure of carboxylic acid derivatives is,

General, Organic, and Biological Chemistry, Chapter 16, Problem 16.7EP , additional homework tip  17

The atom in entity Z that is bonded to the carbonyl carbon atom is an oxygen atom.  As there is a polarity difference between carbon and oxygen atom, the bond between carbon and oxygen will be polar.  This can be shown as given below,

General, Organic, and Biological Chemistry, Chapter 16, Problem 16.7EP , additional homework tip  18

Conclusion

The “CZ” bond is polar or not is indicated.

(d)

Interpretation Introduction

Interpretation:

The “CZ” bond in the general formula of carboxylic derivative is polar or nonpolar has to be indicated.

Concept Introduction:

Carbonyl groups are the one which contain a double bond between carbon and oxygen atom.  Aldehydes and ketones possess this carbonyl functional group in it.  The structural representation of a carbonyl group can be given as shown below,

General, Organic, and Biological Chemistry, Chapter 16, Problem 16.7EP , additional homework tip  19

If a hydroxyl group is attached to a carbonyl group means it is known as carboxyl group.  This can be represented as shown below,

General, Organic, and Biological Chemistry, Chapter 16, Problem 16.7EP , additional homework tip  20

Carboxylic acid derivatives are the ones that are synthesized from or converted to a carboxylic acid.  The generalized structural representation of carboxylic acid derivatives is shown below,

General, Organic, and Biological Chemistry, Chapter 16, Problem 16.7EP , additional homework tip  21

In the carboxylic acid derivatives, if the carbonyl carbon atom is bonded to a more electronegative atom means, then the bond will be polar and is it is bonded to carbon atom means then it will be nonpolar.

(d)

Expert Solution
Check Mark

Answer to Problem 16.7EP

The “CZ bond is polar.

General, Organic, and Biological Chemistry, Chapter 16, Problem 16.7EP , additional homework tip  22

Explanation of Solution

The general structure of carboxylic acid derivatives is,

General, Organic, and Biological Chemistry, Chapter 16, Problem 16.7EP , additional homework tip  23

The atom in entity Z that is bonded to the carbonyl carbon atom is an oxygen atom.  As there is a polarity difference between carbon and oxygen atom, the bond between carbon and oxygen will be polar.  This can be shown as given below,

General, Organic, and Biological Chemistry, Chapter 16, Problem 16.7EP , additional homework tip  24

Conclusion

The “CZ” bond is polar or not is indicated.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Draw condensed structural formulas for the three ketones with the molecular formula C5H10O.
Give simple chemical tests to distinguish between the following pairs of compounds. isopropyl alcohol and tert-butyl alcohol methylamine and acetic acid
What structural characteristic is shared by the aldehydes and the ketones? A) They both are straight chain compounds. B) Aldehydes and ketones both contain a carbonyl carbon. C) Both of these compound classes have as the smallest compound a 5 carbon skeleton. D) Aldehydes and ketones have no shared characteristics.

