PRECALCULUS:GRAPHICAL,...-NASTA ED.
PRECALCULUS:GRAPHICAL,...-NASTA ED.
10th Edition
ISBN: 9780134672090
Author: Demana
Publisher: PEARSON
Expert Solution & Answer
Book Icon
Chapter 10.3, Problem 54E
Solution

a)

To find: A set of data where the standard deviation is less than the interquartile range of the data distribution.

The set of data where the standard deviation is less than the interquartile range is shown below

1, 2, 3, 3, 4, 4, 5, 5, 6, 6, 6, 7, 7, 7, 7.

Given:

The collected set of data is 1, 2, 3, 3, 4, 4, 5, 5, 6, 6, 6, 7, 7, 7, 7.

Concept used:

The standard deviation and interquartile range are measures of variability, the standard deviation is nothing but the average deviation of all values with respect to the mean and the interquartile range is the range of the middle 50% values of the data distribution.

The standard deviation is calculated using the formula

  Standard deviation=∑X−X__2n−1

The Interquartile range is the difference between the third Quartile and the first Quartile, where the first quartile divides the data distribution bottom 25% and top 75% of the data and the quartile three divides the data bottom 75% and top 25% of the data.

Calculation:

The mean of the set of data is calculated as shown below

  Mean=∑Xn=1+2+3+3+4+4+5+5+6+6+6+7+7+7+715=7315=4.87

The standard deviation of the set of data is calculated as shown below

  Standard deviation=∑X−X__2n−1=(1−4.87)2+(2−4.87)2+(3−4.87)2+(3−4.87)2+..+(7−4.87)215−1=53.733514=1.959

The standard deviation of the data set is 1.959.

There are a total of 15 data points given in the data distribution arranging them in ascending order, the median of the data distribution is the middle value which is at the 8th position, which is 5.

The first quartile divides the bottom 25% of the data and the top 75% of the data, it is nothing but the middle value of the values of the first half of the data i.e.

1, 2, 3, 3, 4, 4, 5, 5. There are a total of 8 data values and the middle value is the average of data values at 4th and 5th positions.

  Q1First Quartile=3+42=3.5

The first quartile is 3.5.

The third quartile divides the bottom 75% of the data and the top 25% of the data, it is nothing but the middle value of the values of the second half of the data i.e.

5, 6, 6, 6, 7, 7, 7, 7. There are a total of 8 data values and the middle value is the average of data values at 4th and 5th positions.

  Q3Third Quartile=6+72=6.5

The third quartile is 6.5.

The Interquartile range of the set of data is the difference between the third quartile and first quartile and is calculated as shown below

  IQR=Q3−Q1=6.5−3.5=3

Conclusion:

The collected data set 1, 2, 3, 3, 4, 4, 5, 5, 6, 6, 6, 7, 7, 7, 7 satisfy the condition that the interquartile range is more than the standard deviation.

b)

To find: A set of data where the interquartile range is less than the standard deviation of the data distribution.

The set of data where the interquartile range is less than the standard deviation is shown below

1, 2, 3, 3, 4, 4, 5, 5, 6, 6, 6, 7, 7, 10, 15.

Given:

The collected set of data is 1, 2, 3, 3, 4, 4, 5, 5, 6, 6, 6, 7, 7, 10, 15.

Concept used:

The standard deviation and interquartile range are measures of variability, the standard deviation is nothing but the average deviation of all values with respect to the mean and the interquartile range is the range of the middle 50% values of the data distribution.

The standard deviation is calculated using the formula

  Standard deviation=∑X−X__2n−1

The Interquartile range is the difference between the third Quartile and the first Quartile, where the first quartile divides the data distribution bottom 25% and top 75% of the data and the quartile three divides the data bottom 75% and top 25% of the data.

Calculation:

The mean of the set of data is calculated as shown below

  Mean=∑Xn=1+2+3+3+4+4+5+5+6+6+6+7+7+10+1515=8415=5.6

The standard deviation of the set of data is calculated as shown below

  Standard deviation=∑X−X__2n−1=(1−5.6)2+(2−5.6)2+(3−5.6)2+(3−5.6)2+..+(15−5.6)215−1=165.614=3.439

The standard deviation of the data set is 3.439.

There are a total of 15 data points given in the data distribution arranging them in ascending order, the median of the data distribution is the middle value which is at the 8th position, which is 5.

The first quartile divides the bottom 25% of the data and the top 75% of the data, it is nothing but the middle value of the values of the first half of the data i.e.

