a)
To calculate: The probability that exactly there are 3 left-handed students.
The probability is 0.1696.
Given:
The percentage of students who are left-handed (p)
The total number of students in the class
Concept used:
A probability distribution where each trial has two possible outcomes known as a success and failure, each trial is independent and the probability of each trial is the same, then to calculate the probability of a certain number of successes occurring, a binomial probability distribution is used as shown below
where k is the number of successes, n is the number of trials and p is the probability of success.
Calculation:
Consider, X be the random variable that shows the number of students that are left-handed in the class.
The probability that are exactly 3 left-handed out of 15 students in the class is calculated as shown below
The required probability is 0.1696.
Conclusion:
The probability that there are exactly 3 left-handed out of 15 students in the class is 0.1696.
b)
To calculate: The probability that there are no more than 2 of 6 students are left-handed in the class.
The probability is 0.7346.
Calculation:
The probability is calculated as shown below
Conclusion:
The probability that there are no more than 2 out of 15 students are left-handed in the class is about 0.7346 (rounded to 4 decimal places).
Chapter 10 Solutions
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