Chapter U4.14, Problem 9E

(a)

Interpretation Introduction

Interpretation:

The volume of 12.0 M HCl required to get 3.0 mol HCl needs to be calculated.

Concept Introduction :

12.0 M solution means there are 12.0 moles of solute in 1L of the solution.

Answer to Problem 9E

0.25 L of HCl solution is required to get 3.0 moles of HCl.

Explanation of Solution

Molarity of HCl is 12.0.

12 moles of HCl is present in 1 L solution.

Thus 3.0 moles of HCl is present in 3/12 L solution=0.25 L solution.

(b)

Interpretation Introduction

Interpretation:

The volume of 2.0 M HCl required to get 3.0 mol HCl needs to be calculated.

Concept Introduction :

2.0 M solution means there is 2.0 moles of solute in 1L solution.

Answer to Problem 9E

1.5 L of HCl solution is required to get 3.0 moles of HCl.

Explanation of Solution

Molarity of HCl is 2.0.

2 moles of HCl is present in 1 L solution.

Thus 3.0 moles of HCl is present in 3/2 L solution=1.5 L solution.

(c)

Interpretation Introduction

Interpretation:

The volume of 0.5 M HCl required to get 3.0 mol HCl needs to be determined.

Concept Introduction :

0.5 M solution means there is 0.5 mole of solute in 1L solution.

Answer to Problem 9E

6 L of HCl solution is required to get 3.0 moles of HCl.

Explanation of Solution

Molarity of HCl is 0.5.

0.5 mole of HCl is present in 1 L solution.

Thus 3.0 moles of HCl is present in 3/0.5 L solution=6 L solution.

(d)

Interpretation Introduction

Interpretation:

The volume of 0.010 M HCl required to get 3.0 mol HCl needs to be determined.

Concept Introduction :

0.010 M solution means there is 0.010 mole of solute in 1L solution.

Answer to Problem 9E

300 L of HCl solution is required to get 3.0 moles of HCl.

Explanation of Solution

Molarity of HCl is 0.010.

0.010 mole of HCl is present in 1 L solution.

Thus 3.0 moles of HCl is present in 3/0.010 L solution=300 L solution.