1, 2, 3, 3, 4, 4, 5, 5. There are a total of 8 data values and the middle value is the average of data values at 4th and 5th positions.

  Q1First Quartile=3+42=3.5

The first quartile is 3.5.

The third quartile divides the bottom 75% of the data and the top 25% of the data, it is nothing but the middle value of the values of the second half of the data i.e.

5, 6, 6, 6, 7, 7, 10, 15. There are a total of 8 data values and the middle value is the average of data values at 4th and 5th positions.

  Q3Third Quartile=6+72=6.5

The third quartile is 6.5.

The Interquartile range of the set of data is the difference between the third quartile and first quartile and is calculated as shown below

  IQR=Q3−Q1=6.5−3.5=3

Conclusion:

The collected data set 1, 2, 3, 3, 4, 4, 5, 5, 6, 6, 6, 7, 7, 10, 15 satisfy the condition that the standard deviation is more than the interquartile range.

Previous
Chapter 10.3, Problem 53E
Next
Chapter 10.3, Problem 55E

Chapter 10 Solutions

PRECALCULUS:GRAPHICAL,...-NASTA ED.

Ch. 10.1 - Prob. 1QRCh. 10.1 - Prob. 2QRCh. 10.1 - Prob. 3QRCh. 10.1 - Prob. 4QRCh. 10.1 - Prob. 5QRCh. 10.1 - Prob. 6QRCh. 10.1 - Prob. 7QRCh. 10.1 - Prob. 8QRCh. 10.1 - Prob. 9QRCh. 10.1 - Prob. 10QR
Ch. 10.1 - Prob. 1ECh. 10.1 - Prob. 2ECh. 10.1 - Prob. 3ECh. 10.1 - Prob. 4ECh. 10.1 - Prob. 5ECh. 10.1 - Prob. 6ECh. 10.1 - Prob. 7ECh. 10.1 - Prob. 8ECh. 10.1 - Prob. 9ECh. 10.1 - Prob. 10ECh. 10.1 - Prob. 11ECh. 10.1 - Prob. 12ECh. 10.1 - Prob. 13ECh. 10.1 - Prob. 14ECh. 10.1 - Prob. 15ECh. 10.1 - Prob. 16ECh. 10.1 - Prob. 17ECh. 10.1 - Prob. 18ECh. 10.1 - Prob. 19ECh. 10.1 - Prob. 20ECh. 10.1 - Prob. 21ECh. 10.1 - Prob. 22ECh. 10.1 - Prob. 23ECh. 10.1 - Prob. 24ECh. 10.1 - Prob. 25ECh. 10.1 - Prob. 26ECh. 10.1 - Prob. 27ECh. 10.1 - Prob. 28ECh. 10.1 - Prob. 29ECh. 10.1 - Prob. 30ECh. 10.1 - Prob. 31ECh. 10.1 - Prob. 32ECh. 10.1 - Prob. 33ECh. 10.1 - Prob. 34ECh. 10.1 - Prob. 35ECh. 10.1 - Prob. 36ECh. 10.1 - Prob. 37ECh. 10.1 - Prob. 38ECh. 10.1 - Prob. 39ECh. 10.1 - Prob. 40ECh. 10.1 - Prob. 41ECh. 10.1 - Prob. 42ECh. 10.1 - Prob. 43ECh. 10.1 - Prob. 44ECh. 10.1 - Prob. 45ECh. 10.1 - Prob. 46ECh. 10.1 - Prob. 47ECh. 10.1 - Prob. 48ECh. 10.1 - Prob. 49ECh. 10.1 - Prob. 50ECh. 10.1 - Prob. 51ECh. 10.1 - Prob. 52ECh. 10.1 - Prob. 53ECh. 10.1 - Prob. 54ECh. 10.1 - Prob. 55ECh. 10.1 - Prob. 56ECh. 10.1 - Prob. 57ECh. 10.1 - Prob. 58ECh. 10.1 - Prob. 59ECh. 10.1 - Prob. 60ECh. 10.1 - Prob. 61ECh. 10.1 - Prob. 62ECh. 10.2 - Prob. 1QRCh. 10.2 - Prob. 2QRCh. 10.2 - Prob. 3QRCh. 10.2 - Prob. 4QRCh. 10.2 - Prob. 5QRCh. 10.2 - Prob. 6QRCh. 10.2 - Prob. 7QRCh. 10.2 - Prob. 8QRCh. 10.2 - Prob. 9QRCh. 10.2 - Prob. 10QRCh. 10.2 - Prob. 1ECh. 10.2 - Prob. 2ECh. 10.2 - Prob. 3ECh. 10.2 - Prob. 4ECh. 10.2 - Prob. 5ECh. 10.2 - Prob. 6ECh. 10.2 - Prob. 7ECh. 10.2 - Prob. 8ECh. 10.2 - Prob. 9ECh. 10.2 - Prob. 10ECh. 10.2 - Prob. 11ECh. 10.2 - Prob. 12ECh. 10.2 - Prob. 13ECh. 10.2 - Prob. 14ECh. 10.2 - Prob. 15ECh. 10.2 - Prob. 16ECh. 10.2 - Prob. 17ECh. 10.2 - Prob. 18ECh. 10.2 - Prob. 19ECh. 10.2 - Prob. 20ECh. 10.2 - Prob. 21ECh. 10.2 - Prob. 22ECh. 10.2 - Prob. 23ECh. 10.2 - Prob. 24ECh. 10.2 - Prob. 25ECh. 10.2 - Prob. 26ECh. 10.2 - Prob. 27ECh. 10.2 - Prob. 28ECh. 10.2 - Prob. 29ECh. 10.2 - Prob. 30ECh. 10.2 - Prob. 31ECh. 10.2 - Prob. 32ECh. 10.2 - Prob. 33ECh. 10.2 - Prob. 34ECh. 10.2 - Prob. 35ECh. 10.2 - Prob. 36ECh. 10.2 - Prob. 37ECh. 10.2 - Prob. 38ECh. 10.2 - Prob. 39ECh. 10.2 - Prob. 40ECh. 10.2 - Prob. 41ECh. 10.2 - Prob. 42ECh. 10.2 - Prob. 43ECh. 10.2 - Prob. 44ECh. 10.2 - Prob. 45ECh. 10.2 - Prob. 46ECh. 10.2 - Prob. 47ECh. 10.2 - Prob. 48ECh. 10.3 - Prob. 1QRCh. 10.3 - Prob. 2QRCh. 10.3 - Prob. 3QRCh. 10.3 - Prob. 4QRCh. 10.3 - Prob. 5QRCh. 10.3 - Prob. 6QRCh. 10.3 - Prob. 7QRCh. 10.3 - Prob. 8QRCh. 10.3 - Prob. 9QRCh. 10.3 - Prob. 10QRCh. 10.3 - Prob. 1ECh. 10.3 - Prob. 2ECh. 10.3 - Prob. 3ECh. 10.3 - Prob. 4ECh. 10.3 - Prob. 5ECh. 10.3 - Prob. 6ECh. 10.3 - Prob. 7ECh. 10.3 - Prob. 8ECh. 10.3 - Prob. 9ECh. 10.3 - Prob. 10ECh. 10.3 - Prob. 11ECh. 10.3 - Prob. 12ECh. 10.3 - Prob. 13ECh. 10.3 - Prob. 14ECh. 10.3 - Prob. 15ECh. 10.3 - Prob. 16ECh. 10.3 - Prob. 17ECh. 10.3 - Prob. 18ECh. 10.3 - Prob. 19ECh. 10.3 - Prob. 20ECh. 10.3 - Prob. 21ECh. 10.3 - Prob. 22ECh. 10.3 - Prob. 23ECh. 10.3 - Prob. 24ECh. 10.3 - Prob. 25ECh. 10.3 - Prob. 26ECh. 10.3 - Prob. 27ECh. 10.3 - Prob. 28ECh. 10.3 - Prob. 29ECh. 10.3 - Prob. 30ECh. 10.3 - Prob. 31ECh. 10.3 - Prob. 32ECh. 10.3 - Prob. 33ECh. 10.3 - Prob. 34ECh. 10.3 - Prob. 35ECh. 10.3 - Prob. 36ECh. 10.3 - Prob. 37ECh. 10.3 - Prob. 38ECh. 10.3 - Prob. 39ECh. 10.3 - Prob. 40ECh. 10.3 - Prob. 41ECh. 10.3 - Prob. 42ECh. 10.3 - Prob. 43ECh. 10.3 - Prob. 44ECh. 10.3 - Prob. 45ECh. 10.3 - Prob. 46ECh. 10.3 - Prob. 47ECh. 10.3 - Prob. 48ECh. 10.3 - Prob. 49ECh. 10.3 - Prob. 50ECh. 10.3 - Prob. 51ECh. 10.3 - Prob. 52ECh. 10.3 - Prob. 53ECh. 10.3 - Prob. 54ECh. 10.3 - Prob. 55ECh. 10.3 - Prob. 56ECh. 10.3 - Prob. 57ECh. 10.3 - Prob. 58ECh. 10.3 - Prob. 59ECh. 10.3 - Prob. 60ECh. 10.4 - Prob. 1QRCh. 10.4 - Prob. 2QRCh. 10.4 - Prob. 3QRCh. 10.4 - Prob. 4QRCh. 10.4 - Prob. 5QRCh. 10.4 - Prob. 6QRCh. 10.4 - Prob. 7QRCh. 10.4 - Prob. 8QRCh. 10.4 - Prob. 9QRCh. 10.4 - Prob. 10QRCh. 10.4 - Prob. 1ECh. 10.4 - Prob. 2ECh. 10.4 - Prob. 3ECh. 10.4 - Prob. 4ECh. 10.4 - Prob. 5ECh. 10.4 - Prob. 6ECh. 10.4 - Prob. 7ECh. 10.4 - Prob. 8ECh. 10.4 - Prob. 9ECh. 10.4 - Prob. 10ECh. 10.4 - Prob. 11ECh. 10.4 - Prob. 12ECh. 10.4 - Prob. 13ECh. 10.4 - Prob. 14ECh. 10.4 - Prob. 15ECh. 10.4 - Prob. 16ECh. 10.4 - Prob. 17ECh. 10.4 - Prob. 18ECh. 10.4 - Prob. 19ECh. 10.4 - Prob. 20ECh. 10.4 - Prob. 21ECh. 10.4 - Prob. 22ECh. 10.4 - Prob. 23ECh. 10.4 - Prob. 24ECh. 10.4 - Prob. 25ECh. 10.4 - Prob. 26ECh. 10.4 - Prob. 27ECh. 10.4 - Prob. 28ECh. 10.4 - Prob. 29ECh. 10.4 - Prob. 30ECh. 10.4 - Prob. 31ECh. 10.4 - Prob. 32ECh. 10.4 - Prob. 33ECh. 10.4 - Prob. 34ECh. 10.4 - Prob. 35ECh. 10.4 - Prob. 36ECh. 10.4 - Prob. 37ECh. 10.4 - Prob. 38ECh. 10.4 - Prob. 39ECh. 10.4 - Prob. 40ECh. 10.4 - Prob. 41ECh. 10.4 - Prob. 42ECh. 10.4 - Prob. 43ECh. 10.4 - Prob. 44ECh. 10.4 - Prob. 45ECh. 10.4 - Prob. 46ECh. 10.4 - Prob. 47ECh. 10.4 - Prob. 48ECh. 10.4 - Prob. 49ECh. 10.4 - Prob. 50ECh. 10.4 - Prob. 51ECh. 10.4 - Prob. 52ECh. 10.4 - Prob. 53ECh. 10.4 - Prob. 54ECh. 10.4 - Prob. 55ECh. 10.4 - Prob. 56ECh. 10.5 - Prob. 1QRCh. 10.5 - Prob. 2QRCh. 10.5 - Prob. 3QRCh. 10.5 - Prob. 4QRCh. 10.5 - Prob. 5QRCh. 10.5 - Prob. 6QRCh. 10.5 - Prob. 7QRCh. 10.5 - Prob. 8QRCh. 10.5 - Prob. 9QRCh. 10.5 - Prob. 10QRCh. 10.5 - Prob. 1ECh. 10.5 - Prob. 2ECh. 10.5 - Prob. 3ECh. 10.5 - Prob. 4ECh. 10.5 - Prob. 5ECh. 10.5 - Prob. 6ECh. 10.5 - Prob. 7ECh. 10.5 - Prob. 8ECh. 10.5 - Prob. 9ECh. 10.5 - Prob. 10ECh. 10.5 - Prob. 11ECh. 10.5 - Prob. 12ECh. 10.5 - Prob. 13ECh. 10.5 - Prob. 14ECh. 10.5 - Prob. 15ECh. 10.5 - Prob. 16ECh. 10.5 - Prob. 17ECh. 10.5 - Prob. 18ECh. 10.5 - Prob. 19ECh. 10.5 - Prob. 20ECh. 10.5 - Prob. 21ECh. 10.5 - Prob. 22ECh. 10.5 - Prob. 23ECh. 10.5 - Prob. 24ECh. 10.5 - Prob. 25ECh. 10.5 - Prob. 26ECh. 10.5 - Prob. 27ECh. 10.5 - Prob. 28ECh. 10.5 - Prob. 29ECh. 10.5 - Prob. 30ECh. 10.5 - Prob. 31ECh. 10.5 - Prob. 32ECh. 10.5 - Prob. 33ECh. 10.5 - Prob. 34ECh. 10.5 - Prob. 35ECh. 10.5 - Prob. 36ECh. 10.5 - Prob. 37ECh. 10.5 - Prob. 38ECh. 10.5 - Prob. 39ECh. 10.5 - Prob. 40ECh. 10.5 - Prob. 41ECh. 10.5 - Prob. 42ECh. 10.5 - Prob. 43ECh. 10.5 - Prob. 44ECh. 