
(a)
Interpretation:
The formation of +3 ions in praseodymium needs to be explained.
Concept introduction:
Electronic configurations of the atoms of the elements in the ground state are determined with the help of Aufbau principle, hund’s rule and Paulie’s Exclusion principle.

Answer to Problem 117A
Praseodymium loses 3 electrons in 4f orbital because 4f orbital has higher energy than 6s orbital.
Explanation of Solution
Given the electronic configuration of praseodymium is [Xe]4f36s2. Praseodymium has 2 electrons in 6s orbital. Praseodymium loses 3 electrons in 4f orbital because 4f orbital has higher energy than 6s orbital.
(b)
Interpretation:
The correct formulas for both compounds that formed by praseodymium needs to be determined.
Concept introduction:
Electronic configurations of the atoms of the elements in the ground state are determined with the help of Aufbau principle, hund’s rule and Paulie’s Exclusion principle.
(b)

Answer to Problem 117A
The correct formulas for both compounds that formed by praseodymium PrN and PrCl3.
Explanation of Solution
From the reaction of hydrochloric and Praseodymium ionic compounds are formed. With praseodymium (III) cation, PrCl3 chloride anion carries -1 charge and form 1:3 compound. From the reaction of nitric acid and Praseodymium ionic compounds are formed. praseodymium (III) nitride, PrN carries -3 charge and form 1:1 compound.
Chapter 7 Solutions
Glencoe Chemistry: Matter and Change, Student Edition
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