Concept explainers
Interpretation:The change in gas pressure in flexible and rigid container needs to be explained.
Concept Introduction:
Due to random movement of gas particles, they colloid with other gas particles and also colloid with wall of container. The collision between gas particles of air and wall of container exert pressure on the wall of container.
The gas pressure is inversely proportional to the volume of gas. This is because as the gas pressure increases, the gas particles come close to each other. It decreases the intermolecular distance between particles and volume decreases.
Answer to Problem 1TAI
In a flexible container, the volume will change with pressure. On the contrary, in a rigid container, the volume will remain constant. So at constant volume, the pressure of gas is directly proportional to the temperature of gas.
Explanation of Solution
The Boyle’s law states that at constant temperature and amount of gas molecules, the volume is inversely proportional to the pressure of gas.
In a flexible container, the volume will change with pressure. As the pressure increase, the volume of gas will decrease as gas molecules will come close to each other.
On the contrary, in a rigid container, the volume will remain constant. So at constant volume, the pressure of gas is directly proportional to the temperature of gas. This is called as Gay Lussac's Law of gases.
So as the temperature of the rigid container increases, the pressure of gas also increases.
Chapter U3 Solutions
Living By Chemistry: First Edition Textbook
Additional Science Textbook Solutions
Human Anatomy & Physiology (2nd Edition)
Campbell Essential Biology (7th Edition)
Microbiology: An Introduction
Biology: Life on Earth (11th Edition)
Campbell Biology (11th Edition)
Laboratory Experiments in Microbiology (12th Edition) (What's New in Microbiology)
- Hi I need help on my practice final, If you could explain how to solve it, offer strategies, and dumb it down that would be amazing.arrow_forward-1 2 3 4 5 7 8 At a certain temperature this reaction follows first-order kinetics with a rate constant of 0.0635 s 2C1,0, (g) →2C1, (g)+50, (g) Suppose a vessel contains C1,0, at a concentration of 1.03 M. Calculate how long it takes for the concentration of C1,0, to decrease by 86.0%. You may assume no other reaction is important. Round your answer to 2 significant digits. e х th Earrow_forwardASAP....arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY