Chapter U4, Problem SIV2RE

Interpretation Introduction

Interpretation:

The three substances that neutralize HCl solution should be stated. The balanced chemical equation for each substance with HCl should be predicted.

Concept Introduction:

The reaction of an acid with a base results in the formation of salt and water. This type of reaction is known as neutralization reaction.

Answer to Problem SIV2RE

The three substances that use to neutralize a hydrochloric acid are sodium hydroxide, potassium hydroxide and calcium hydroxide. The balanced equation for each substance with HCl solution is mentioned below:

• $\text{HCl}+\text{NaOH}\to \text{NaCl}+{\text{H}}_2\text{O}$
• $\text{HCl}+\text{KOH}\to \text{KCl}+{\text{H}}_2\text{O}$
• $\text{2HCl}+\text{Ca}{\left(\text{OH}\right)}_{\text{2}}\to {\text{CaCl}}_2+2{\text{H}}_2\text{O}$

Explanation of Solution

Hydrochloric acid is a strong acid. It can be neutralized by base. The three substances that use to neutralize a hydrochloric acid are sodium hydroxide, potassium hydroxide and calcium hydroxide.

The balanced equation for each substance with HCl solution is mentioned below:

• Reaction of NaOH with HCl

  $\text{HCl}+\text{NaOH}\to \text{NaCl}+{\text{H}}_2\text{O}$

• Reaction of KOH with HCl

  $\text{HCl}+\text{KOH}\to \text{KCl}+{\text{H}}_2\text{O}$

• Reaction of $\text{Ca}{\left(\text{OH}\right)}_{\text{2}}$ with HCl

  $\text{2HCl}+\text{Ca}{\left(\text{OH}\right)}_{\text{2}}\to {\text{CaCl}}_2+2{\text{H}}_2\text{O}$

Conclusion

The three substances that use to neutralize a hydrochloric acid are sodium hydroxide, potassium hydroxide and calcium hydroxide. The balanced equation for each substance with HCl solution is mentioned below:

• $\text{HCl}+\text{NaOH}\to \text{NaCl}+{\text{H}}_2\text{O}$
• $\text{HCl}+\text{KOH}\to \text{KCl}+{\text{H}}_2\text{O}$
• $\text{2HCl}+\text{Ca}{\left(\text{OH}\right)}_{\text{2}}\to {\text{CaCl}}_2+2{\text{H}}_2\text{O}$