Organic And Biological Chemistry
Organic And Biological Chemistry
7th Edition
ISBN: 9781305081079
Author: STOKER, H. Stephen (howard Stephen)
Publisher: Cengage Learning,
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Chapter 2, Problem 2.12EP

(a)

Interpretation Introduction

Interpretation:

The given molecular formula belongs to alkene with one double bond, or a cycloalkene with one double bond has to be indicated.

Concept Introduction:

Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms.  Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements.  The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.

Hydrocarbons are further classified into two categories.  They are saturated hydrocarbons and unsaturated hydrocarbons.  The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon.  The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.

Saturated hydrocarbons are alkanes.  Unsaturated hydrocarbons are alkene, alkyne and aromatic hydrocarbons.

Alkane has general molecular formula as CnH2n+2.  Alkene in which one double is present has general molecular formula as CnH2n.  Alkyne in which one triple bond is present has the general molecular formula as CnH2n-2.  Cycloalkanes have the general molecular formula as CnH2n.  Cycloalkenes in which one double bond is present have the general molecular formula as CnH2n-2.

(a)

Expert Solution
Check Mark

Answer to Problem 2.12EP

Given molecular formula belongs to an alkene with one double bond.

Explanation of Solution

Given molecular formula is C4H8.  Considering the general molecular formula the value of “n” is 4.  The total number of hydrogen atoms present in the given molecular formula is 8.  This is twice the number of carbon atoms.  Hence, the general molecular formula of the given compound can be deduced as CnH2n.  This is a general molecular formula of alkene with one double bond.

Conclusion

The given molecular formula is found to be that for an alkene containing one double bond.

(b)

Interpretation Introduction

Interpretation:

The given molecular formula belongs to alkene with one double bond, or a cycloalkene with one double bond has to be indicated.

Concept Introduction:

Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms.  Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements.  The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.

Hydrocarbons are further classified into two categories.  They are saturated hydrocarbons and unsaturated hydrocarbons.  The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon.  The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.

Saturated hydrocarbons are alkanes.  Unsaturated hydrocarbons are alkene, alkyne and aromatic hydrocarbons.

Alkane has general molecular formula as CnH2n+2.  Alkene in which one double is present has general molecular formula as CnH2n.  Alkyne in which one triple bond is present has the general molecular formula as CnH2n-2.  Cycloalkanes have the general molecular formula as CnH2n.  Cycloalkenes in which one double bond is present have the general molecular formula as CnH2n-2.

(b)

Expert Solution
Check Mark

Answer to Problem 2.12EP

Given molecular formula belongs to a cycloalkene with one double bond.

Explanation of Solution

Given molecular formula is C5H8.  Considering the general molecular formula the value of “n” is 5.  The total number of hydrogen atoms present in the given molecular formula is 8.  This is two numbers less than the twice number of carbon atoms.  Hence, the general molecular formula of the given compound can be deduced as CnH2n-2.  This is a general molecular formula of cycloalkene with one double bond.

Conclusion

The given molecular formula is found to be that for a cycloalkene containing one double bond.

(c)

Interpretation Introduction

Interpretation:

The given molecular formula belongs to alkene with one double bond, or a cycloalkene with one double bond has to be indicated.

Concept Introduction:

Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms.  Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements.  The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.

Hydrocarbons are further classified into two categories.  They are saturated hydrocarbons and unsaturated hydrocarbons.  The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon.  The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.

Saturated hydrocarbons are alkanes.  Unsaturated hydrocarbons are alkene, alkyne and aromatic hydrocarbons.

Alkane has general molecular formula as CnH2n+2.  Alkene in which one double is present has general molecular formula as CnH2n.  Alkyne in which one triple bond is present has the general molecular formula as CnH2n-2.  Cycloalkanes have the general molecular formula as CnH2n.  Cycloalkenes in which one double bond is present have the general molecular formula as CnH2n-2.

(c)

Expert Solution
Check Mark

Answer to Problem 2.12EP

Given molecular formula belongs to a cycloalkene with one double bond.

Explanation of Solution

Given molecular formula is C6H10.  Considering the general molecular formula the value of “n” is 6.  The total number of hydrogen atoms present in the given molecular formula is 10.  This is two numbers less than the twice number of carbon atoms.  Hence, the general molecular formula of the given compound can be deduced as CnH2n-2.  This is a general molecular formula of cycloalkene with one double bond.

Conclusion

The given molecular formula is found to be that for a cycloalkene containing one double bond.

(d)

Interpretation Introduction

Interpretation:

The given molecular formula belongs to alkene with one double bond, or a cycloalkene with one double bond has to be indicated.

Concept Introduction:

Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms.  Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements.  The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.

Hydrocarbons are further classified into two categories.  They are saturated hydrocarbons and unsaturated hydrocarbons.  The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon.  The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.

Saturated hydrocarbons are alkanes.  Unsaturated hydrocarbons are alkene, alkyne and aromatic hydrocarbons.

Alkane has general molecular formula as CnH2n+2.  Alkene in which one double is present has general molecular formula as CnH2n.  Alkyne in which one triple bond is present has the general molecular formula as CnH2n-2.  Cycloalkanes have the general molecular formula as CnH2n.  Cycloalkenes in which one double bond is present have the general molecular formula as CnH2n-2.

(d)

Expert Solution
Check Mark

Answer to Problem 2.12EP

Given molecular formula belongs to an alkene with one double bond.

Explanation of Solution

Given molecular formula is C5H10.  Considering the general molecular formula the value of “n” is 5.  The total number of hydrogen atoms present in the given molecular formula is 10.  This is twice the number of carbon atoms.  Hence, the general molecular formula of the given compound can be deduced as CnH2n.  This is a general molecular formula of alkene with one double bond.

Conclusion

The given molecular formula is found to be that for an alkene containing one double bond.

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The most common frequency in organic chemistry is the Select one: Oa. carbon-oxygen single bond Ob. None of the above Oc. carbon-carbon double bond Od. carbon-carbon single bond
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Chapter 2 Solutions