Chapter 16 Solutions

General, Organic, and Biological Chemistry

Ch. 16.3 - Prob. 1QQCh. 16.3 - Prob. 2QQCh. 16.3 - Prob. 3QQCh. 16.4 - Prob. 1QQCh. 16.4 - Prob. 2QQCh. 16.4 - Prob. 3QQCh. 16.5 - Prob. 1QQCh. 16.5 - Prob. 2QQCh. 16.5 - Prob. 3QQCh. 16.6 - Prob. 1QQCh. 16.6 - Prob. 2QQCh. 16.7 - Prob. 1QQCh. 16.7 - Prob. 2QQCh. 16.7 - Prob. 3QQCh. 16.8 - Prob. 1QQCh. 16.8 - Prob. 2QQCh. 16.8 - Prob. 3QQCh. 16.8 - Prob. 4QQCh. 16.9 - Prob. 1QQCh. 16.9 - Prob. 2QQCh. 16.10 - Prob. 1QQCh. 16.10 - Prob. 2QQCh. 16.11 - Prob. 1QQCh. 16.11 - Prob. 2QQCh. 16.11 - Prob. 3QQCh. 16.12 - Prob. 1QQCh. 16.12 - Prob. 2QQCh. 16.12 - Prob. 3QQCh. 16.12 - Prob. 4QQCh. 16.13 - Prob. 1QQCh. 16.13 - Prob. 2QQCh. 16.14 - Prob. 1QQCh. 16.14 - Prob. 2QQCh. 16.14 - Prob. 3QQCh. 16.15 - Prob. 1QQCh. 16.15 - Prob. 2QQCh. 16.15 - Prob. 3QQCh. 16.16 - Prob. 1QQCh. 16.16 - Prob. 2QQCh. 16.16 - Prob. 3QQCh. 16.17 - Prob. 1QQCh. 16.17 - Prob. 2QQCh. 16.18 - Prob. 1QQCh. 16.18 - Prob. 2QQCh. 16.18 - Prob. 3QQCh. 16.19 - Prob. 1QQCh. 16.19 - Prob. 2QQCh. 16.19 - Prob. 3QQCh. 16.19 - Prob. 4QQCh. 16.20 - Prob. 1QQCh. 16.20 - Prob. 2QQCh. 16.20 - Prob. 3QQCh. 16.20 - Prob. 4QQCh. 16 - Prob. 16.1EPCh. 16 - Prob. 16.2EPCh. 16 - Prob. 16.3EPCh. 16 - Prob. 16.4EPCh. 16 - Prob. 16.5EPCh. 16 - Prob. 16.6EPCh. 16 - Prob. 16.7EPCh. 16 - Prob. 16.8EPCh. 16 - Prob. 16.9EPCh. 16 - Prob. 16.10EPCh. 16 - Prob. 16.11EPCh. 16 - Prob. 16.12EPCh. 16 - Prob. 16.13EPCh. 16 - Prob. 16.14EPCh. 16 - Prob. 16.15EPCh. 16 - Prob. 16.16EPCh. 16 - Prob. 16.17EPCh. 16 - Prob. 16.18EPCh. 16 - Prob. 16.19EPCh. 16 - Prob. 16.20EPCh. 16 - Prob. 16.21EPCh. 16 - Prob. 16.22EPCh. 16 - Prob. 16.23EPCh. 16 - Prob. 16.24EPCh. 16 - Prob. 16.25EPCh. 16 - Prob. 16.26EPCh. 16 - Prob. 16.27EPCh. 16 - Prob. 16.28EPCh. 16 - Prob. 16.29EPCh. 16 - Prob. 16.30EPCh. 16 - Prob. 16.31EPCh. 16 - Prob. 16.32EPCh. 16 - Prob. 16.33EPCh. 16 - Prob. 16.34EPCh. 16 - Prob. 16.35EPCh. 16 - Prob. 16.36EPCh. 16 - Prob. 16.37EPCh. 16 - Prob. 16.38EPCh. 16 - Prob. 16.39EPCh. 16 - Prob. 16.40EPCh. 16 - Determine the maximum number of hydrogen bonds...Ch. 16 - Prob. 16.42EPCh. 16 - Prob. 16.43EPCh. 16 - Prob. 16.44EPCh. 16 - Prob. 16.45EPCh. 16 - Prob. 16.46EPCh. 16 - Prob. 16.47EPCh. 16 - Prob. 16.48EPCh. 16 - Prob. 16.49EPCh. 16 - Prob. 16.50EPCh. 16 - Prob. 16.51EPCh. 16 - Prob. 16.52EPCh. 16 - Prob. 16.53EPCh. 16 - Prob. 16.54EPCh. 16 - Prob. 16.55EPCh. 16 - Prob. 16.56EPCh. 16 - Give the IUPAC name for each of the following...Ch. 16 - Give the IUPAC name for each of the following...Ch. 16 - Prob. 16.59EPCh. 16 - Give the common name for each of the carboxylic...Ch. 16 - Prob. 16.61EPCh. 16 - Write a chemical equation for the preparation of...Ch. 16 - Prob. 16.63EPCh. 16 - Prob. 16.64EPCh. 16 - Prob. 16.65EPCh. 16 - Prob. 16.66EPCh. 16 - Prob. 16.67EPCh. 16 - Prob. 16.68EPCh. 16 - Prob. 16.69EPCh. 16 - Prob. 16.70EPCh. 16 - Prob. 16.71EPCh. 16 - Prob. 16.72EPCh. 16 - Prob. 16.73EPCh. 16 - Prob. 16.74EPCh. 16 - Prob. 16.75EPCh. 16 - Prob. 16.76EPCh. 16 - Prob. 16.77EPCh. 16 - Prob. 16.78EPCh. 16 - Prob. 16.79EPCh. 16 - Prob. 16.80EPCh. 16 - Prob. 16.81EPCh. 