Concept explainers
Joints of high quality can be formed by friction welding. Consider the friction welding of two 40-mm-diameter Inconel rods. The bottom rod is stationary, while the top rod is forced into a back-and-forth linear motion characterized by an instantaneous horizontal displacement,
Want to see the full answer?
Check out a sample textbook solutionChapter 5 Solutions
Fundamentals of Heat and Mass Transfer
Additional Engineering Textbook Solutions
Fox and McDonald's Introduction to Fluid Mechanics
Applied Statics and Strength of Materials (6th Edition)
Automotive Technology: Principles, Diagnosis, and Service (5th Edition)
Engineering Mechanics: Statics
Engineering Mechanics: Dynamics (14th Edition)
- Please make it short and simple ( Include diagram) Handwritten would be better. Answer is 10Narrow_forwardA 915 mm diameter driving pulley is used to drive 1,220 mm pulley. The center to center distance between the two pulleys is 3.5 mm and the output of the driven shaft is 85 HP. If a leather belt is used with a belt speed of 1,300 m/min, coefficient of friction is 0.28, percent slip is 1.5% on each pulley, and loss due to friction on each shaft is 6%, calculate: (a) The rpm of each shaft: Ans. N1 = 459.13 rpm; N2 = 344.35 rpm (b) Difference in belt tension: Ans.(F1 - F2) = 3.11 kN (c) Size of 9.5 mm thick leather belt: Ans. b = 0.2475 mm; L = 10.6792 m Note: Assume open belt if not stated and assume that pulleys are of the same material. As such, f is the same and the smaller pulley is the basis of design calculations. Consider the 6 % frictional loss in your belt tension calculations.arrow_forwardThe clutch of a motor car is required to transmit 9 kW at 3500 rpm. It is of single-plate type, with both sides of the plate being effective. The coefficient of friction is 0.25 and the maximum pressure is limited to 82 N/cm2. The ratio of diameters is 1.4. Assuming uniform wear determine: (You should upload the answers in the Link provided for submitting the assignment, typing the answers in the box provided below is optional). The internal diameter of the plate in mm The external diameter of the plate in mmarrow_forward
- A single plate cutch conisists of one pair of contacting surfaces. The inner and outer diameters of the friction disk are 100 and 150 mm respectively. The coefficient of friction is 0.15 and the permissible intensity of pressure is 2 N/mm (0) Assuming uniform-pressure theory, calculate the power-transmitting capacity of the clutch at 650 rpm. (1) Assuming uniform-wear theory, calculate the power-transmitting capacity of the clutch at 650 rpmarrow_forwardProvide a very clear and complete solution as well as diagram. A pulley 600 mm in diameter transmits 40 KW at 500 rpm. The arc of contact between the belt and pulley is 144 degrees, the coefficient of friction between belt and pulley is 0.15 and the safe working stress of the beltis 2.1 Mpa. Determine the belt tension ratio, neglecting the effect of centrifugal force. A. 2.41 B. 2.44 C. 1.458 D. 4.1arrow_forwardA nut which is connected to a lead screw is moved in a horizontal plane against a force of 100kN at a speed of 4mm/sec by electric motor powered screw. The following data is given Single start square thread screw Pitch of the screw = 6mm Outlet diameter of the screw = 40mm Co-efficient of friction of the screw thread = 0.15 Efficiency of the motor = 85% Determine the power required and efficiency of the screwarrow_forward
- Please solve ellaborately and include the untis in every step, show diagram and write your solutions clearly and readable if your solution is in written form. Your work will be appreaciated much. Thank You. A pulley 190 mm. in diameter transmits 22 kW at 350 rpm. The arc of contact between the belt and pulley is 115.7° having a center distance of 410 mm. Determine (a) diameter of the driven pulley for open belt drive,(b) speed of the driven pulley, and (c) belt length for an open belt connection. (a) Diameter of Driven Pulley Answer and unit for part 1 (b) Speed of the Driven Pulley Answer and unit for part 2 (c) Belt Lengtharrow_forwardi need the answer quicklyarrow_forwardA bolt is expected to break at 105 ft-lb of torque. A cheater bar is being used to tighten the bolt. The cheater bar is placed on the wrench 3 inches from the center of the bolt. The cheater bar is made of pipe that is 6.6 pounds per linear foot. The bar is 5.7 feet long. What is the lowest angle above the horizon that that the bar can be held before it exceeds the maximum expected torque?arrow_forward
- A football (soccer) player can kick the ball with about 4 kN of force. Suppose an athlete accidentally kicks their competitor's tibia instead of the ball. This injury may be modeled by the diagram below, where the kick is represented by force F. Assume that the load is applied directly in the middle of the tibia. For the sake of simplicity, model the bone as a solid beam with 2 cm x 2 cm square cross-sectional area. Note that the pin and roller in the model do not induce reaction moments. Use E = 16 GPa. F = 500 N/cm 20 cm (a) Draw a free body diagram (FBD) including all external forces.arrow_forwardA nut which is connected to a lead screw is moved in a horizontal plane against a force of 100kN at a speed of 4mm/sec by electric motor powered screw. The following data is given Single start square thread screw Pitch of the screw=6mm Outlet diameter of the screw =40mm Co-efficient of friction of the screw thread =0.15 Efficiency of the motor=85% Determine the power required and efficiency of the screw The following data is refers to a screw jack. The vertical load on the screw=20kN Force applied at the lever end whose length=80cm The mean radius of the screw-2.5cm Pitch of the screw=1cm Co-efficient of friction between the screw thread and the nut=0.15 Determine the force on the lever end while raising the load and efficiency of the screw jackarrow_forwardWe will use both shearing and bearing analysis to determine the quantities of rivets needed to fasten BC and BE. We can determine two values then choose what will be more safe. ■ For Member BC: ■ Based on Shearing: V T == ■ Av Based on Bearing: P Ab 70MPa = 96000 N .n. (19) ²x n 1/4. π n = 4.84 5 rivets 96000 N (19mm) (6mm) xn 140MPa n = 46.015≈ 7 rivets For member BC, we must use 7 rivets since we must need a minimum of 7 rivets to resist bearing stress produced by the connection. If we only use 5 rivets, then the bearing stress will become 168.42 MPa. It will result to failure since the allowable bearing stress is only 140 Mpa. ■ For member BE: (Practice at Home) Pac EXAMPLE: 5. The figure shows a roof truss and the detail of the riveted connection at joint B. Using allowable stresses of t = 70 MPa and ob= 140 MPa, how many 19-mm diameter rivets are required to fasten member BC to the gusset plate? Member BE? What is the largest average tensile or compressive stress in BC and BE? Say…arrow_forward
- Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University PressMechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSONThermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
- Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEYMechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage LearningEngineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY