Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
2nd Edition
ISBN: 9781305079243
Author: Steven S. Zumdahl, Susan A. Zumdahl
Publisher: Cengage Learning
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Chapter 21, Problem 2Q

(a)

Interpretation Introduction

Interpretation: The type of isomerism that could be exhibited by the given formulas.

An example that illustrates the specific type of isomerism is to be stated.

Concept introduction: Organic compounds which have similar chemical formula but different structures, i.e., the atoms are in a different spatial arrangement, they are known as structural isomers. Cis and Trans isomers are also structural or geometrical isomers.

To determine: The type of isomerism that could be exhibited by C6H12 and an example that illustrates the specific type of isomerism.

(a)

Expert Solution
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Explanation of Solution

Explanation

The structural isomer of C6H12 is 1 -hexene.

The given formula, C6H12 has six carbon atoms and twelve hydrogen atoms. 1 -hexene also has six carbon atoms and twelve hydrogen atoms but their structures are different. Therefore, 1 -hexene is a structural isomer of C6H12 .

The root word hexene indicates that six carbon atoms are present in the parent chain. Double bond is present between first and second carbon.

The structure of 1 -hexene is shown in Figure 1.

Chemistry: An Atoms First Approach, Chapter 21, Problem 2Q , additional homework tip  1

Figure 1

The structural isomer of C6H12 is 2 -hexene.

The given formula, C6H12 has six carbon atoms and twelve hydrogen atoms. 2 -hexene also has six carbon atoms and twelve hydrogen atoms but their structures are different. Therefore, 2 -hexene is a structural isomer of C6H12 .

The root word hexene indicates that six carbon atoms are present in the parent chain. The number 2 indicates that the double bond is present between second and third carbon.

The structure of 2 -hexene is shown in Figure 2.

Chemistry: An Atoms First Approach, Chapter 21, Problem 2Q , additional homework tip  2

Figure 2

The structural isomer of C6H12 is 3 -hexene.

The given formula, C6H12 has six carbon atoms and twelve hydrogen atoms. 3 -hexene also has six carbon atoms and twelve hydrogen atoms but their structures are different. Therefore, 3 -hexene is a structural isomer of C6H12 .

The root word hexene indicates that six carbon atoms are present in the parent chain. The number 3 indicates that the double bond is present between the third and fourth carbon.

The structure of 3 -hexene is shown in Figure 3.

Chemistry: An Atoms First Approach, Chapter 21, Problem 2Q , additional homework tip  3

Figure 3

The structural isomer of C6H12 is 3 -methylpent- 2 -ene.

The given formula, C6H12 has six carbon atoms and twelve hydrogen atoms. 3 -methylpent- 2 -ene also has six carbon atoms and twelve hydrogen atoms but their structures are different. Therefore, 3 -methylpent- 2 -ene is a structural isomer of C6H12 .

The root word pentene indicates that five carbon atoms are present in the parent chain. The number 2 indicates that the double bond is present between second and third carbon. The number 3 indicates that the methyl group is attached to the third carbon.

The structure of 3 -methylpent- 2 -ene is shown in Figure 4.

Chemistry: An Atoms First Approach, Chapter 21, Problem 2Q , additional homework tip  4

Figure 4

The structural isomer of C6H12 is 2,3 -dimethylbut- 2 -ene.

The given formula, C6H12 has six carbon atoms and twelve  hydrogen atoms. 2,3 -dimethylbut- 2 -ene also has six carbon atoms and twelve hydrogen atoms but their structures are different. Therefore, 2,3 -dimethylbut- 2 -ene is a structural isomer of C6H12

The root word butene indicates that six carbon atoms are present in the parent chain. The double bond is present between second and third carbon. Two methyl groups are attached at second and third carbon.

The structure of 2,3 -dimethylbut- 2 -ene is shown in Figure 5.

Chemistry: An Atoms First Approach, Chapter 21, Problem 2Q , additional homework tip  5

Figure 5

The geometric isomer of C6H12 is cis- 2 -hexene and trans- 2 -hexene.

The structure of cis- 2 -hexene is,

Chemistry: An Atoms First Approach, Chapter 21, Problem 2Q , additional homework tip  6

Figure 6

The structure of trans- 2 -hexene is,

Chemistry: An Atoms First Approach, Chapter 21, Problem 2Q , additional homework tip  7

Figure 7

In the cis isomer, the two hydrogen of the double bonded carbons are adjacent to each other while in trans isomer, they are opposite to each other.

The geometric isomer of C6H12 is cis- 3 -hexene and trans- 3 -hexene.

