
Interpretation: The position of platinum in the activity series is to be determined.
Concept Introduction: Some metals are more active than others. By combining different metals and metal ions, one can experimentally determine which metals are more active than other metals. This gives an activity series in which metals can be arranged in order of their activity. More active metals are placed at the top of the list and less active ones are at the bottom of the list.

Answer to Problem 6E
In the activity series, platinum can be placed below silver and above gold; that is in between silver and gold.
Explanation of Solution
The activity series gives list of metals which are more active than other metals. Metals on top of the list like potassium, sodium, calcium are more active than those lower on the list such as iron, nickel, copper etc. More active metals at the top of the list will always displace less active metals below.
Since platinum is more active than gold it is surely above gold in the activity series. Platinum is less active than silver, so it has to be below silver in the activity series. Since silver is more active than gold, the metals can be arranged with silver on top, platinum in the middle and gold at the bottom of the series.
Gold atoms are very difficult to oxidize, and gold cations are very easy to reduce. That is why gold is found in pure state. It rarely forms compounds with other atoms. Hence gold is placed at the bottom of the activity series.
Chapter U5 Solutions
Living By Chemistry: First Edition Textbook
Additional Science Textbook Solutions
College Physics: A Strategic Approach (3rd Edition)
Human Physiology: An Integrated Approach (8th Edition)
Cosmic Perspective Fundamentals
Organic Chemistry (8th Edition)
Campbell Biology (11th Edition)
Introductory Chemistry (6th Edition)
- Indicate the substitutes in one place, if they are a diazonio room.arrow_forwardIndicate the product formed in each reaction. If the product exhibits tautomerism, draw the tautomeric structure. a) о + CH3-NH-NH2 CO2C2H5 b) + CoH5-NH-NH2 OC2H5arrow_forwardIndicate the formula of the compound, that is the result of the N- alquilación (nucleofílic substitution), in which an additional lateral chain was formed (NH-CH2-COOMe). F3C. CF3 NH NH2 Br о OMe K2CO3, DABCO, DMFarrow_forward
- Synthesis of 1-metilbenzotriazole from 1,2-diaminobenceno.arrow_forwardSynthesis of 1-metilbenzotriazole.arrow_forwardIndicate the formula of the compound, that is the result of the N- alquilación (nucleofílic substitution), in which an additional lateral chain was formed (NH-CH2-COOMe). F3C. CF3 NH NH2 Br о OMe K2CO3, DABCO, DMFarrow_forward
- Identify the mechanism through which the following reaction will proceed and draw the major product. Part 1 of 2 Br KOH EtOH Through which mechanism will the reaction proceed? Select the single best answer. E1 E2 neither Part: 1/2 Part 2 of 2 Draw the major product formed as a result of the reaction. Click and drag to start drawing a structure. Xarrow_forwardWhat is single-point calibration? Provide an example.arrow_forwardDraw the major product formed via an E1 pathway.arrow_forward
- Part 9 of 9 Consider the products for the reaction. Identify the major and minor products. HO Cl The E stereoisomer is the major product and the Z stereoisomer is the minor product ▼ S major product minor productarrow_forwardConsider the reactants below. Answer the following questions about the reaction mechanism and products. HO Clarrow_forwardjulietteyep@gmail.com X YSCU Grades for Juliette L Turner: Orc X 199 A ALEKS - Juliette Turner - Modul X A ALEKS - Juliette Turner - Modul x G butane newman projection - Gox + www-awa.aleks.com/alekscgi/x/Isl.exe/10_u-IgNslkr7j8P3jH-IBxzaplnN4HsoQggFsejpgqKoyrQrB2dKVAN-BcZvcye0LYa6eXZ8d4vVr8Nc1GZqko5mtw-d1MkNcNzzwZsLf2Tu9_V817y?10Bw7QYjlb il Scribbr citation APA SCU email Student Portal | Main Ryker-Learning WCU-PHARM D MySCU YSCU Canvas- SCU Module 4: Homework (Ch 9-10) Question 28 of 30 (1 point) | Question Attempt: 1 of Unlimited H₂SO heat OH The mechanism of this reaction involves two carbocation intermediates, A and B. Part 1 of 2 KHSO 4 rearrangement A heat B H₂O 2 OH Draw the structure of A. Check Search #t m Save For Later Juliet Submit Assignm 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





