a.
To find: The mean and the standard deviation of the number of targets he’d hit if the new bow were no more accurate than the old.
The required value of mean is 32.5 and the value of standard deviation is 3.37
Given information:
Percentage of target hit: 65%
On testing new bow, he hit 41 of the first 50 targets.
Calculation:
The computation of mean is shown.
The computation of standard deviation is shown.
b.
The objective is to explain why a normal model can be used to describe the distribution of targets hit.
Yes, the numbers of expected hits (32.5) and misses (17.5) are both greater than 10.
Given information:
Percentage of target hit: 65%
On testing new bow, he hit 41 of the first 50 targets.
Concept used:
If we expect at least 10 successes and 10 failures
Explanation:
Since
Thus, it can follow normal distribution.
c.
The objective is to determine if it is plausible that his performance was just a run of good luck, or was this evidence that he is a much better shot with the new bow?
The z-score for 41 hits is 2.52, statistically significant evidence of improvement.
Given information:
Percentage of target hit: 65%
On testing new bow, he hit 41 of the first 50 targets.
Explanation:
The computation of z-score is shown:
It means there statistically significant evidence of improvement.
Chapter 10 Solutions
PRECALCULUS:GRAPHICAL,...-NASTA ED.
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