
Concept explainers
(a)
Interpretation:
The metal that will be oxidized and the metal that will be reduced when an
Concept introduction:
Metal will be oxidized for which reduction potential is less. It will be a reducing agent.

Answer to Problem SIV5RE
Lead metal will be oxidized and silver metal will be reduced.
Explanation of Solution
As the silver electrode has a higher reduction potential as compared to the lead electrode, silver will be cathode where reduction will take place. Thus silver will be reduced and lead will be oxidized.
The two half cell reactions are shown in which 2e are involved.
(b)
Interpretation:
The balanced overall reaction must be written for the cell.
Concept introduction:
Overall electrochemical reaction is the total reaction taking place in cathode and anode which includes oxidation of one electrode and reduction of another electrode.

Answer to Problem SIV5RE
The overall cell reaction is
Explanation of Solution
The overall reaction for the cell is written in which electrons are cancelled from both the sides.
The physical states of all the species involved are given in bracket.
(c)
Interpretation:
The number moles of electrons that will flow from cathode to anode must be calculated.
Concept introduction:
Silver is monovalent cation whereas lead is divalent cation. So, 2 moles of silver ions are reacting with 1 mole of lead.

Answer to Problem SIV5RE
2 moles of electron will flow from anode to cathode.
Explanation of Solution
From the two half cell reactions, it can be seen that 2 moles of electrons are involved.
So from anode to cathode, 2 moles of electrons will flow.
(d)
Interpretation:
The voltage for the electrochemical cell must be calculated.
Concept introduction:
The voltage of an electrochemical cell can be written as

Answer to Problem SIV5RE
Voltage of the electrochemical cell is 0.93 V.
Explanation of Solution
The standard reduction potential for silver (cathode) and lead (anode) electrode are 0.80 V and -0.13 V respectively.
Thus,
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