Chapter U4.15, Problem 6E

Interpretation Introduction

Interpretation:

Amount of fructose present in 1L of soft drink with a molarity of 0.75 needs to be determined.

Concept introduction:

Molarity of a sample is the number of moles of solute dissolved in 1L solution.

Answer to Problem 6E

135 g fructose is present in 1L of soft drink with a molarity of 0.75.

Explanation of Solution

Molarity of fructose in the soft drink is 0.75 means 0.75 moles of fructose is present in 1L soft drink. To find the mass of fructose in the soft drink, moles must be multiplied with the molecular weight of fructose which is 180.

Mass of fructose in the soft drink will be:

  $mass=180\text{ g/mol}\times 0.75\text{ mol}=135\text{ g}$

Conclusion

Thus, the mass of fructose is 135 g.