Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133128741
Author: Serope Kalpakjian, Steven Schmid
Publisher: Prentice Hall
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Chapter 21, Problem 37QLP
You will note that the values of a and b in Eq. (21.24) are higher for high-speed steels than for carbides. Why is this so?
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A number of through holes with 10-mm-diameter have been drilled through 30-mm thick cast iron plate. At a
cutting speed of 25 m/min, the high-speed steel drill tool lasted for 44 holes. But, when the cutting speed
increased to 35 m/min, the drill tool lasted for only five holes. The feed used in the both cases is 0.08 mm/rev.
Determine the values of n and Cin the Taylor tool life equation for the data, where cutting speed v is expressed
in m/min, and tool life T is expressed in min.
Tool life tests in turning yield the following data: (1) v = 100 m/min, T = 10 min; (2) v = 75 m/min, T = 30 min. (a) Determine the n and C values in the Taylor tool life equation. Based on your equation, compute (b) the tool life for a speed of 90 m/min, and (c) the speed corresponding to a tool life of 20 min
2 2 . 13 Explain the difference between M-series and T-series high-speed steels.
Chapter 21 Solutions
Manufacturing Engineering & Technology
Ch. 21 - Explain why continuous chips are not necessarily...Ch. 21 - Name the factors that contribute to the formation...Ch. 21 - What is the cutting ratio? Is it always less than...Ch. 21 - Explain the difference between positive and...Ch. 21 - Explain how a dull tool can lead to negative rake...Ch. 21 - Comment on the role and importance relief angle.Ch. 21 - Explain the difference between discontinuous chips...Ch. 21 - Why should we be interested in the magnitude of...Ch. 21 - What are the differences between orthogonal and...Ch. 21 - What is a BUE? Why does it form?
Ch. 21 - Is there any advantage to having a built-up edge...Ch. 21 - What is the function of chip breakers? How do they...Ch. 21 - Identify the forces involved in a cutting...Ch. 21 - Explain the characteristics of different types of...Ch. 21 - List the factors that contribute to poor surface...Ch. 21 - Explain what is meant by the term machinability...Ch. 21 - What is shaving in machining? When would it be...Ch. 21 - List reasons that machining operations may be...Ch. 21 - Are the locations of maximum temperature and...Ch. 21 - Is material ductility important for machinability?...Ch. 21 - Explain why studying the types of chips produced...Ch. 21 - Prob. 22QLPCh. 21 - Tool life can be almost infinite at low cutting...Ch. 21 - Explain the consequences of allowing temperatures...Ch. 21 - The cutting force increases with the depth of cut...Ch. 21 - Why is it not always advisable to increase the...Ch. 21 - What are the consequences if a cutting tool chips?Ch. 21 - What are the effects of performing a cutting...Ch. 21 - Prob. 29QLPCh. 21 - Prob. 30QLPCh. 21 - Prob. 31QLPCh. 21 - Prob. 32QLPCh. 21 - Comment on your observations regarding Figs. 21.1...Ch. 21 - Prob. 34QLPCh. 21 - Comment on your observations regarding the...Ch. 21 - Why does the temperature in cutting depend on the...Ch. 21 - You will note that the values of a and b in Eq....Ch. 21 - Prob. 38QLPCh. 21 - Prob. 39QLPCh. 21 - Explain whether it is desirable to have a high or...Ch. 21 - The Taylor tool-life equation is directly...Ch. 21 - Prob. 42QLPCh. 21 - Why are tool temperatures low at low cutting...Ch. 21 - Can high-speed machining be performed without the...Ch. 21 - Prob. 45QLPCh. 21 - Prob. 46QLPCh. 21 - State whether or not the following statements are...Ch. 21 - Let n = 0.5 and C = 400 in the Taylor equation for...Ch. 21 - Assume that, in orthogonal cutting, the rake angle...Ch. 21 - Prob. 50QTPCh. 21 - Prob. 51QTPCh. 21 - Using trigonometric relationships, derive an...Ch. 21 - An orthogonal cutting operation is being carried...Ch. 21 - Prob. 54QTPCh. 21 - Prob. 55QTPCh. 21 - Prob. 56QTPCh. 21 - Show that, for the same shear angle, there are two...Ch. 21 - With appropriate diagrams, show how the use of a...Ch. 21 - In a cutting operation using a 5 rake angle, the...Ch. 21 - For a turning operation using a ceramic cutting...Ch. 21 - In Example 21.3, if the cutting speed V is...Ch. 21 - Using Eq. (21.30), select an appropriate feed for...Ch. 21 - With a carbide tool, the temperature in a cutting...Ch. 21 - The following flank wear data were collected in a...Ch. 21 - The following data are available from orthogonal...Ch. 21 - Prob. 66QTPCh. 21 - Design an experimental setup whereby orthogonal...Ch. 21 - Describe your thoughts on whether chips produced...Ch. 21 - Recall that cutting tools can be designed so that...Ch. 21 - Recall that the chip-formation mechanism also can...Ch. 21 - Prob. 73SDPCh. 21 - Describe your thoughts regarding the recycling of...Ch. 21 - List products that can be directly produced from...Ch. 21 - Obtain a wood planer and some wood specimens. Show...Ch. 21 - It has been noted that the chips from certain...Ch. 21 - As we have seen, chips carry away the majority of...
