Living By Chemistry: First Edition Textbook
Living By Chemistry: First Edition Textbook
1st Edition
ISBN: 9781559539418
Author: Angelica Stacy
Publisher: MAC HIGHER
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Chapter U4.18, Problem 4E

(a)

Interpretation Introduction

Interpretation: Thehydroiodic acid HI needs to be classified as an acid or a base. Also, the ions formed in its solution needs to be represented.

Concept Introduction:

On the basis of taste, reactivity and presence of ions; substances can be classified as acidic and basic. An acidic substance can be defined as the substance that can give H+ ions in the solution. A basic substance can give OH- ions in its solution.

(a)

Expert Solution
Check Mark

Answer to Problem 4E

  HI(aq)  + H2O(l)H3O+(aq)+I-(aq)

Hydroiodic acid = HI = Acid

Explanation of Solution

Acidic and basic substance can also be classified on the basis of taste. Acidic substances are sour in taste whereas basic substances are bitter in taste.

In hydroiodic acid HI, there is one H atom and it can give H+ ions in its solution therefore it must be an acid. The acid dissociation for hydroiodic acid can be shown as:

  HI(aq)  + H2O(l)H3O+(aq)+I-(aq)

(b)

Interpretation Introduction

Interpretation: Theformic acid HCOOH needs to be classified as an acid or a base. Also, the ions formed in its solution needs to be represented.

Concept Introduction:

On the basis of taste, reactivity and presence of ions; substances can be classified as acidic and basic. An acidic substance can be defined as the substance that can give H+ ions in the solution. A basic substance can give OH- ions in its solution.

(b)

Expert Solution
Check Mark

Answer to Problem 4E

  HCOOH(aq)  + H2O(l)H3O+(aq)+ HCOO-(aq)

Formic acid = HCOOH = Acid

Explanation of Solution

Acidic and basic substance can also be classified on the basis of taste. Acidic substances are sour in taste whereas basic substances are bitter in taste.

In formic acid HCOOH, there is one ionizable H atom and it can give H+ ions in its solution therefore it must be an acid. The acid dissociation for formic acid can be shown as:

  HCOOH(aq)  + H2O(l)H3O+(aq)+ HCOO-(aq)

(c)

Interpretation Introduction

Interpretation: Therubidium hydroxide RbOH needs to be classified as an acid or a base. Also, the ions formed in its solution needs to be represented.

Concept Introduction:

On the basis of taste, reactivity and presence of ions; substances can be classified as acidic and basic. An acidic substance can be defined as the substance that can give H+ ions in the solution. A basic substance can give OH- ions in its solution.

(c)

Expert Solution
Check Mark

Answer to Problem 4E

  RbOH(aq) H2O(l)Rb+(aq)+ OH-(aq)

Rubidium hydroxide RbOH= base

Explanation of Solution

Acidic and basic substance can also be classified on the basis of taste. Acidic substances are sour in taste whereas basic substances are bitter in taste.

In Rubidium hydroxide RbOH, there is one OH group and it can give OH- ions in its solution therefore it must be a base. The base dissociation forRbOHcan be shown as:

  RbOH(aq) H2O(l)Rb+(aq)+ OH-(aq)

(d)

Interpretation Introduction

Interpretation: Thehypochlorus acid HOCl needs to be classified as an acid or a base. Also, the ions formed in its solution needs to be represented.

Concept Introduction:

On the basis of taste, reactivity and presence of ions; substances can be classified as acidic and basic. An acidic substance can be defined as the substance that can give H+ ions in the solution. A basic substance can give OH- ions in its solution.

(d)

Expert Solution
Check Mark

Answer to Problem 4E

  HOCl(aq)  + H2O(l)H3O+(aq)+ ClO-(aq)

Hypochlorus acid HOCl= Acid

Explanation of Solution

Acidic and basic substance can also be classified on the basis of taste. Acidic substances are sour in taste whereas basic substances are bitter in taste.

In Hypochlorus acid HOCl, there is one H atom and it can give H+ ions in its solution therefore it must be an acid. The acid dissociation for hypochlorus acid HOClcan be shown as:

  HOCl(aq)  + H2O(l)H3O+(aq)+ ClO-(aq)

(e)

Interpretation Introduction

Interpretation: Theselenous acid H2SeO4 needs to be classified as an acid or a base. Also, the ions formed in its solution needs to be represented.

