
Concept explainers
(a)
Interpretation:
Number of moles of H+ in 0.75 L of a 0.10 M HCl solution must be calculated.
Concept Introduction :
Molarity of HCl solution is 0.10 means there is 0.10 mol of HCl in 1L solution.
(a)

Answer to Problem 7E
0.075 mole of H+ are there in 0.75 L of a 0.10 M HCl solution.
Explanation of Solution
From molarity, moles can be calculated as follows:
Here, M and V are molarity and volume of the solution in L.
So, moles of
As HCl is a strong acid it will produce quantitative H+. So moles of
(b)
Interpretation:
If 0.35 L water is added then the new concentration of HCl must be calculated.
Concept Introduction :
If water is added to an acid solution, the concentration decreases due to increase in volume of the solution keeping the amount of solute same.
(b)

Answer to Problem 7E
Concentration of HCl will be 0.068 M.
Explanation of Solution
The relation between initial and final strength and volume will be:
Here V1, S1, V2 and S2 are initial volume, initial strength, final volume and final strength for the HCl solution respectively.
Putting the values it can be written as
Or,
So, final concentration of HCl is 0.068 M.
(c)
Interpretation:
The pH of the diluted HCl solution needs to be calculated.
Concept Introduction :
The pH of the solution can be calculated as follows:
With dilution of acid solution, pH increases.
(c)

Answer to Problem 7E
pH will be 1.17.
Explanation of Solution
New concentration of HCl solution is 0.068 M after 0.35 L water is added.
Now,
Thus,
Chapter U4 Solutions
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