The structure of cis- 3 -hexene is,

Chemistry: An Atoms First Approach, Chapter 21, Problem 2Q , additional homework tip  8

Figure 8

The structure of trans- 3 -hexene is,

Chemistry: An Atoms First Approach, Chapter 21, Problem 2Q , additional homework tip  9

Figure 9

In the cis isomer, the two hydrogen of the double bonded carbons are adjacent to each other while in trans isomer, they are opposite to each other.

(b)

Interpretation Introduction

Interpretation: The type of isomerism that could be exhibited by the given formulas.

An example that illustrates the specific type of isomerism is to be stated.

Concept introduction: Organic compounds which have similar chemical formula but different structures, i.e., the atoms are in a different spatial arrangement, they are known as structural isomers. Cis and Trans isomers are also structural or geometrical isomers.

To determine: The type of isomerism that could be exhibited by C5H10O and an example that illustrates the specific type of isomerism.

(b)

Expert Solution
Check Mark

Explanation of Solution

Explanation

C5H10O have five carbon atoms, ten hydrogen atoms and one oxygen atom. pentan-1-ol also have five carbon atoms, ten hydrogen atoms and one oxygen atom  but their structures are different. Therefore, pentan-1-ol is a structural isomer of C5H10O .

The root word pentane indicates that five carbon atoms are present in the parent chain. Hydroxyl group is attached to first carbon.

The structure of pentan-1-ol is shown in Figure 10.

Chemistry: An Atoms First Approach, Chapter 21, Problem 2Q , additional homework tip  10

Figure 10

The structural isomer of C5H10O is 1 -methoxybutane.

C5H10O have five carbon atoms, ten hydrogen atoms and one oxygen atom. 1 -methoxybutane also have five carbon atoms, ten hydrogen atoms and one oxygen atom  but their structures are different. Therefore, 1 -methoxybutane is a structural isomer of C5H10O .

The root word butane indicates that four carbon atoms are present in the parent chain. 1 -methoxy indicates that ether group is present and methyl group is attached to the oxygen of ether group.

The structure of 1 -methoxybutane is shown in Figure 11.

Chemistry: An Atoms First Approach, Chapter 21, Problem 2Q , additional homework tip  11

Figure 11

The structural isomer of C5H10O is 2 -ethoxypropane.

C5H10O have five carbon atoms, ten hydrogen atoms and one oxygen atom. 2 -ethoxypropane also have five carbon atoms, ten hydrogen atoms and one oxygen atom  but their structures are different. Therefore, 2 -ethoxypropane is a structural isomer of C5H10O .

The root word propane indicates that three carbon atoms are present in the parent chain. 2 -ethoxy indicates that ether group is present and ethyl group is attached to the oxygen of ether group and second carbon of propane chain is attached to oxygen.

The structure of 2 -ethoxypropane is shown in Figure 12.

Chemistry: An Atoms First Approach, Chapter 21, Problem 2Q , additional homework tip  12

Figure 12

The structural isomer of C5H10O is 2 -methoxybutane.

C5H10O have five carbon atoms, ten hydrogen atoms and one oxygen atom. v also have five carbon atoms, ten hydrogen atoms and one oxygen atom but their structures are different. Therefore, 2 -methoxybutane is a structural isomer of C5H10O .

The root word butane indicates that four carbon atoms are present in the parent chain. 2 -methoxy indicates that ether group is present and methyl group is attached to the oxygen of ether group and second carbon of butane chain is attached to oxygen.

The structure of 2 -methoxybutane is shown in Figure 13.

Chemistry: An Atoms First Approach, Chapter 21, Problem 2Q , additional homework tip  13

Figure 13

The structural isomer of C5H10O is pentan- 3 -ol.

C5H10O have five carbon atoms, ten hydrogen atoms and one oxygen atom. pentan- 3 -ol also have five carbon atoms, ten hydrogen atoms and one oxygen atom but their structures are different. Therefore, pentan- 3 -ol is a structural isomer of C5H10O .

The root word pentane indicates that five carbon atoms are present in the parent chain. Hydroxyl group is attached to third carbon.

The structure of pentan- 3 -ol is shown in Figure 14.

Chemistry: An Atoms First Approach, Chapter 21, Problem 2Q , additional homework tip  14

Figure 14

The structural isomer of C5H10O is pentan- 2 -ol.

C5H10O have five carbon atoms, ten hydrogen atoms and one oxygen atom. pentan- 2 -ol also have five carbon atoms, ten hydrogen atoms and one oxygen atom but their structures are different. Therefore, pentan- 2 -ol is a structural isomer of C5H10O .