Concept Introduction:

On the basis of taste, reactivity and presence of ions; substances can be classified as acidic and basic. An acidic substance can be defined as the substance that can give H+ ions in the solution. A basic substance can give OH- ions in its solution.

(e)

Expert Solution
Check Mark

Answer to Problem 4E

  H2SeO4(aq)  + 2 H2O(l)2 H3O+(aq)+  SeO42-(aq)

Selenous acid H2SeO4 = Acid

Explanation of Solution

Acidic and basic substance can also be classified on the basis of taste. Acidic substances are sour in taste whereas basic substances are bitter in taste.

In Selenousacid H2SeO4 , there are two ionizable H atoms and it can give H+ ions in its solution therefore it must be an acid. The acid dissociation for selenous acid H2SeO4 can be shown as:

  H2SeO4(aq)  + 2 H2O(l)2 H3O+(aq)+  SeO42-(aq)

(f)

Interpretation Introduction

Interpretation: Thephosphine PH3 needs to be classified as an acid or a base. Also, the ions formed in its solution needs to be represented.

Concept Introduction:

On the basis of taste, reactivity and presence of ions; substances can be classified as acidic and basic. An acidic substance can be defined as the substance that can give H+ ions in the solution. A basic substance can give OH- ions in its solution.

(f)

Expert Solution
Check Mark

Answer to Problem 4E

  PH3(aq)  +  H2O(l) PH4+(aq)+  OH-(aq)

  PH3 = base

Explanation of Solution

Acidic and basic substance can also be classified on the basis of taste. Acidic substances are sour in taste whereas basic substances are bitter in taste.

Phosphine PH3 gives OH- ions in its aqueous solution by accepting hydrogen from water so it must be basic in nature.

  PH3(aq)  +  H2O(l) PH4+(aq)+  OH-(aq)

(g)

Interpretation Introduction

Interpretation: Theperchloric acid HClO4 needs to be classified as an acid or a base. Also, the ions formed in its solution needs to be represented.

Concept Introduction:

On the basis of taste, reactivity and presence of ions; substances can be classified as acidic and basic. An acidic substance can be defined as the substance that can give H+ ions in the solution. A basic substance can give OH- ions in its solution.

(g)

Expert Solution
Check Mark

Answer to Problem 4E

  HClO4(aq)  +  H2O(l) H3O+(aq)+  ClO4-(aq)

Perchloric acid HClO4 = Acid

Explanation of Solution

Acidic and basic substance can also be classified on the basis of taste. Acidic substances are sour in taste whereas basic substances are bitter in taste.

Perchloric acid HClO4 there is one H atom and it can give H+ ions in its solution therefore it must be an acid. The acid dissociation for perchloric acid can be shown as:

  HClO4(aq)  +  H2O(l) H3O+(aq)+  ClO4-(aq)

(h)

Interpretation Introduction

Interpretation: Thecalcium hydroxide Ca(OH)2 needs to be classified as an acid or a base. Also, the ions formed in its solution needs to be represented.

Concept Introduction:

On the basis of taste, reactivity and presence of ions; substances can be classified as acidic and basic. An acidic substance can be defined as the substance that can give H+ ions in the solution. A basic substance can give OH- ions in its solution.

(h)

Expert Solution
Check Mark

Answer to Problem 4E

  Ca(OH)2(aq) H2O(l)Ca2+(aq)+  2 OH-(aq)

Calcium hydroxide Ca(OH)2 = Base

Explanation of Solution

Acidic and basic substance can also be classified on the basis of taste. Acidic substances are sour in taste whereas basic substances are bitter in taste.

