Chapter 7, Problem 54A

Interpretation Introduction

Interpretation:

The formation of Barium ion needs to be explained.

Concept introduction:

The formation of ion takes place when there is deficiency of electrons in the outermost shell. The electron can be lost to form a cation or electron can be gained to form an anion.

Answer to Problem 54A

Barium loses two electrons to become Barium ion.

Explanation of Solution

Barium belongs to Group 2 of periodic table. It has atomic number of 56. It has electronic configuration as

${\text{1s}}^{2}2{\text{s}}^{\text{2}}2{\text{p}}^6{\text{3s}}^{\text{2}}{\text{3p}}^6{\text{4s}}^{\text{2}}{\text{3d}}^{10}{\text{4p}}^6{\text{5s}}^2{\text{4d}}^{10}{\text{5p}}^{\text{6}}6{\text{s}}^{\text{2}}$

It has two valence electrons and this element will lose the two electrons to become a positive ion to get configuration of Nobel gas Xenon.

$\text{Ba }\stackrel{-2e^{-}}{\to }{\text{ Ba}}^{2+}$

Conclusion

Barium loses two electrons to become Barium ion.