Chapter U5.7, Problem 4E

(a)

Interpretation Introduction

Interpretation: The balanced chemical equation for the following combustion reaction needs to be written and the fuel in the reaction needs to be identified.

  ${\text{C}}_{\text{2}}{\text{H}}_{\text{6}}(g)+{\text{O}}_{\text{2}}(g)\to {\text{CO}}_{\text{2}}(g)+{\text{H}}_{\text{2}}\text{O}\text{(}l\text{)}$

Concept Introduction Combustion is a chemical reaction where a compound or an element undergoes reaction with oxygen and releases energy in the form of light and heat. A wide variety of substances undergoes combustion. Solid, such as wood and coal, liquids such as kerosene or methanol and gases like hydrogen and methane etc. all can combust.

Answer to Problem 4E

Balanced chemical equation is,

  ${\text{2C}}_{\text{2}}{\text{H}}_{\text{6}}(g)+7{\text{O}}_{\text{2}}(g)\to 4{\text{CO}}_{\text{2}}(g)+6{\text{H}}_{\text{2}}\text{O}\text{(}l\text{)}$

And fuel in the reaction is ${\text{C}}_2{\text{H}}_6$ .

Explanation of Solution

Balanced chemical reaction is the chemical equation in which number of atoms of every element is equal in both reactant and product side of the chemical equal.

Given equation is as follows:

  ${\text{C}}_{\text{2}}{\text{H}}_{\text{6}}(g)+{\text{O}}_{\text{2}}(g)\to {\text{CO}}_{\text{2}}(g)+{\text{H}}_{\text{2}}\text{O}\text{(}l\text{)}$

The above equation is not a balanced chemical equation. To balance the equation, add coefficient 2 to ${\text{C}}_2{\text{H}}_6$ , coefficient 7 to ${\text{O}}_{\text{2}}$ , coefficient 4 to ${\text{CO}}_{\text{2}}$ and 6 to ${\text{H}}_2\text{O}$

  ${\text{2C}}_{\text{2}}{\text{H}}_{\text{6}}(g)+7{\text{O}}_{\text{2}}(g)\to 4{\text{CO}}_{\text{2}}(g)+6{\text{H}}_{\text{2}}\text{O}\text{(}l\text{)}$

In a combustion reaction, the other reactant which reacts with oxygen is called as fuel. So, fuel in the reaction is ${\text{C}}_2{\text{H}}_6$ .

(b)

Interpretation Introduction

Interpretation: The balanced chemical equation for the following combustion reaction needs to be written and the fuel in the reaction needs to be identified.

  ${\text{C}}_6{\text{H}}_{12}{\text{O}}_{\text{6}}(s)+{\text{O}}_{\text{2}}(g)\to {\text{CO}}_{\text{2}}(g)+{\text{H}}_{\text{2}}\text{O}\text{(}l\text{)}$

Concept Introduction : Combustion is a chemical reaction where a compound or an element undergoes reaction with oxygen and releases energy in the form of light and heat. A wide variety of substances undergoes combustion. Solid, such as wood and coal, liquids such as kerosene or methanol and gases like hydrogen and methane etc. all can combust.

Answer to Problem 4E

Balanced chemical equation is,

  ${\text{C}}_6{\text{H}}_{12}{\text{O}}_{\text{6}}(s)+6{\text{O}}_{\text{2}}(g)\to 6{\text{CO}}_{\text{2}}(g)+6{\text{H}}_{\text{2}}\text{O}\text{(}l\text{)}$

And fuel in the reaction is

Explanation of Solution

Balanced chemical reaction is the chemical equation in which number of atoms of every element is equal in both reactant and product side of the chemical equal.

The given equation is,

  ${\text{C}}_6{\text{H}}_{12}{\text{O}}_{\text{6}}(s)+{\text{O}}_{\text{2}}(g)\to {\text{CO}}_{\text{2}}(g)+{\text{H}}_{\text{2}}\text{O}\text{(}l\text{)}$

The above equation is not a balanced chemical equation. To balance the equation, add coefficient 6 to ${\text{O}}_{\text{2}}$ , coefficient 6 to ${\text{CO}}_{\text{2}}$ and coefficient 6 to ${\text{H}}_2\text{O}$ .

