
Concept explainers
a)
Interpretation:
Balanced equation for the combustion of propane must be given.
Concept Introduction:
Hydrocarbons undergo combustion reaction to produce carbon dioxide and water as shown below.
Here x and y represents number of carbon and hydrogen atoms in the hydrocarbon.
a)

Answer to Problem SII4RE
Explanation of Solution
There are 3 carbons and 8 hydrogens. So from 1 mole propane, 3 moles of carbon dioxide and 4 moles of water were obtained after complete combustion.
b)
Interpretation:
Heat of combustion of propane must be converted from kJ/mol unit to kJ/g unit.
Concept Introduction:
Molar mass of propane (C3H8) is 44 g/mol.
Heat of combustion in kJ/g
b)

Answer to Problem SII4RE
Heat of combustion of propane is -50.45 kJ/g.
Explanation of Solution
Heat of combustion of propane is given as -2220 kJ/mol.
To convert this to kJ/g unit, the energy value must be divided by the molar mass of propane which is 44 g/mol.
Heat of combustion in kJ/g
c)
Interpretation:
Whether heat of combustion of propane in kJ/g is greater than that of methane must be explained. Also, whether heat of combustion of propane in kJ/mol is greater than that of methane must be explained.
Concept Introduction:
Heat of combustion is the heat energy released when 1 mol of fuel is combusted with oxygen completely. It can be expressed generally in kJ/mol or in kJ/g unit.
c)

Answer to Problem SII4RE
Heat of combustion of propane is lesser than that of methane in kJ/g unit.
Heat of combustion of propane is greater than that of methane in kJ/ mol unit.
Explanation of Solution
Heat of combustion of propane is given as -2220 kJ/mol.
To convert this to kJ/g unit, the energy value must be divided by the molar mass of propane which is 44 g/mol.
Heat of combustion in kJ/g
Heat of combustion of methane is given as -889 kJ/mol.
To convert this to kJ/g unit, the energy value must be divided by the molar mass of methane which is 16 g/mol.
Heat of combustion in kJ/g
Thus heat of combustion of methane is greater than that of propane in kJ/g unit. But heat of combustion of propane is greater than that of methane in kJ/mol unit.
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