Chapter 3.2, Problem 24AYU

To determine

Explain why it does not make sense to interpret the $y-\mathrm{int}ercept$ .

Answer to Problem 24AYU

There is no existence of $y$ intercept here that is why it does not make any sense to interpret the $y$ intercept in problem.

Explanation of Solution

Given information:

Explain why it does not make sense to interpret the $y-\mathrm{int}ercept$ .

  $\begin{array}{ccc}CandyBar& Weight,x& Calories,y\\ Hershey\text{'}sMilkChocolate& 44.28& 230\\ Nestle\text{'}scrunch& 44.84& 230\\ Butterfinger& 61.30& 270\\ Babyruth& 66.45& 280\\ AlmondJoy& 47.33& 220\\ Twix\left(withcaramel\right)& 58,00& 280\\ snic\ker s& 61.12& 280\\ Heath& 39.52& 210\end{array}$

Calculation:

Consider the table,

  $\begin{array}{ccc}CandyBar& Weight,x& Calories,y\\ Hershey\text{'}sMilkChocolate& 44.28& 230\\ Nestle\text{'}scrunch& 44.84& 230\\ Butterfinger& 61.30& 270\\ Babyruth& 66.45& 280\\ AlmondJoy& 47.33& 220\\ Twix\left(withcaramel\right)& 58,00& 280\\ snic\ker s& 61.12& 280\\ Heath& 39.52& 210\end{array}$

As we have that for $y$ intercept, $x$ coordinate is always zero, or the value of independent variable must always be zero

Now as in problem, a candy bar would always have some weight that is independent variable in the given table, so for the existence of candy bar, the value of weight can verve be zero that means there is no existence of $y$ intercept here that is why it does not make any sense to interpret the $y$ intercept in problem there.

Hence,there is no existence of $y$ intercept here that is why it does not make any sense to interpret the $y$ intercept in problem there.