  ${\text{C}}_6{\text{H}}_{12}{\text{O}}_{\text{6}}(s)+6{\text{O}}_{\text{2}}(g)\to 6{\text{CO}}_{\text{2}}(g)+6{\text{H}}_{\text{2}}\text{O}\text{(}l\text{)}$

In a combustion reaction, the other reactant which reacts with oxygen is called as fuel. So, fuel in the reaction is ${\text{C}}_6{\text{H}}_{12}{\text{O}}_{\text{6}}$ .

(c)

Interpretation Introduction

Interpretation: The balanced chemical equation for the following combustion reaction needs to be written and the fuel in the reaction needs to be identified.

  ${\text{C}}_2{\text{H}}_5\text{OH}(l)+{\text{O}}_{\text{2}}(g)\to {\text{CO}}_{\text{2}}(g)+{\text{H}}_{\text{2}}\text{O}\text{(}l\text{)}$

Concept Introduction : Combustion is a chemical reaction where a compound or an element undergoes reaction with oxygen and releases energy in the form of light and heat. A wide variety of substances undergoes combustion. Solid, such as wood and coal, liquids such as kerosene or methanol and gases like hydrogen and methane etc. all can combust.

Answer to Problem 4E

Balanced chemical equation is,

  ${\text{C}}_2{\text{H}}_5\text{OH}(l)+3{\text{O}}_{\text{2}}(g)\to 2{\text{CO}}_{\text{2}}(g)+3{\text{H}}_{\text{2}}\text{O}\text{(}l\text{)}$

And fuel in the reaction is ${\text{C}}_2{\text{H}}_5\text{OH}$ .

Explanation of Solution

Balanced chemical reaction is the chemical equation in which number of atoms of every element is equal in both reactant and product side of the chemical equal.

The given equation is,

  ${\text{C}}_2{\text{H}}_5\text{OH}(l)+{\text{O}}_{\text{2}}(g)\to {\text{CO}}_{\text{2}}(g)+{\text{H}}_{\text{2}}\text{O}\text{(}l\text{)}$

The above equation is not a balanced chemical equation. To balance the equation, add coefficient 2 to ${\text{CO}}_{\text{2}}$ , coefficient 3 to ${\text{H}}_2\text{O}$ and coefficient 3 to ${\text{O}}_2$ .

  ${\text{C}}_2{\text{H}}_5\text{OH}(l)+3{\text{O}}_{\text{2}}(g)\to 2{\text{CO}}_{\text{2}}(g)+3{\text{H}}_{\text{2}}\text{O}\text{(}l\text{)}$

In a combustion reaction, the other reactant which reacts with oxygen is called as fuel. So, fuel in the reaction is ${\text{C}}_2{\text{H}}_5\text{OH}$ .

(d)

Interpretation Introduction

Interpretation: The balanced chemical equation for the following combustion reaction needs to be written and the fuel in the reaction needs to be identified.

  ${\text{C}}_{21}{\text{H}}_{24}{\text{N}}_2{\text{O}}_4(s)+{\text{O}}_{\text{2}}(g)\to {\text{CO}}_{\text{2}}(g)+{\text{H}}_{\text{2}}\text{O}\text{(}l\text{)}\text{+}{\text{NO}}_{\text{2}}(g)$

Concept Introduction: Combustion is a chemical reaction where a compound or an element undergoes reaction with oxygen and releases energy in the form of light and heat. A wide variety of substances undergoes combustion. Solid, such as wood and coal, liquids such as kerosene or methanol and gases like hydrogen and methane etc. all can combust.

Answer to Problem 4E

Balanced chemical equation is,

  ${\text{C}}_{21}{\text{H}}_{24}{\text{N}}_2{\text{O}}_4(s)+27{\text{O}}_{\text{2}}(g)\to 21{\text{CO}}_{\text{2}}(g)+12{\text{H}}_{\text{2}}\text{O}\text{(}l\text{)}\text{+}2{\text{NO}}_{\text{2}}(g)$

Fuel in the reaction is ${\text{C}}_{21}{\text{H}}_{24}{\text{N}}_2{\text{O}}_4$

Explanation of Solution

Balanced chemical reaction is the chemical equation in which number of atoms of every element is equal in both reactant and product side of the chemical equal.

