
Concept explainers
Interpretation:
The unbranched 1-alkene that will be liquid at room temperature has to be chosen from the given set of options.
Concept Introduction:
Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.
Alkenes and cycloalkenes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkenes and cycloalkenes do not get solubilized in water. In other words, alkenes and cycloalkenes are insoluble in water.
Regarding density, alkenes and cycloalkenes have density lower than water. When alkenes and cycloalkenes are mixed with water, two layers are formed which is a result of insolubility. Alkenes and cycloalkenes are present on top of water layer which is due to lesser density.
Boiling point of alkenes and cycloalkenes increase with an increase in carbon‑chain length or the ring size. The continuous chain alkenes which contain two to four carbon atoms are gases at room temperature. The continuous chain alkenes that contain five to seventeen carbon atoms and one double bond are liquids at room temperature.
When branching happens in the carbon chain, it lowers the boiling point of alkenes. In simple words, unbranched alkenes have more boiling point than branched alkenes with the same number of carbon atoms.
Cycloalkenes have more boiling point compared to noncyclic alkenes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropene and cyclobutene are relatively unstable compound and gets converted into other hydrocarbons.

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Chapter 2 Solutions
Organic And Biological Chemistry
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- H R Part: 1/2 :CI: is a/an electrophile Part 2 of 2 Draw the skeletal structure of the product(s) for the Lewis acid-base reaction. Include lone pairs and formal charges (if applicable) on the structures. 4-7: H ö- H Skip Part Check X :C1: $ % L Fi Click and drag to start drawing a structure. MacBook Pro & ㅁ x G 0: P Add or increase positive formal cha Save For Later Submit ©2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Centearrow_forwardDraw the friedel-crafts acylation mechanism of m-Xylenearrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
- 1. Base on this experimental results, how do you know that the product which you are turning in is methyl 3-nitrobenzoate(meta substituted product ) rather than either of the other two products? 2. What observation suggests that at least a small amount of one or both of the other two isomers are in the mother liquor?arrow_forwardExplain Huckel's rule.arrow_forwardhere is my question can u help me please!arrow_forward
- Organic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning