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- A 150-mm-long, 10-mm-diameter, high-strength cast iron rod is being reduced in diameter to 8 mm by turning on a lathe. The spindle rotates at N = 500 rpm., and the tool is traveling at an axial speed of 200 mm/min.arrow_forward21.37 You will note that the values of a and b in Eq. (21.24) are higher for high-speed steels than for carbides. Why is this so?arrow_forwardDuring turning tests, using a cemented carbide tool resulted in a 1‑min tool life at a cutting speed = 4.8 m/s and a 22‑min tool life at a speed = 2.0 m/s. (a) Find the n and Carrow_forward
- A 200 mm long magnesium alloy bar, 63 mm in diameter is turned on a lathe using a high speed steel cutter travelling at 180 mm/min. The spindle rotates at 450 rpm and lathe is equipped with a 10 kW motor, operating at a mechanical efficiency of 92%. The final diameter of the magnesium alloy bar is 59,5 mm. Indicate with a sketch the recommend size and location of the following tool angles: back rake, side rake, end relief, side relief and side and end cutting edge. Calculate the cutting time for the machining process.Calculate the required cutting force.arrow_forwardA turning operation is performed on C1008 steel (a ductile steel) using a tool with a nose radius= 1.3 mm. Cutting speed = 61 m/min and feed = 0.27 mm/rev. Compute an estimate of the surface roughness in this operation. (Hint: the ratio of actual to ideal roughness can be read on the figure below) Equations used; Ra Ri Actual Ratio Theoretical 32NR = rai Ri 2.4 2.2 2.0 1.8 1.6 1.4 1.2 1.0 0 Ductile metals Cast irons Free machining alloys. 100 30.5 200 Cutting speed-ft/min 61 Cutting speed - m/min 300 91.5 400 122arrow_forwardanswer quicklyarrow_forward
- A student is using a lathe with 80-hp and 80% efficiency to fabricate a copper alloy with Sy = 1200ksi If the width of cut is 0.30 inand the student set a rake angle of 0and a cutting speed of 200fl / min while she assumed a coefficient of friction to be 0.5. What is the maximum depth of cut the student can achieve?arrow_forwardExample 3.18 A low carbon steel bar of 147 mm diameter with length of 630 mm is being turned with uncoated carbide insert. The observed tool life are 24 and 12 for cutting velocities of 90 m/min and 120 m/min respectively. The feed and depth of cut are 0.2 mm./rev and 2 mm respectively. Use the unmachined to calculate the cutting velocity (i) When tool life is 20 min. the cutting velocity in m/min is (a) 87 (b) 97 (c) 107 (d) 114 (ii) Neglect over travel or approach of the tool. When tool life is 20 min, the machining time in remain for a single pass is (a) 5 (b) 10 (c) 15 (d) 20arrow_forwardA student is using a lathe with 80-hp and 80% efficiency to fabricate a copper alloy with Sy= 1200 ksi. If the width of cut is 0.30 in. and the student set a rake angle of 0° and a cutting speed of 200 ft/ min while she assumed a coefficient of friction to be 0.5. What is the maximum depth of cut the student can achieve?arrow_forward
- Using the power-angle characteristic illustrate the Critical Clearing Angle (CCA) for three different values of inertia, H, and comment on your findings. That is, how does the inertia impact on the CCA?arrow_forwardParvinbhaiarrow_forwardThe outside diameter of a cylinder made of steel is to be turned. The starting diameter is 120 mm and the length is 1400 mm. The feed is 0.3 mm/rev and the depth of cut is 2.5mm. The cut will be made with a cemented carbide cutting tool whose Taylor tool life parameters are: n= 0.33 and C=500. Units for the Taylor equation are min for tool life and m/min for cutting speed. Compute the cutting speed that will allow the tool life to be just equal to the cutting time required to complete this turning operation.arrow_forward
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