PRECALCULUS:GRAPHICAL,...-NASTA ED.
10th Edition
ISBN: 9780134672090
Author: Demana
Publisher: PEARSON
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Expert Solution & Answer
Chapter 10, Problem 17RE
Solution
a.
To Plot: The stemplot of the data using split stems.
The stemplot is :
| Stem | Leaf |
| 2 | 2 |
| 3 | 3 7 7 |
| 4 | 0 1 1 1 2 2 3 5 5 6 7 7 |
| 5 | 4 |
Given:
The passing yardage of Peyton Manning for 13 seasons as Colt and 4 as a Bronco.
| Year | Yard |
| 1998 | 3739 |
| 1999 | 4135 |
| 2000 | 3313 |
| 2001 | 4131 |
| 2002 | 4200 |
| 2003 | 4267 |
| 2004 | 4557 |
| 2005 | 3747 |
| 2006 | 4397 |
| 2007 | 4040 |
| 2008 | 4002 |
| 2009 | 4500 |
| 2010 | 4700 |
| 2011 | Injured |
| 2012 | 4659 |
| 2013 | 5477 |
| 2014 | 4727 |
| 2015 | 2249 |
Concept Used:
For visualization, the data is truncated to 100 units. Only the first two digits of each data value is considered to plot the stem-and-leaf diagram, which does not affect the visualization.
Plot:
The data is arranged in ascending order and the first two digits are considered. And the stems are split with intervals of 500.
| Stem | Leaf |
| 2 | 2 |
| 3 | 3 7 7 |
| 4 | 0 1 1 1 2 2 3 5 5 6 7 7 |
| 5 | 4 |
b.
To determine the shape of distribution for the passing yards data.
The data is skewed to left.
Given:
The passage yards data is plotted in stem-and-leaf diagram as
| Stem | Leaf |
| 2 | 2 |
| 3 | 3 7 7 |
| 4 | 0 1 1 1 2 2 3 5 5 6 7 7 |
| 5 | 4 |
Concept Used:
The shape of the distribution through the stem-and-leaf diagram is determined by the spread of the values in Leaf.
Conclusion:
There is a spike at the lower part of the leaf and the tail on the above is elongated more than the lower part. So, it can be said that the data is not symmetric and it is skewed to left.
Chapter 10 Solutions
PRECALCULUS:GRAPHICAL,...-NASTA ED.
Ch. 10.1 - Prob. 1QRCh. 10.1 - Prob. 2QRCh. 10.1 - Prob. 3QRCh. 10.1 - Prob. 4QRCh. 10.1 - Prob. 5QRCh. 10.1 - Prob. 6QRCh. 10.1 - Prob. 7QRCh. 10.1 - Prob. 8QRCh. 10.1 - Prob. 9QRCh. 10.1 - Prob. 10QR
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Prob. 30ECh. 10.2 - Prob. 31ECh. 10.2 - Prob. 32ECh. 10.2 - Prob. 33ECh. 10.2 - Prob. 34ECh. 10.2 - Prob. 35ECh. 10.2 - Prob. 36ECh. 10.2 - Prob. 37ECh. 10.2 - Prob. 38ECh. 10.2 - Prob. 39ECh. 10.2 - Prob. 40ECh. 10.2 - Prob. 41ECh. 10.2 - Prob. 42ECh. 10.2 - Prob. 43ECh. 10.2 - Prob. 44ECh. 10.2 - Prob. 45ECh. 10.2 - Prob. 46ECh. 10.2 - Prob. 47ECh. 10.2 - Prob. 48ECh. 10.3 - Prob. 1QRCh. 10.3 - Prob. 2QRCh. 10.3 - Prob. 3QRCh. 10.3 - Prob. 4QRCh. 10.3 - Prob. 5QRCh. 10.3 - Prob. 6QRCh. 10.3 - Prob. 7QRCh. 10.3 - Prob. 8QRCh. 10.3 - Prob. 9QRCh. 10.3 - Prob. 10QRCh. 10.3 - Prob. 1ECh. 10.3 - Prob. 2ECh. 10.3 - Prob. 3ECh. 10.3 - Prob. 4ECh. 10.3 - Prob. 5ECh. 10.3 - Prob. 6ECh. 10.3 - Prob. 7ECh. 10.3 - Prob. 8ECh. 10.3 - Prob. 9ECh. 10.3 - Prob. 10ECh. 10.3 - Prob. 11ECh. 10.3 - Prob. 12ECh. 10.3 - Prob. 13ECh. 10.3 - Prob. 14ECh. 10.3 - Prob. 15ECh. 10.3 - Prob. 16ECh. 10.3 - Prob. 17ECh. 10.3 - Prob. 18ECh. 10.3 - Prob. 19ECh. 10.3 - Prob. 20ECh. 10.3 - Prob. 21ECh. 10.3 - Prob. 22ECh. 10.3 - 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Prob. 55ECh. 10.4 - Prob. 56ECh. 10.5 - Prob. 1QRCh. 10.5 - Prob. 2QRCh. 10.5 - Prob. 3QRCh. 10.5 - Prob. 4QRCh. 10.5 - Prob. 5QRCh. 10.5 - Prob. 6QRCh. 10.5 - Prob. 7QRCh. 10.5 - Prob. 8QRCh. 10.5 - Prob. 9QRCh. 10.5 - Prob. 10QRCh. 10.5 - Prob. 1ECh. 10.5 - Prob. 2ECh. 10.5 - Prob. 3ECh. 10.5 - Prob. 4ECh. 10.5 - Prob. 5ECh. 10.5 - Prob. 6ECh. 10.5 - Prob. 7ECh. 10.5 - Prob. 8ECh. 10.5 - Prob. 9ECh. 10.5 - Prob. 10ECh. 10.5 - Prob. 11ECh. 10.5 - Prob. 12ECh. 10.5 - Prob. 13ECh. 10.5 - Prob. 14ECh. 10.5 - Prob. 15ECh. 10.5 - Prob. 16ECh. 10.5 - Prob. 17ECh. 10.5 - Prob. 18ECh. 10.5 - Prob. 19ECh. 10.5 - Prob. 20ECh. 10.5 - Prob. 21ECh. 10.5 - Prob. 22ECh. 10.5 - Prob. 23ECh. 10.5 - Prob. 24ECh. 10.5 - Prob. 25ECh. 10.5 - Prob. 26ECh. 10.5 - Prob. 27ECh. 10.5 - Prob. 28ECh. 10.5 - Prob. 29ECh. 10.5 - Prob. 30ECh. 10.5 - Prob. 31ECh. 10.5 - Prob. 32ECh. 10.5 - Prob. 33ECh. 10.5 - Prob. 34ECh. 10.5 - Prob. 35ECh. 10.5 - Prob. 36ECh. 10.5 - Prob. 37ECh. 10.5 - Prob. 38ECh. 10.5 - Prob. 39ECh. 10.5 - 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