Organic And Biological Chemistry

Ch. 2.3 - Prob. 4QQCh. 2.4 - Prob. 1QQCh. 2.4 - Prob. 2QQCh. 2.5 - Prob. 1QQCh. 2.5 - Prob. 2QQCh. 2.5 - Prob. 3QQCh. 2.6 - Prob. 1QQCh. 2.6 - Prob. 2QQCh. 2.6 - Prob. 3QQCh. 2.7 - Prob. 1QQCh. 2.7 - Prob. 2QQCh. 2.7 - Prob. 3QQCh. 2.8 - Prob. 1QQCh. 2.8 - Prob. 2QQCh. 2.9 - Prob. 1QQCh. 2.9 - Prob. 2QQCh. 2.10 - Prob. 1QQCh. 2.10 - Prob. 2QQCh. 2.10 - Prob. 3QQCh. 2.10 - Prob. 4QQCh. 2.10 - Prob. 5QQCh. 2.11 - Prob. 1QQCh. 2.11 - Prob. 2QQCh. 2.11 - Prob. 3QQCh. 2.11 - Prob. 4QQCh. 2.11 - Prob. 5QQCh. 2.12 - Prob. 1QQCh. 2.12 - Prob. 2QQCh. 2.12 - Prob. 3QQCh. 2.12 - Prob. 4QQCh. 2.12 - Prob. 5QQCh. 2.13 - Prob. 1QQCh. 2.13 - Prob. 2QQCh. 2.13 - Prob. 3QQCh. 2.14 - Prob. 1QQCh. 2.14 - Prob. 2QQCh. 2.14 - Prob. 3QQCh. 2.14 - Prob. 4QQCh. 2.15 - Prob. 1QQCh. 2.15 - Prob. 2QQCh. 2.15 - Prob. 3QQCh. 2.15 - Prob. 4QQCh. 2.16 - Prob. 1QQCh. 2.16 - Prob. 2QQCh. 2 - Classify each of the following hydrocarbons as...Ch. 2 - Prob. 2.2EPCh. 2 - Prob. 2.3EPCh. 2 - Prob. 2.4EPCh. 2 - Prob. 2.5EPCh. 2 - Prob. 2.6EPCh. 2 - Prob. 2.7EPCh. 2 - Characterize the physical properties of saturated...Ch. 2 - Prob. 2.9EPCh. 2 - Prob. 2.10EPCh. 2 - Prob. 2.11EPCh. 2 - Prob. 2.12EPCh. 2 - Prob. 2.13EPCh. 2 - Prob. 2.14EPCh. 2 - What is the name of the spatial arrangement for...Ch. 2 - Prob. 2.16EPCh. 2 - Prob. 2.17EPCh. 2 - Prob. 2.18EPCh. 2 - Draw a condensed structural formula for each of...Ch. 2 - Prob. 2.20EPCh. 2 - The following names are incorrect by IUPAC rules....Ch. 2 - The following names are incorrect by IUPAC rules....Ch. 2 - Prob. 2.23EPCh. 2 - Draw a condensed structural formula for each of...Ch. 2 - Prob. 2.25EPCh. 2 - Classify each of the following compounds as...Ch. 2 - Prob. 2.27EPCh. 2 - How many hydrogen atoms are present in a molecule...Ch. 2 - Draw a line-angle structural formula for each of...Ch. 2 - Draw a line-angle structural formula for each of...Ch. 2 - Prob. 2.31EPCh. 2 - Prob. 2.32EPCh. 2 - Prob. 2.33EPCh. 2 - Prob. 2.34EPCh. 2 - Prob. 2.35EPCh. 2 - Prob. 2.36EPCh. 2 - Prob. 2.37EPCh. 2 - Prob. 2.38EPCh. 2 - For each of the following pairs of alkenes,...Ch. 2 - For each of the following pairs of alkenes,...Ch. 2 - Prob. 2.41EPCh. 2 - Prob. 2.42EPCh. 2 - Prob. 2.43EPCh. 2 - Prob. 2.44EPCh. 2 - Prob. 2.45EPCh. 2 - Prob. 2.46EPCh. 2 - For each molecule, indicate whether cistrans...Ch. 2 - Prob. 2.48EPCh. 2 - Prob. 2.49EPCh. 2 - Prob. 2.50EPCh. 2 - Draw a structural formula for each of the...Ch. 2 - Prob. 2.52EPCh. 2 - Prob. 2.53EPCh. 2 - For each of the following molecules, indicate...Ch. 2 - Prob. 2.55EPCh. 2 - Prob. 2.56EPCh. 2 - Prob. 2.57EPCh. 2 - Prob. 2.58EPCh. 2 - Prob. 2.59EPCh. 2 - How many isoprene units are present in a....Ch. 2 - Prob. 2.61EPCh. 2 - Indicate whether each of the following statements...Ch. 2 - Prob. 2.63EPCh. 2 - Prob. 2.64EPCh. 2 - Prob. 2.65EPCh. 2 - Prob. 2.66EPCh. 2 - Prob. 2.67EPCh. 2 - Prob. 2.68EPCh. 2 - Prob. 2.69EPCh. 2 - Prob. 2.70EPCh. 2 - Prob. 2.71EPCh. 2 - Prob. 2.72EPCh. 2 - Prob. 2.73EPCh. 2 - Prob. 2.74EPCh. 2 - Prob. 2.75EPCh. 2 - Prob. 2.76EPCh. 2 - Supply the structural formula of the product in...Ch. 2 - Prob. 2.78EPCh. 2 - Prob. 2.79EPCh. 2 - What reactant would you use to prepare each of the...Ch. 2 - Prob. 2.81EPCh. 2 - Prob. 2.82EPCh. 2 - Prob. 2.83EPCh. 2 - Prob. 2.84EPCh. 2 - Prob. 2.85EPCh. 2 - Prob. 2.86EPCh. 2 - Prob. 2.87EPCh. 2 - Prob. 2.88EPCh. 2 - Prob. 2.89EPCh. 2 - Prob. 2.90EPCh. 2 - Prob. 2.91EPCh. 2 - Prob. 2.92EPCh. 2 - Prob. 2.93EPCh. 2 - Prob. 2.94EPCh. 2 - Prob. 2.95EPCh. 2 - Prob. 2.96EPCh. 2 - Prob. 2.97EPCh. 2 - Prob. 2.98EPCh. 2 - Prob. 2.99EPCh. 2 - Prob. 2.100EPCh. 2 - Prob. 2.101EPCh. 2 - Prob. 2.102EPCh. 2 - Prob. 2.103EPCh. 2 - Prob. 2.104EPCh. 2 - Prob. 2.105EPCh. 2 - Prob. 2.106EPCh. 2 - Prob. 2.107EPCh. 2 - Prob. 2.108EPCh. 2 - Assign each of the compounds in Problem 13-107 an...Ch. 2 - Assign each of the compounds in Problem 13-108 an...Ch. 2 - Prob. 2.111EPCh. 2 - Prob. 2.112EPCh. 2 - Prob. 2.113EPCh. 2 - Prob. 2.114EPCh. 2 - Prob. 2.115EPCh. 2 - Prob. 2.116EPCh. 2 - Prob. 2.117EPCh. 2 - Prob. 2.118EPCh. 2 - Prob. 2.119EPCh. 2 - Prob. 2.120EPCh. 2 - Prob. 2.121EPCh. 2 - Prob. 2.122EPCh. 2 - Prob. 2.123EPCh. 2 - Prob. 2.124EPCh. 2 - Prob. 2.125EPCh. 2 - Prob. 2.126EPCh. 2 - Prob. 2.127EPCh. 2 - Prob. 2.128EPCh. 2 - Prob. 2.129EPCh. 2 - Prob. 2.130EP
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