Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133128741
Author: Serope Kalpakjian, Steven Schmid
Publisher: Prentice Hall
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Chapter 21, Problem 38QLP
To determine
As shown in Fig. 21.14, the percentage of the total cutting energy carried away by the chip increases with increasing cutting speed. Why?
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Determine ratio of friction energy to total energy
44. In Orthogonal Cutting Model, why chip thickness after cut is greater than chip thickness before cut? explain.
(b) An orthogonal cutting operation is being carried out under the following conditions:
depth of cut, to = 0.1 mm, chip thickness, to = 0.2 mm, width of cut = 4 mm, cutting
speed, v = 3 m/s, rake angle, a = 10°, Cutting force, Fc = 500 N, and Thrust force, F1=
200 N. Calculate the percentage of the total energy that is dissipated in the shear plane
of cutting process.
Chapter 21 Solutions
Manufacturing Engineering & Technology
Ch. 21 - Explain why continuous chips are not necessarily...Ch. 21 - Name the factors that contribute to the formation...Ch. 21 - What is the cutting ratio? Is it always less than...Ch. 21 - Explain the difference between positive and...Ch. 21 - Explain how a dull tool can lead to negative rake...Ch. 21 - Comment on the role and importance relief angle.Ch. 21 - Explain the difference between discontinuous chips...Ch. 21 - Why should we be interested in the magnitude of...Ch. 21 - What are the differences between orthogonal and...Ch. 21 - What is a BUE? Why does it form?
Ch. 21 - Is there any advantage to having a built-up edge...Ch. 21 - What is the function of chip breakers? How do they...Ch. 21 - Identify the forces involved in a cutting...Ch. 21 - Explain the characteristics of different types of...Ch. 21 - List the factors that contribute to poor surface...Ch. 21 - Explain what is meant by the term machinability...Ch. 21 - What is shaving in machining? When would it be...Ch. 21 - List reasons that machining operations may be...Ch. 21 - Are the locations of maximum temperature and...Ch. 21 - Is material ductility important for machinability?...Ch. 21 - Explain why studying the types of chips produced...Ch. 21 - Prob. 22QLPCh. 21 - Tool life can be almost infinite at low cutting...Ch. 21 - Explain the consequences of allowing temperatures...Ch. 21 - The cutting force increases with the depth of cut...Ch. 21 - Why is it not always advisable to increase the...Ch. 21 - What are the consequences if a cutting tool chips?Ch. 21 - What are the effects of performing a cutting...Ch. 21 - Prob. 29QLPCh. 21 - Prob. 30QLPCh. 21 - Prob. 31QLPCh. 21 - Prob. 32QLPCh. 21 - Comment on your observations regarding Figs. 21.1...Ch. 21 - Prob. 34QLPCh. 21 - Comment on your observations regarding the...Ch. 21 - Why does the temperature in cutting depend on the...Ch. 21 - You will note that the values of a and b in Eq....Ch. 21 - Prob. 38QLPCh. 21 - Prob. 39QLPCh. 21 - Explain whether it is desirable to have a high or...Ch. 21 - The Taylor tool-life equation is directly...Ch. 21 - Prob. 42QLPCh. 21 - Why are tool temperatures low at low cutting...Ch. 21 - Can high-speed machining be performed without the...Ch. 21 - Prob. 45QLPCh. 21 - Prob. 46QLPCh. 21 - State whether or not the following statements are...Ch. 21 - Let n = 0.5 and C = 400 in the Taylor equation for...Ch. 21 - Assume that, in orthogonal cutting, the rake angle...Ch. 21 - Prob. 50QTPCh. 21 - Prob. 51QTPCh. 21 - Using trigonometric relationships, derive an...Ch. 21 - An orthogonal cutting operation is being carried...Ch. 21 - Prob. 54QTPCh. 21 - Prob. 55QTPCh. 21 - Prob. 56QTPCh. 21 - Show that, for the same shear angle, there are two...Ch. 21 - With appropriate diagrams, show how the use of a...Ch. 21 - In a cutting operation using a 5 rake angle, the...Ch. 21 - For a turning operation using a ceramic cutting...Ch. 21 - In Example 21.3, if the cutting speed V is...Ch. 21 - Using Eq. (21.30), select an appropriate feed for...Ch. 21 - With a carbide tool, the temperature in a cutting...Ch. 21 - The following flank wear data were collected in a...Ch. 21 - The following data are available from orthogonal...Ch. 21 - Prob. 66QTPCh. 21 - Design an experimental setup whereby orthogonal...Ch. 21 - Describe your thoughts on whether chips produced...Ch. 21 - Recall that cutting tools can be designed so that...Ch. 21 - Recall that the chip-formation mechanism also can...Ch. 21 - Prob. 73SDPCh. 21 - Describe your thoughts regarding the recycling of...Ch. 21 - List products that can be directly produced from...Ch. 21 - Obtain a wood planer and some wood specimens. Show...Ch. 21 - It has been noted that the chips from certain...Ch. 21 - As we have seen, chips carry away the majority of...
