(a)
To calculate: The probability distribution for Y in a table.
The probability distribution for Y in a table is:
Y | 1 | 2 | 3 | 4 | 5 |
P(Y) | 0.25 | 0.15 | 0.35 | 0.20 | 0.05 |
Given information:
The bag contains 20 number of balls.
5 balls are numbered 1.
3 balls are numbered 2.
7 balls are numbered 3.
4 balls are numbered 4.
1 ball are numbered 5.
Formula used:
Here, E is the favourable outcomes and S is the total possible outcomes.
Calculation:
Let Y= number on a ball chosen at random from the bag.
5 balls are numbered 1.
Substitute 5 for
3 balls are numbered 2.
Substitute 3 for
7 balls are numbered 3.
Substitute 7 for
4 balls are numbered 4.
Substitute 4 for
1 ball are numbered 5.
Substitute 1 for
Let us combine the probabilities in table.
Y | 1 | 2 | 3 | 4 | 5 |
P(Y) | 0.25 | 0.15 | 0.35 | 0.20 | 0.05 |
(b)
To calculate: The expected value for Y.
The expected value for Y.is 2.65.
Given information:
The bag contains 20 number of balls.
5 balls are numbered 1.
3 balls are numbered 2.
7 balls are numbered 3.
4 balls are numbered 4.
1 ball are numbered 5.
Formula used:
Here, E is the favourable outcomes and S is the total possible outcomes.
Calculation:
Let Y= number on a ball chosen at random from the bag.
5 balls are numbered 1.
Substitute 5 for
3 balls are numbered 2.
Substitute 3 for
7 balls are numbered 3.
Substitute 7 for
4 balls are numbered 4.
Substitute 4 for
1 ball are numbered 5.
Substitute 1 for
Now,
The expected value (or mean) is the sum of the product of each possibility x with its probability P ( x ):
Substitute
Hence, the expected value for Y.is 2.65.
Chapter 10 Solutions
PRECALCULUS:GRAPHICAL,...-NASTA ED.
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