
Concept explainers
(a)
Interpretation:
If a particle view of HBr is drawn with 10 H+ ions then the number of Br- will be required must be explained.
Concept Introduction :
HBr is an acid which undergoes dissociation to produce one H+ and one Br-.
(a)

Answer to Problem 5E
10 Br- will be required.
Explanation of Solution
The dissociation of HBr can be shown as
Thus, it is clear than the number of H+ andBr- is same. So for 10 H+ ions 10 Br- ions will be required.
(b)
Interpretation:
A particle view of HBr must be drawn with 10 H+ ions.
Concept Introduction :
Number of H+ and Br- will be same as 1 HBr produces 1 H+ and 1 Br-.
(b)

Answer to Problem 5E
A sketch is shown below for HBr with 10 H+ ions.
Here, red dots represent H+ and black dots represent Br-.
Complete dissociation of HBr takes place because it is a strong acid.
Explanation of Solution
From the sketch it is clear that number of H+ and Br- ions is same. For 10 red dots (H+) there are 10 black dots (Br-).
Chapter U4 Solutions
Living By Chemistry: First Edition Textbook
Additional Science Textbook Solutions
Biology: Life on Earth with Physiology (11th Edition)
Applications and Investigations in Earth Science (9th Edition)
Campbell Biology: Concepts & Connections (9th Edition)
Campbell Biology in Focus (2nd Edition)
Chemistry (7th Edition)
Organic Chemistry (8th Edition)
- Using the following two half-reactions, determine the pH range in which $NO_2^-\ (aq)$ cannot be found as the predominant chemical species in water.* $NO_3^-(aq)+10H^+(aq)+8e^-\rightarrow NH_4^+(aq)+3H_2O(l),\ pE^{\circ}=14.88$* $NO_2^-(aq)+8H^+(aq)+6e^-\rightarrow NH_4^+(aq)+2H_2O(l),\ pE^{\circ}=15.08$arrow_forwardIndicate characteristics of oxodec acid.arrow_forwardWhat is the final product when hexanedioic acid reacts with 1º PCl5 and 2º NH3.arrow_forward
- What is the final product when D-galactose reacts with hydroxylamine?arrow_forwardIndicate the formula of the product obtained by reacting methyl 5-chloro-5-oxopentanoate with 1 mole of 4-penten-1-ylmagnesium bromide.arrow_forwardIn the two chair conformations of glucose, the most stable is the one with all the OH groups in the equatorial position. Is this correct?arrow_forward
- please help me with my homeworkarrow_forwardhelparrow_forwardThe temperature on a sample of pure X held at 1.25 atm and -54. °C is increased until the sample boils. The temperature is then held constant and the pressure is decreased by 0.42 atm. On the phase diagram below draw a path that shows this set of changes. pressure (atm) 2 0 0 200 400 temperature (K) Xarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