The given equation is,

  ${\text{C}}_{21}{\text{H}}_{24}{\text{N}}_2{\text{O}}_4(s)+{\text{O}}_{\text{2}}(g)\to {\text{CO}}_{\text{2}}(g)+{\text{H}}_{\text{2}}\text{O}\text{(}l\text{)}\text{+}{\text{NO}}_{\text{2}}(g)$

The above equation is not a balanced chemical equation. To balance the equation, add coefficient 21 to ${\text{CO}}_{\text{2}}$ , coefficient 12 to ${\text{H}}_2\text{O}$ , 2 to ${\text{NO}}_2$ and coefficient 27 to ${\text{O}}_2$ .

  ${\text{C}}_{21}{\text{H}}_{24}{\text{N}}_2{\text{O}}_4(s)+27{\text{O}}_{\text{2}}(g)\to 21{\text{CO}}_{\text{2}}(g)+12{\text{H}}_{\text{2}}\text{O}\text{(}l\text{)}\text{+}2{\text{NO}}_{\text{2}}(g)$

In a combustion reaction, the other reactant which reacts with oxygen is called as fuel. So, fuel in the reaction is ${\text{C}}_{21}{\text{H}}_{24}{\text{N}}_2{\text{O}}_4$ .

(e)

Interpretation Introduction

Interpretation: The balanced chemical equation for the following combustion reaction needs to be written and the fuel in the reaction needs to be identified.

  ${\text{C}}_2{\text{H}}_5\text{SH}(l)+{\text{O}}_{\text{2}}(g)\to {\text{CO}}_{\text{2}}(g)+{\text{H}}_{\text{2}}\text{O}\text{(}l\text{)}\text{+}{\text{SO}}_2(g)$

Concept Introduction: Combustion is a chemical reaction where a compound or an element undergoes reaction with oxygen and releases energy in the form of light and heat. A wide variety of substances undergoes combustion. Solid, such as wood and coal, liquids such as kerosene or methanol and gases like hydrogen and methane etc. all can combust.

Answer to Problem 4E

Balanced chemical equation is,

  ${\text{2C}}_2{\text{H}}_5\text{SH}(l)+9{\text{O}}_{\text{2}}(g)\to 4{\text{CO}}_{\text{2}}(g)+6{\text{H}}_{\text{2}}\text{O}\text{(}l\text{)}\text{+}2{\text{SO}}_2(g)$

And fuel in the reaction is ${\text{C}}_2{\text{H}}_5\text{SH}$ .

Explanation of Solution

Balanced chemical reaction is the chemical equation in which number of atoms of every element is equal in both reactant and product side of the chemical equal.

The given equation is,

  ${\text{C}}_2{\text{H}}_5\text{SH}(l)+{\text{O}}_{\text{2}}(g)\to {\text{CO}}_{\text{2}}(g)+{\text{H}}_{\text{2}}\text{O}\text{(}l\text{)}\text{+}{\text{SO}}_2(g)$

The above equation is not a balanced chemical equation. To balance the equation, add coefficient 2 to ${\text{C}}_2{\text{H}}_5\text{SH}$ , coefficient 9 to ${\text{O}}_2$ , coefficient 4 to ${\text{CO}}_2$ , 6 to ${\text{H}}_2\text{O}$ and coefficient 2 to ${\text{SO}}_2$ .

  ${\text{2C}}_2{\text{H}}_5\text{SH}(l)+9{\text{O}}_{\text{2}}(g)\to 4{\text{CO}}_{\text{2}}(g)+6{\text{H}}_{\text{2}}\text{O}\text{(}l\text{)}\text{+}2{\text{SO}}_2(g)$

In a combustion reaction, the other reactant which reacts with oxygen is called as fuel. So, fuel in the reaction is ${\text{C}}_2{\text{H}}_5\text{SH}$ .