16 - Prob. 16.82EPCh. 16 - Prob. 16.83EPCh. 16 - Prob. 16.84EPCh. 16 - Prob. 16.85EPCh. 16 - Prob. 16.86EPCh. 16 - Prob. 16.87EPCh. 16 - Prob. 16.88EPCh. 16 - Prob. 16.89EPCh. 16 - Prob. 16.90EPCh. 16 - Prob. 16.91EPCh. 16 - Prob. 16.92EPCh. 16 - Assign an IUPAC name to each of the following...Ch. 16 - Prob. 16.94EPCh. 16 - Prob. 16.95EPCh. 16 - Prob. 16.96EPCh. 16 - Prob. 16.97EPCh. 16 - Prob. 16.98EPCh. 16 - Prob. 16.99EPCh. 16 - Prob. 16.100EPCh. 16 - How many carbon atoms are present in a molecule of...Ch. 16 - Prob. 16.102EPCh. 16 - Prob. 16.103EPCh. 16 - Prob. 16.104EPCh. 16 - Prob. 16.105EPCh. 16 - Prob. 16.106EPCh. 16 - Prob. 16.107EPCh. 16 - Prob. 16.108EPCh. 16 - Prob. 16.109EPCh. 16 - Prob. 16.110EPCh. 16 - Prob. 16.111EPCh. 16 - Prob. 16.112EPCh. 16 - Prob. 16.113EPCh. 16 - Prob. 16.114EPCh. 16 - Prob. 16.115EPCh. 16 - Prob. 16.116EPCh. 16 - Prob. 16.117EPCh. 16 - Prob. 16.118EPCh. 16 - Prob. 16.119EPCh. 16 - Prob. 16.120EPCh. 16 - Prob. 16.121EPCh. 16 - Prob. 16.122EPCh. 16 - Prob. 16.123EPCh. 16 - Prob. 16.124EPCh. 16 - Prob. 16.125EPCh. 16 - Prob. 16.126EPCh. 16 - Prob. 16.127EPCh. 16 - Prob. 16.128EPCh. 16 - Prob. 16.129EPCh. 16 - Prob. 16.130EPCh. 16 - Prob. 16.131EPCh. 16 - Prob. 16.132EPCh. 16 - Prob. 16.133EPCh. 16 - Prob. 16.134EPCh. 16 - Prob. 16.135EPCh. 16 - Prob. 16.136EPCh. 16 - Prob. 16.137EPCh. 16 - Prob. 16.138EPCh. 16 - Prob. 16.139EPCh. 16 - Prob. 16.140EPCh. 16 - Prob. 16.141EPCh. 16 - Prob. 16.142EPCh. 16 - Prob. 16.143EPCh. 16 - Prob. 16.144EPCh. 16 - Prob. 16.145EPCh. 16 - Prob. 16.146EPCh. 16 - Prob. 16.147EPCh. 16 - Prob. 16.148EPCh. 16 - Draw a condensed structural formula for the...Ch. 16 - Prob. 16.150EPCh. 16 - Prob. 16.151EPCh. 16 - Prob. 16.152EPCh. 16 - Prob. 16.153EPCh. 16 - Prob. 16.154EPCh. 16 - Prob. 16.155EPCh. 16 - Prob. 16.156EPCh. 16 - Prob. 16.157EPCh. 16 - Prob. 16.158EPCh. 16 - Prob. 16.159EPCh. 16 - Prob. 16.160EPCh. 16 - Prob. 16.161EPCh. 16 - Prob. 16.162EPCh. 16 - Prob. 16.163EPCh. 16 - Prob. 16.164EP
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Text book image
Chemistry for Today: General, Organic, and Bioche...
Chemistry
ISBN:9781305960060
Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:Cengage Learning
Text book image
Chemistry: Matter and Change
Chemistry
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Glencoe/McGraw-Hill School Pub Co
Text book image
Introductory Chemistry For Today
Chemistry
ISBN:9781285644561
Author:Seager
Publisher:Cengage
Text book image
Organic And Biological Chemistry
Chemistry
ISBN:9781305081079
Author:STOKER, H. Stephen (howard Stephen)
Publisher:Cengage Learning,
Text book image
General, Organic, and Biological Chemistry
Chemistry
ISBN:9781285853918
Author:H. Stephen Stoker
Publisher:Cengage Learning
Text book image
Macroscale and Microscale Organic Experiments
Chemistry
ISBN:9781305577190
Author:Kenneth L. Williamson, Katherine M. Masters
Publisher:Brooks Cole
Lipids - Fatty Acids, Triglycerides, Phospholipids, Terpenes, Waxes, Eicosanoids; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=7dmoH5dAvpY;License: Standard YouTube License, CC-BY