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- 2 1.46 Explain why the power requirements in cutting depend on the cutting force but not the thrust force.arrow_forwardI need the answer as soon as possiblearrow_forwardAn orthogonal cutting operations is being carried out in which uncut thickness is 0.010 mm, cutting speed is 130 m/min, rake angle is 15° and width of cut is 6 mm. It is observed that the chip thickness is 0.015 mm, the cutting force is 60 N and the thrust force is 25 N. The ratio of friction energy to total energy is (correct to twoarrow_forward
- A turning operation is carried out on aluminum. Based on the specific energy values in the table in your text, determine material removal rate and cutting power in the operation under the following sets of conditions: (a) Cutting speed = 5.6 m/s, feed = 0.25 mm/rev, and depth of cut = 2.0 mm; and (b) cutting speed = 1.3 m/s, feed = 0.75 mm/rev, and depth of cut = 4.0 mm.arrow_forwardDraw the geometry of single point cutting tool (3 views) and explain the importance of each angle in metal cutting.arrow_forwardAssume that, in orthogonal cutting, the rake angle, oz,is 20° and the friction angle, B, is 35° at the chip-tool interface.Determine the percentage change in chip thickness when the friction angle is 50°. (Note: do not use Eq. (21.3)arrow_forward
- 3. Draw the forces and angles involved in the cutting process and calculate shear angle (0), friction coefficient and tangential force if .cutting force 80 kN, resultant of forces 100KN, friction force-75KN, rake angle =20° undeformed chip thickness %3D 0.65mm and deformed chip thickness 0.72mm. %3Darrow_forward2 1.23 Tool life can be almost infinite at low cutting speeds.Would you then recommend that all machining be done at low speeds? Explain.arrow_forwardQuestion 1: Explain the following terms and situations in metal cutting. Give enough explanation with figures if it is necessary. a) Up and down milling operations. What are the effects on the workpiece surface finish and machine tool? b) Orthogonal and oblique cutting. c) Cutting force diagram in orthogonal cutting. d) Theoretical prediction of shear angle in orthogonal cutting. e) Machinability. f) Force and chatter vibrations. How can you detect the vibration during the machining? How can you decide which type of the vibration you have? g) Mode shapes. Mode coupling. h) Process damping. Which parameters can affect the process damping? i) j) Regenerative chatter vibrations. k) Stability lobes. Question 2: How will the cutting force be affected by the following situations during the machining operation? Why? a) Large rake angle b) Small relief angle c) Large nose radius d) Sharp cutting edge e) Smooth rake face f) Hard workpiece material g) High cutting speed h) Large feed rate i)…arrow_forward
- Assume that in orthogonal cutting the rake angle is 15o and the coefficient of friction is 0.15. Using Eq. 8.20, determine the percentage increase in chip thickness when the coefficient of friction is doubled.arrow_forwardIn an orthogonal cutting operation an 8 mm deep groove is to be turned on a 50 mm diameter steel bar. Spindle speed is 300 rpm and a feed rate of 0.25 mm/rev is given to the tool. Produced chips have a width of 2 mm. Calculate the material removal rate at the beginning and at the end of the cut. Can u help me please?arrow_forwardAssume that, in orthogonal cutting, the rake angle is 20 and the friction angle is 35 at thechip-tool interface. Determine the percentage change in chip thickness when the frictionangle is 50. Note that Merchant’s equation is more preferable.arrow_forward
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