The root word pentane indicates that five carbon atoms are present in the parent chain. Hydroxyl group is attached to second carbon.

The structure of pentan- 2 -ol is shown in Figure 15.

Chemistry: An Atoms First Approach, Chapter 21, Problem 2Q , additional homework tip  15

Figure 15

(c)

Interpretation Introduction

Interpretation: The type of isomerism that could be exhibited by the given formulas.

An example that illustrates the specific type of isomerism is to be stated.

Concept introduction: Organic compounds which have similar chemical formula but different structures, i.e., the atoms are in a different spatial arrangement, they are known as structural isomers. Cis and Trans isomers are also structural or geometrical isomers.

To determine: The type of isomerism that could be exhibited by C6H4Br2 and an example that illustrates the specific type of isomerism.

(c)

Expert Solution
Check Mark

Explanation of Solution

Explanation

The structural isomer of C6H4Br2 is 1,2 -dibromobenzene.

In C6H4Br2 , six carbon atoms, four hydrogen atoms and two bromine atoms are present. 1,2 -dibromobenzene also have six carbon atoms, four hydrogen atoms and two bromine atoms. In 1,2 -dibromobenzene, two bromine atoms are attached to benzene ring at first and second position, therefore prefix di is used. Its structure is,

Chemistry: An Atoms First Approach, Chapter 21, Problem 2Q , additional homework tip  16

Figure 16

The structural isomer of C6H4Br2 is 1,3 -dibromobenzene.

In C6H4Br2 , six carbon atoms, four hydrogen atoms and two bromine atoms are present. 1,3 -dibromobenzene also have six carbon atoms, four hydrogen atoms and two bromine atoms. In 1,3 -dibromobenzene, two bromine atoms are attached to benzene ring at first and third position, therefore prefix di is used. Its structure is,

Chemistry: An Atoms First Approach, Chapter 21, Problem 2Q , additional homework tip  17

Figure 17

The structural isomer of C6H4Br2 is 1,4 -dibromobenzene.

In C6H4Br2 , six carbon atoms, four hydrogen atoms and two bromine atoms are present. 1,4 -dibromobenzene also have six carbon atoms, four hydrogen atoms and two bromine atoms. In 1,4 -dibromobenzene, two bromine atoms are attached to benzene ring at first and third position, therefore prefix di is used. Its structure is,

Chemistry: An Atoms First Approach, Chapter 21, Problem 2Q , additional homework tip  18