In calcium hydroxide Ca(OH)2 , there are two OH groups and it can give OH- ions in its solution therefore it must be a base. The base dissociation for OH- can be shown as:

  Ca(OH)2(aq) H2O(l)Ca2+(aq)+  2 OH-(aq)

Chapter U4 Solutions

Living By Chemistry: First Edition Textbook

Ch. U4.2 - Prob. 3ECh. U4.2 - Prob. 4ECh. U4.2 - Prob. 5ECh. U4.3 - Prob. 1TAICh. U4.3 - Prob. 1ECh. U4.3 - Prob. 2ECh. U4.3 - Prob. 3ECh. U4.3 - Prob. 4ECh. U4.3 - Prob. 6ECh. U4.4 - Prob. 1TAICh. U4.4 - Prob. 1ECh. U4.4 - Prob. 2ECh. U4.4 - Prob. 3ECh. U4.4 - Prob. 4ECh. U4.4 - Prob. 5ECh. U4.4 - Prob. 6ECh. U4.4 - Prob. 7ECh. U4.5 - Prob. 1TAICh. U4.5 - Prob. 1ECh. U4.5 - Prob. 2ECh. U4.5 - Prob. 3ECh. U4.5 - Prob. 4ECh. U4.6 - Prob. 1TAICh. U4.6 - Prob. 1ECh. U4.6 - Prob. 2ECh. U4.6 - Prob. 3ECh. U4.6 - Prob. 5ECh. U4.6 - Prob. 6ECh. U4.6 - Prob. 7ECh. U4.7 - Prob. 1TAICh. U4.7 - Prob. 1ECh. U4.7 - Prob. 2ECh. U4.7 - Prob. 4ECh. U4.7 - Prob. 5ECh. U4.8 - Prob. 1TAICh. U4.8 - Prob. 1ECh. U4.8 - Prob. 2ECh. U4.8 - Prob. 4ECh. U4.8 - Prob. 5ECh. U4.8 - Prob. 6ECh. U4.8 - Prob. 7ECh. U4.8 - Prob. 8ECh. U4.8 - Prob. 9ECh. U4.8 - Prob. 10ECh. U4.8 - Prob. 11ECh. U4.9 - Prob. 1TAICh. U4.9 - Prob. 1ECh. U4.9 - Prob. 2ECh. U4.9 - Prob. 3ECh. U4.9 - Prob. 4ECh. U4.9 - Prob. 5ECh. U4.9 - Prob. 6ECh. U4.9 - Prob. 7ECh. U4.9 - Prob. 8ECh. U4.10 - Prob. 1TAICh. U4.10 - Prob. 1ECh. U4.10 - Prob. 2ECh. U4.10 - Prob. 3ECh. U4.10 - Prob. 4ECh. U4.10 - Prob. 5ECh. U4.10 - Prob. 6ECh. U4.10 - Prob. 7ECh. U4.10 - Prob. 8ECh. U4.11 - Prob. 1TAICh. U4.11 - Prob. 1ECh. U4.11 - Prob. 2ECh. U4.11 - Prob. 3ECh. U4.11 - Prob. 4ECh. U4.11 - Prob. 5ECh. U4.11 - Prob. 6ECh. U4.11 - Prob. 7ECh. U4.11 - Prob. 8ECh. U4.12 - Prob. 1TAICh. U4.12 - Prob. 1ECh. U4.12 - Prob. 2ECh. U4.12 - Prob. 3ECh. U4.12 - Prob. 4ECh. U4.13 - Prob. 1TAICh. U4.13 - Prob. 1ECh. U4.13 - Prob. 2ECh. U4.13 - Prob. 3ECh. U4.13 - Prob. 4ECh. U4.13 - Prob. 5ECh. U4.13 - Prob. 6ECh. U4.13 - Prob. 7ECh. U4.13 - Prob. 8ECh. U4.13 - Prob. 9ECh. U4.13 - Prob. 10ECh. U4.14 - Prob. 1TAICh. U4.14 - Prob. 1ECh. U4.14 - Prob. 2ECh. U4.14 - Prob. 3ECh. U4.14 - Prob. 4ECh. U4.14 - Prob. 5ECh. U4.14 - Prob. 6ECh. U4.14 - Prob. 7ECh. U4.14 - Prob. 8ECh. U4.14 - Prob. 9ECh. U4.15 - Prob. 1TAICh. U4.15 - Prob. 1ECh. U4.15 - Prob. 2ECh. U4.15 - Prob. 3ECh. U4.15 - Prob. 4ECh. U4.15 - Prob. 5ECh. U4.15 - Prob. 6ECh. U4.15 - Prob. 7ECh. U4.15 - Prob. 8ECh. U4.16 - Prob. 1TAICh. U4.16 - Prob. 1ECh. U4.16 - Prob. 2ECh. U4.16 - Prob. 3ECh. U4.16 - Prob. 4ECh. U4.16 - Prob. 5ECh. U4.16 - Prob. 6ECh. U4.16 - Prob. 7ECh. U4.17 - Prob. 1TAICh. U4.17 - Prob. 1ECh. U4.17 - Prob. 2ECh. U4.17 - Prob. 3ECh. U4.17 - Prob. 5ECh. U4.17 - Prob. 6ECh. U4.17 - Prob. 7ECh. U4.18 - Prob. 1TAICh. U4.18 - Prob. 1ECh. U4.18 - Prob. 2ECh. U4.18 - Prob. 3ECh. U4.18 - Prob. 4ECh. U4.18 - Prob. 5ECh. U4.18 - Prob. 6ECh. U4.18 - Prob. 7ECh. U4.18 - Prob. 8ECh. U4.19 - Prob. 1TAICh. U4.19 - Prob. 1ECh. U4.19 - Prob. 2ECh. U4.19 - Prob. 3ECh. U4.19 - Prob. 4ECh. U4.19 - Prob. 6ECh. U4.19 - Prob. 7ECh. U4.19 - Prob. 8ECh. U4.20 - Prob. 1TAICh. U4.20 - Prob. 1ECh. U4.20 - Prob. 2ECh. U4.20 - Prob. 3ECh. U4.20 - Prob. 4ECh. U4.20 - Prob. 5ECh. U4.20 - Prob. 6ECh. U4.20 - Prob. 7ECh. U4.20 - Prob. 8ECh. U4.21 - Prob. 1TAICh. U4.21 - Prob. 1ECh. U4.21 - Prob. 2ECh. U4.21 - Prob. 4ECh. U4.21 - Prob. 5ECh. U4.21 - Prob. 6ECh. U4.21 - Prob. 7ECh. U4.21 - Prob. 8ECh. U4.22 - Prob. 1TAICh. U4.22 - Prob. 1ECh. U4.22 - Prob. 2ECh. U4.22 - Prob. 3ECh. U4.22 - Prob. 4ECh. U4.22 - Prob. 5ECh. U4.22 - Prob. 6ECh. U4.23 - Prob. 1ECh. U4.23 - Prob. 2ECh. U4.23 - Prob. 3ECh. U4.23 - Prob. 4ECh. U4.23 - Prob. 5ECh. U4.23 - Prob. 6ECh. U4.23 - Prob. 7ECh. U4.24 - Prob. 1ECh. U4.24 - Prob. 2ECh. U4.24 - Prob. 3ECh. U4.24 - Prob. 5ECh. U4.24 - Prob. 6ECh. U4.25 - Prob. 1TAICh. U4.25 - Prob. 1ECh. U4.25 - Prob. 2ECh. U4.25 - Prob. 3ECh. U4.25 - Prob. 4ECh. U4.26 - Prob. 1TAICh. U4.26 - Prob. 1ECh. U4.26 - Prob. 2ECh. U4.26 - Prob. 4ECh. U4.26 - Prob. 5ECh. U4.26 - Prob. 6ECh. U4 - Prob. SI3RECh. U4 - Prob. SI4RECh. U4 - Prob. SII1RECh. U4 - Prob. SII2RECh. U4 - Prob. SII3RECh. U4 - Prob. SII5RECh. U4 - Prob. SII6RECh. U4 - Prob. SIII1RECh. U4 - Prob. SIII2RECh. U4 - Prob. SIII3RECh. U4 - Prob. SIII4RECh. U4 - Prob. SIII5RECh. U4 - Prob. SIII6RECh. U4 - Prob. SIII7RECh. U4 - Prob. SIII8RECh. U4 - Prob. SIV1RECh. U4 - Prob. SIV2RECh. U4 - Prob. SIV3RECh. U4 - Prob. SIV4RECh. U4 - Prob. SV1RECh. U4 - Prob. SV2RECh. U4 - Prob. SV3RECh. U4 - Prob. 1RECh. U4 - Prob. 4RECh. U4 - Prob. 5RECh. U4 - Prob. 6RECh. U4 - Prob. 7RECh. U4 - Prob. 8RECh. U4 - Prob. 9RECh. U4 - Prob. 10RECh. U4 - Prob. 11RECh. U4 - Prob. 12RE

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