
(a)
Interpretation:
The volume of 0.10 M NaCl containing 58.44 g NaCl needs to be determined.
Concept Introduction :
Molecular weight of NaCl is 58.44 g/mol.
Molarity of NaCl is 0.10 means there is 0.10 mol NaCl in 1 L solution.
(a)

Answer to Problem 5E
10 L of 0.10 M NaCl would contain 58.44 g NaCl.
Explanation of Solution
Molecular weight of NaCl is 55.44 g/mol.
The mass can be calculated from number of moles and molar mass as follows:
I L must contain 0.10 mole NaCl
5.844 g NaCl would be in 1L solution.
So, 58.44 g NaCl is would be in 10 L solution.
(b)
Interpretation:
The volume of 3.0 M NaCl containing 58.44 g NaCl needs to be calculated.
Concept Introduction :
Molecular weight of NaCl is 58.44 g/mol.
Molarity of NaCl is 3.0 means there is 3.0 mol NaCl in 1 L solution.
(b)

Answer to Problem 5E
0.33 L of 3.0 M NaCl would contain 58.44 g NaCl.
Explanation of Solution
Molecular weight of NaCl is 55.44 g/mol.
The mass can be calculated from number of moles and molar mass as follows:
I L must contains 3.0 mole NaCl which is equal to
Since, 175.32 g is in 1 L solution, thus, 58.44 g will be in:
So 58.44 g NaCl is would be in 0.33 L solution.
(c)
Interpretation:
The volume of 5.5 M NaCl containing 58.44 g NaCl needs to be determined.
Concept Introduction :
Molecular weight of NaCl is 58.44 g.
Molarity of NaCl is 5.5 means there is 5.5 mol NaCl in 1 L solution.
(c)

Answer to Problem 5E
0.182 L of 5.5 M NaCl would contain 58.44 g NaCl.
Explanation of Solution
Molecular weight of NaCl is 55.44 g/mol.
The mass from 5.5 mol can be calculated as follows:
Thus, 1 L of solution contains 321.42 g of NaCl.
The volume of solution containing 58.44 g of NaCl will be:
Chapter U4 Solutions
Living By Chemistry: First Edition Textbook
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