Figure 18

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Chapter 21 Solutions

Chemistry: An Atoms First Approach

Ch. 21 - Prob. 11RQCh. 21 - Prob. 12RQCh. 21 - Prob. 1QCh. 21 - Prob. 2QCh. 21 - What is wrong with the following names? Give the...Ch. 21 - Prob. 4QCh. 21 - Prob. 5QCh. 21 - Prob. 6QCh. 21 - Prob. 7QCh. 21 - Prob. 8QCh. 21 - Prob. 9QCh. 21 - Prob. 10QCh. 21 - Prob. 11QCh. 21 - Prob. 12QCh. 21 - Prob. 13ECh. 21 - Prob. 14ECh. 21 - Draw all the structural isomers for C8H18 that...Ch. 21 - Draw all the structural isomers for C8H18 that...Ch. 21 - Prob. 17ECh. 21 - Prob. 18ECh. 21 - Draw the structural formula for each of the...Ch. 21 - Prob. 20ECh. 21 - Prob. 21ECh. 21 - Prob. 22ECh. 21 - Prob. 23ECh. 21 - Prob. 24ECh. 21 - Name each of the following alkenes. a. CH2 = CH ...Ch. 21 - Name each of the following alkenes or alkynes. a....Ch. 21 - Prob. 27ECh. 21 - Prob. 28ECh. 21 - Prob. 29ECh. 21 - Prob. 30ECh. 21 - Name each of the following. a. b. CH3CH2CH2CCl3 c....Ch. 21 - Prob. 32ECh. 21 - There is only one compound that is named...Ch. 21 - Prob. 34ECh. 21 - Prob. 35ECh. 21 - Prob. 36ECh. 21 - Prob. 37ECh. 21 - Prob. 38ECh. 21 - Prob. 39ECh. 21 - Prob. 40ECh. 21 - Draw all structural and geometrical (cistrans)...Ch. 21 - Prob. 42ECh. 21 - Prob. 43ECh. 21 - Prob. 44ECh. 21 - If one hydrogen in a hydrocarbon is replaced by a...Ch. 21 - There are three isomers of dichlorobenzene, one of...Ch. 21 - Prob. 47ECh. 21 - Prob. 48ECh. 21 - Prob. 49ECh. 21 - Minoxidil (C9H15N5O) is a compound produced by...Ch. 21 - Prob. 51ECh. 21 - Prob. 52ECh. 21 - Name all the alcohols that have the formula...Ch. 21 - Prob. 54ECh. 21 - Prob. 55ECh. 21 - Prob. 56ECh. 21 - Prob. 57ECh. 21 - Prob. 58ECh. 21 - Prob. 59ECh. 21 - Prob. 60ECh. 21 - Prob. 61ECh. 21 - Prob. 62ECh. 21 - Prob. 63ECh. 21 - Prob. 64ECh. 21 - Prob. 65ECh. 21 - Prob. 66ECh. 21 - Prob. 67ECh. 21 - Prob. 68ECh. 21 - Prob. 69ECh. 21 - Complete the following reactions. a. CH3CO2H +...Ch. 21 - Prob. 71ECh. 21 - Prob. 72ECh. 21 - Prob. 73ECh. 21 - Prob. 74ECh. 21 - Prob. 75ECh. 21 - The polyester formed from lactic acid, is used for...Ch. 21 - Prob. 77ECh. 21 - Prob. 78ECh. 21 - Prob. 79ECh. 21 - Prob. 80ECh. 21 - Prob. 81ECh. 21 - Prob. 82ECh. 21 - Prob. 83ECh. 21 - Prob. 84ECh. 21 - Prob. 85ECh. 21 - Prob. 86ECh. 21 - Prob. 87ECh. 21 - Prob. 88ECh. 21 - Prob. 89ECh. 21 - Prob. 90ECh. 21 - Prob. 91ECh. 21 - Prob. 92ECh. 21 - Prob. 93ECh. 21 - Prob. 94ECh. 21 - Prob. 95ECh. 21 - Prob. 96ECh. 21 - Prob. 97ECh. 21 - Prob. 98ECh. 21 - Prob. 99ECh. 21 - Prob. 100ECh. 21 - Prob. 101ECh. 21 - Prob. 102ECh. 21 - Prob. 103ECh. 21 - Prob. 104ECh. 21 - Prob. 105ECh. 21 - Prob. 106ECh. 21 - Which base will hydrogen-bond with uracil within...Ch. 21 - Prob. 108ECh. 21 - The base sequences in mRNA that code for certain...Ch. 21 - Prob. 110ECh. 21 - Prob. 111AECh. 21 - Prob. 112AECh. 21 - Prob. 113AECh. 21 - Prob. 114AECh. 21 - Prob. 115AECh. 21 - Prob. 116AECh. 21 - Prob. 117AECh. 21 - Prob. 118AECh. 21 - Prob. 119AECh. 21 - Prob. 120AECh. 21 - Prob. 121AECh. 21 - Prob. 122AECh. 21 - Prob. 123AECh. 21 - Prob. 124AECh. 21 - Prob. 125AECh. 21 - Prob. 126AECh. 21 - Prob. 127AECh. 21 - Prob. 128AECh. 21 - Prob. 129AECh. 21 - Prob. 130AECh. 21 - Prob. 131AECh. 21 - Prob. 132AECh. 21 - Prob. 133AECh. 21 - Prob. 134AECh. 21 - When heat is added to proteins, the hydrogen...Ch. 21 - Prob. 136AECh. 21 - Prob. 137CWPCh. 21 - Prob. 138CWPCh. 21 - Prob. 139CWPCh. 21 - Name each of the following alkenes and alkynes. a....Ch. 21 - a. Name each of the following alcohols. b. Name...Ch. 21 - Prob. 142CWPCh. 21 - Prob. 143CWPCh. 21 - Prob. 144CWPCh. 21 - Prob. 145CPCh. 21 - Prob. 146CPCh. 21 - Prob. 147CPCh. 21 - Prob. 148CPCh. 21 - Prob. 149CPCh. 21 - Prob. 150CPCh. 21 - Prob. 151CPCh. 21 - Prob. 152CPCh. 21 - Prob. 153CPCh. 21 - Prob. 154CPCh. 21 - Stretch a rubber band while holding it gently to...Ch. 21 - Alcohols are very useful starting materials for...Ch. 21 - Prob. 157CPCh. 21 - Prob. 158CPCh. 21 - Prob. 159IPCh. 21 - Prob. 160IPCh. 21 - Prob. 161MPCh. 21 - Prob. 162MP
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