Chapter U4, Problem SIII6RE

Interpretation Introduction

Interpretation: The volume of the solution needs to be calculated, if 47 g of sulfuric acid is dissolved in water to prepare 0.50 M solution.

Concept Introduction: Mole concept is used to calculate the moles, mass, number of atoms and moles of a compound. The relation between these values can be shown as:

  $\begin{array}{l}\text{Moles = }\frac{\text{mass}}{\text{molar mass}}\\ {\text{1 mole = N}}_{\text{a}}\text{ atoms}\\ {\text{N}}_{\text{a}}\text{ = 6}\text{.022 }\times {\text{ 10}}^{\text{23}}\end{array}$

The relation between molarity and moles is as follows:

  $\text{Molarity = }\frac{\text{moles }}{\text{volume }}$

Answer to Problem SIII6RE

  $volume=0.96L$

Explanation of Solution

Given information:

Mass of sulfuric acid = 47 g

Concentration of solution = 0.50 M

  $\text{Molarity = }\frac{\text{moles }}{\text{volume }}$

Molar mass of sulfuric acid = 98 g/mol

Substitute the values to calculate the volume:

  $\begin{array}{l}Molarity=\frac{moles}{volume}=\frac{\text{mass}}{\text{molar mass×volume}}\\ 0.50mol/L=\frac{47g}{98g/mol\times volume}\\ volume=\frac{47g}{98g/mol\times 0.50mol/L}\\ volume=0.96L\end{array}$

Conclusion

  $volume=0.96L$