Chapter U3.8, Problem 8E

Interpretation Introduction

Interpretation: The mass of 3.5 L of carbon dioxide gas needs to be determined.

Concept Introduction:

The density of a substance is related to its mass and volume as follows:

  $d=\frac{m}{V}$

Here, m is mass and V is volume.

Answer to Problem 8E

6.65 g.

Explanation of Solution

The density of carbon dioxide gas is 0.0019 g/mL and volume carbon dioxide gas is given 3.5 L thus, mass can be calculated as follows:

  $m=V\times d$

Putting the values,

  $m=\left(3.5\text{ L}\right)\left(\frac{1000\text{ mL}}{1\text{ L}}\right)\left(0.0019\text{ g/mL}\right)=6.65\text{ g}$

Thus, the mass is 6.65 g.

Conclusion

Therefore, the mass of carbon dioxide gas is 6.65 g.