
(a)
Interpretation:The number of lead ions in the 0.002 M of 10 mL solution of lead nitrate needs to be calculated.
Concept Introduction: The molecular mass of compound is the sum of
(a)

Answer to Problem SIII3RE
Explanation of Solution
Molar mass of lead nitrate = 331.2 g/mol
Concentration = 0.002 M
Volume = 10 mL = 0.01 L
1 mole = 6.022 x 1023atoms
Calculate number of lead ions:
(b)
Interpretation:The mass of lead nitrate in the 0.002 M of 10 mL solution of lead nitrate needs to be determined.
Concept Introduction: The molecular mass of compound is the sum of atomic mass of all the atoms present in the given chemical compound. Mole concept is used to calculate the moles, mass, number of atoms and moles of a compound. The relation between these values can be shown as:
(b)

Answer to Problem SIII3RE
Explanation of Solution
Molar mass of lead nitrate = 331.2 g/mol
Concentration = 0.002 M
Volume = 10 mL = 0.01 L
1 mole = 6.022 x 1023atoms
Calculate mass of lead nitrate:
(c)
Interpretation:The mass of lead ion in the 0.002 M of 10 mL solution of lead nitrate needs to be determined.
Concept Introduction: The molecular mass of compound is the sum of atomic mass of all the atoms present in the given chemical compound. Mole concept is used to calculate the moles, mass, number of atoms and moles of a compound. The relation between these values can be shown as:
(c)

Answer to Problem SIII3RE
Explanation of Solution
Molar mass of lead = 207 g/mol
Concentration = 0.002 M
Volume = 10 mL = 0.01 L
1 mole = 6.022 x 1023atoms
Calculate mass of lead nitrate:
1 mole of lead ion= 1 mole of lead nitrate
Calculate mass of lead ion:
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