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(a)
Interpretation:
The structural formula for
Concept Introduction:
In
In organic chemistry, reduction reaction is referred to the number
Alcohols undergo
Aldehyde undergoes oxidation to give carboxylic acid as the product while ketone does not undergo oxidation reaction.
(a)
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Answer to Problem 16.45EP
The structural formula of the expected product is,
Explanation of Solution
Primary alcohol on oxidation gives aldehyde as intermediate product. This on further oxidation gives carboxylic acid as the product. The general scheme can be represented as shown below,
Given substance is,
This is a primary alcohol. The given compound is ethanol. Ethanol on oxidation gives ethanal as the intermediate product. The formed ethanal on oxidation gives ethanoic acid as the product. The complete scheme can be represented as shown below,
The carboxylic acid that is formed on oxidation of the given substance is ethanoic acid. The structural formula of ethanoic acid is given below,
Structural formula of the carboxylic acid formed by the oxidation of given substance is drawn.
(b)
Interpretation:
The structural formula for carboxylic acid that is expected to be formed on oxidation of the given substance has to be drawn.
Concept Introduction:
In organic chemistry, oxidation reaction is referred to the number
In organic chemistry, reduction reaction is referred to the number
Alcohols undergo oxidation reaction and reduction reaction. This depends upon the number of hydrogen atoms that is bonded to the alpha carbon atom. Primary and secondary alcohol undergoes oxidation reaction while tertiary alcohol does not undergo oxidation reaction. Primary alcohols undergo oxidation to give aldehyde and carboxylic acid as product. Secondary alcohol undergoes oxidation to give ketone as the product.
Aldehyde undergoes oxidation to give carboxylic acid as the product while ketone does not undergo oxidation reaction.
Aromatic carboxylic acids are prepared from alkyl substituted benzenes.
(b)
![Check Mark](/static/check-mark.png)
Answer to Problem 16.45EP
The structural formula of the expected product is,
Explanation of Solution
Aldehyde on oxidation gives carboxylic acid as the product. The general scheme can be represented as shown below,
Given substance is,
The given compound is ethanal and it is an aldehyde. Ethanal on oxidation gives ethanoic acid as the product. The complete scheme can be represented as shown below,
The carboxylic acid that is formed on oxidation of the given substance is ethanoic acid. The structural formula of ethanoic acid is given below,
Structural formula of the carboxylic acid formed by the oxidation of given substance is drawn.
(c)
Interpretation:
The structural formula for carboxylic acid that is expected to be formed on oxidation of the given substance has to be drawn.
Concept Introduction:
In organic chemistry, oxidation reaction is referred to the number
In organic chemistry, reduction reaction is referred to the number
Alcohols undergo oxidation reaction and reduction reaction. This depends upon the number of hydrogen atoms that is bonded to the alpha carbon atom. Primary and secondary alcohol undergoes oxidation reaction while tertiary alcohol does not undergo oxidation reaction. Primary alcohols undergo oxidation to give aldehyde and carboxylic acid as product. Secondary alcohol undergoes oxidation to give ketone as the product.
Aldehyde undergoes oxidation to give carboxylic acid as the product while ketone does not undergo oxidation reaction.
Aromatic carboxylic acids are prepared from alkyl substituted benzenes.
(c)
![Check Mark](/static/check-mark.png)
Answer to Problem 16.45EP
The structural formula of the expected product is,
Explanation of Solution
Aldehyde on oxidation gives carboxylic acid as the product. The general scheme can be represented as shown below,
Given substance is,
The given compound is 3-methylpentanal and it is an aldehyde. 3-methylpentanal on oxidation gives 3-methylpentanoic acid as the product. The complete scheme can be represented as shown below,
The carboxylic acid that is formed on oxidation of the given substance is 3-methylpentanoic acid. The structural formula of 3-methylpentanoic acid is given below,
Structural formula of the carboxylic acid formed by the oxidation of given substance is drawn.
(d)
Interpretation:
The structural formula for carboxylic acid that is expected to be formed on oxidation of the given substance has to be drawn.
Concept Introduction:
In organic chemistry, oxidation reaction is referred to the number
In organic chemistry, reduction reaction is referred to the number
Alcohols undergo oxidation reaction and reduction reaction. This depends upon the number of hydrogen atoms that is bonded to the alpha carbon atom. Primary and secondary alcohol undergoes oxidation reaction while tertiary alcohol does not undergo oxidation reaction. Primary alcohols undergo oxidation to give aldehyde and carboxylic acid as product. Secondary alcohol undergoes oxidation to give ketone as the product.
Aldehyde undergoes oxidation to give carboxylic acid as the product while ketone does not undergo oxidation reaction.
Aromatic carboxylic acids are prepared from alkyl substituted benzenes.
(d)
![Check Mark](/static/check-mark.png)
Answer to Problem 16.45EP
The structural formula of the expected product is,
Explanation of Solution
Given substance is,
Oxidation of the alkyl side chain in a benzene derivative leads to the formation of aromatic acids. All the carbon atoms in alkyl group are lost except the one that is attached to the ring. The one carbon that is attached to the ring becomes a part of carboxyl
The product formed is benzoic acid.
Structural formula of the carboxylic acid formed by the oxidation of given substance is drawn.
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Chapter 16 Solutions
General, Organic, and Biological Chemistry
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- Part I. a) Elucidate the structure of compound A using the following information. • mass spectrum: m+ = 102, m/2=57 312=29 • IR spectrum: 1002.5 % TRANSMITTANCE Ngg 50 40 30 20 90 80 70 60 MICRONS 5 8 9 10 12 13 14 15 16 19 1740 cm M 10 0 4000 3600 3200 2800 2400 2000 1800 1600 13 • CNMR 'H -NMR Peak 8 ppm (H) Integration multiplicity a 1.5 (3H) triplet b 1.3 1.5 (3H) triplet C 2.3 1 (2H) quartet d 4.1 1 (2H) quartet & ppm (c) 10 15 28 60 177 (C=0) b) Elucidate the structure of compound B using the following information 13C/DEPT NMR 150.9 MHz IIL 1400 WAVENUMBERS (CM-1) DEPT-90 DEPT-135 85 80 75 70 65 60 55 50 45 40 35 30 25 20 ppm 1200 1000 800 600 400arrow_forward• Part II. a) Elucidate The structure of compound c w/ molecular formula C10 11202 and the following data below: • IR spectra % TRANSMITTANCE 1002.5 90 80 70 60 50 40 30 20 10 0 4000 3600 3200 2800 2400 2000 1800 1600 • Information from 'HAMR MICRONS 8 9 10 11 14 15 16 19 25 1400 WAVENUMBERS (CM-1) 1200 1000 800 600 400 peak 8 ppm Integration multiplicity a 2.1 1.5 (3H) Singlet b 3.6 1 (2H) singlet с 3.8 1.5 (3H) Singlet d 6.8 1(2H) doublet 7.1 1(2H) doublet Information from 13C-nmR Normal carbon 29ppm Dept 135 Dept -90 + NO peak NO peak 50 ppm 55 ppm + NO peak 114 ppm t 126 ppm No peak NO peak 130 ppm t + 159 ppm No peak NO peak 207 ppm по реак NO peakarrow_forwardCould you redraw these and also explain how to solve them for me pleasarrow_forward
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