(a)
Interpretation:
The correct formula for compound, AlCl needs to be determined.
Concept introduction:
The formula for ionic compound is written as based on the charge of cation and anion. The technique used mostly is crisscross method wherein the charges become subscript of the opposite ion. If the numbers are high, it is reduced to lowest ratio.
(a)
Answer to Problem 85A
The correct chemical formula for ionic compound AlCl is AlCl3
Explanation of Solution
The ionic compound is AlCl.
Al is aluminum which has
Cl is Chlorine having atomic number as 17 with configuration as 1s22s22p63s23p5. It has 7 valence electrons. Hence, it will need one electron to get octet and becomes Cl−
For the compound having Al3+ and Cl− is
(b)
Interpretation:
The correct formula for compound, Na3SO4 needs to be determined.
Concept introduction:
The formula for ionic compound is written as based on the charge of cation and anion. The technique used mostly is crisscross method wherein the charge becomes subscript of the opposite ion. If the numbers are high, it is reduced to lowest ratio.
(b)
Answer to Problem 85A
The correct chemical formula for ionic compound Na3SO4 is Na2SO4
Explanation of Solution
The ionic compound is Na3SO4
Na is Sodium which has atomic number 11 with configuration as 1s22s22p63s1. It has 1 valence electrons. Hence, it will lose one electron to get octet and become Na+.
SO4 is sulphate, SO42−, having charge of -2.
For the compound having Na+ and SO42− is
(c)
Interpretation:
The correct formula for compound, BaOH2 needs to be determined.
Concept introduction:
The formula for ionic compound is written as based on the charge of cation and anion. The technique used mostly is crisscross method wherein the charge becomes subscript of the opposite ion. If the numbers are high, it is reduced to lowest ratio.
(c)
Answer to Problem 85A
The correct chemical formula for ionic compound BaOH2 is Ba(OH)2
Explanation of Solution
The ionic compound is BaOH2
Ba is Barium which has atomic number 56 with configuration as 1s22s22p63s1 3p63d104s24p64d105s25p66s2. It has 2 valence electrons. Hence, it will lose two electrons to get octet and become Ba2+.
OH is hydroxide ion and has charge of -1.
For the compound having Ba2+ and OH− is
(d)
Interpretation:
The correct formula for compound, Fe2O needs to be determined.
Concept introduction:
The formula for ionic compound is written as based on the charge of cation and anion. The technique used mostly is crisscross method wherein the charges becomes subscript of the opposite ion. If the numbers are high, it is reduced to lowest ratio.
Answer to Problem 85A
The correct chemical formula for ionic compound Fe2O is Fe2O3 or FeO
Explanation of Solution
The ionic compound is Fe2O .
Fe is Iron which has atomic number 26 with configuration as 1s22s22p63s2 3p64s23d6. It has 6 valence electrons. Hence, it will lose two electrons to get octet and become Fe2+. It can also lose 3 electrons and become Fe3+
O is Oxygen having atomic number as 8 with configuration as 1s22s22p4. It has 6 valence electrons. Hence, it will need two electrons to get octet and becomes O2−
For the compound having Fe2+ and O2− is
For compound having Fe3+ and O2− is
For compound having Fe3+ and O2− is
Chapter 7 Solutions
Glencoe Chemistry: Matter and Change, Student Edition
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