10.5 - Prob. 45ECh. 10.5 - Prob. 46ECh. 10.5 - Prob. 47ECh. 10.5 - Prob. 48ECh. 10.5 - Prob. 49ECh. 10.5 - Prob. 50ECh. 10.5 - Prob. 51ECh. 10.5 - Prob. 52ECh. 10.5 - Prob. 55ECh. 10.5 - Prob. 56ECh. 10.5 - Prob. 59ECh. 10.5 - Prob. 60ECh. 10 - Prob. 1RECh. 10 - Prob. 2RECh. 10 - Prob. 3RECh. 10 - Prob. 4RECh. 10 - Prob. 5RECh. 10 - Prob. 6RECh. 10 - Prob. 7RECh. 10 - Prob. 8RECh. 10 - Prob. 9RECh. 10 - Prob. 10RECh. 10 - Prob. 11RECh. 10 - Prob. 12RECh. 10 - Prob. 13RECh. 10 - Prob. 14RECh. 10 - Prob. 15RECh. 10 - Prob. 16RECh. 10 - Prob. 17RECh. 10 - Prob. 18RECh. 10 - Prob. 19RECh. 10 - Prob. 20RECh. 10 - Prob. 21RECh. 10 - Prob. 22RECh. 10 - Prob. 23RECh. 10 - Prob. 24RECh. 10 - Prob. 25RECh. 10 - Prob. 26RECh. 10 - Prob. 27RECh. 10 - Prob. 28RECh. 10 - Prob. 29RECh. 10 - Prob. 30RECh. 10 - Prob. 31RECh. 10 - Prob. 32RECh. 10 - Prob. 33RECh. 10 - Prob. 34RECh. 10 - Prob. 35RECh. 10 - Prob. 36RECh. 10 - Prob. 37RECh. 10 - Prob. 38RECh. 10 - Prob. 39RECh. 10 - Prob. 40RECh. 10 - Prob. 41RECh. 10 - Prob. 42RECh. 10 - Prob. 43RECh. 10 - Prob. 44RECh. 10 - Prob. 45RECh. 10 - Prob. 46RECh. 10 - Prob. 47RECh. 10 - Prob. 48RECh. 10 - Prob. 49RECh. 10 - Prob. 50RECh. 10 - Prob. 51RECh. 10 - Prob. 52RECh. 10 - Prob. 53RECh. 10 - Prob. 54RECh. 10 - Prob. 55RECh. 10 - Prob. 56RECh. 10 - Prob. 57RECh. 10 - Prob. 58RECh. 10 - Prob. 59RECh. 10 - Prob. 60RECh. 10 - Prob. 61RECh. 10 - Prob. 62RECh. 10 - Prob. 63RECh. 10 - Prob. 64RECh. 10 - Prob. 65RECh. 10 - Prob. 66RECh. 10 - Prob. 67RECh. 10 - Prob. 68RECh. 10 - Prob. 69RECh. 10 - Prob. 70RECh. 10 - Prob. 71RECh. 10 - Prob. 72RE
Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Calculus: Early Transcendentals
Calculus
ISBN:9781285741550
Author:James Stewart
Publisher:Cengage Learning
Text book image
Thomas' Calculus (14th Edition)
Calculus
ISBN:9780134438986
Author:Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:PEARSON
Text book image
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:9780134763644
Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:PEARSON
Text book image
Calculus: Early Transcendentals
Calculus
ISBN:9781319050740
Author:Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:W. H. Freeman
Text book image
Precalculus
Calculus
ISBN:9780135189405
Author:Michael Sullivan
Publisher:PEARSON
Text book image
Calculus: Early Transcendental Functions
Calculus
ISBN:9781337552516
Author:Ron Larson, Bruce H. Edwards
Publisher:Cengage Learning
SEE MORE TEXTBOOKS