Concept explainers
(a)
Interpretation:
“Parent” amine can be regenerated from the given salt or not has to be indicated.
Concept Introduction:
Quaternary ammonium salt is the one that has four carbon atoms attached to the nitrogen atom. This is formed by the reaction of tertiary amine with
Neutralization reaction is the one that takes place between an acid and a base to give salt as product. As
When a strong base is added to the amine salt, the parent amine can be obtained. This is a reverse reaction of the amine salt formation reaction. These reactions can be represented as shown below,
Quaternary ammonium salt does not give the “parent” amine when treated with a strong base as there is no possibility of deprotonation to take place.
(b)
Interpretation:
“Parent” amine can be regenerated from the given salt or not has to be indicated.
Concept Introduction:
Quaternary ammonium salt is the one that has four carbon atoms attached to the nitrogen atom. This is formed by the reaction of tertiary amine with alkyl halide in presence of a strong base.
Neutralization reaction is the one that takes place between an acid and a base to give salt as product. As amines are bases due to the amino group in it, the reaction with inorganic acid or carboxylic acid gives salt as product. The salt formed is an amine salt. Proton is donated from the acid to the nitrogen atom which acts as a proton acceptor. In simple words, it can be said that in an amine‑acid reaction, the acid loses a hydrogen ion and amine gains a hydrogen ion.
When a strong base is added to the amine salt, the parent amine can be obtained. This is a reverse reaction of the amine salt formation reaction. These reactions can be represented as shown below,
Quaternary ammonium salt does not give the “parent” amine when treated with a strong base as there is no possibility of deprotonation to take place.
(c)
Interpretation:
“Parent” amine can be regenerated from the given salt or not has to be indicated.
Concept Introduction:
Quaternary ammonium salt is the one that has four carbon atoms attached to the nitrogen atom. This is formed by the reaction of tertiary amine with alkyl halide in presence of a strong base.
Neutralization reaction is the one that takes place between an acid and a base to give salt as product. As amines are bases due to the amino group in it, the reaction with inorganic acid or carboxylic acid gives salt as product. The salt formed is an amine salt. Proton is donated from the acid to the nitrogen atom which acts as a proton acceptor. In simple words, it can be said that in an amine‑acid reaction, the acid loses a hydrogen ion and amine gains a hydrogen ion.
When a strong base is added to the amine salt, the parent amine can be obtained. This is a reverse reaction of the amine salt formation reaction. These reactions can be represented as shown below,
Quaternary ammonium salt does not give the “parent” amine when treated with a strong base as there is no possibility of deprotonation to take place.
(d)
Interpretation:
“Parent” amine can be regenerated from the given salt or not has to be indicated.
Concept Introduction:
Quaternary ammonium salt is the one that has four carbon atoms attached to the nitrogen atom. This is formed by the reaction of tertiary amine with alkyl halide in presence of a strong base.
Neutralization reaction is the one that takes place between an acid and a base to give salt as product. As amines are bases due to the amino group in it, the reaction with inorganic acid or carboxylic acid gives salt as product. The salt formed is an amine salt. Proton is donated from the acid to the nitrogen atom which acts as a proton acceptor. In simple words, it can be said that in an amine‑acid reaction, the acid loses a hydrogen ion and amine gains a hydrogen ion.
When a strong base is added to the amine salt, the parent amine can be obtained. This is a reverse reaction of the amine salt formation reaction. These reactions can be represented as shown below,
Quaternary ammonium salt does not give the “parent” amine when treated with a strong base as there is no possibility of deprotonation to take place.
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Chapter 6 Solutions
EBK ORGANIC AND BIOLOGICAL CHEMISTRY
- What is the molarisuty of a 0.396 m glucose solution if its density is 1.16 g/mL? MM glucose 180.2 /mol.arrow_forwardProvide the proper IUPAC or common name for the following compound. Dashes, commas, and spaces must be used correctly. Br ......Im OHarrow_forwardCan you please help me solve this problems. The top one is just drawing out the skeletal correct and then the bottom one is just very confusing to me and its quite small in the images. Can you enlarge it and explain it to me please. Thank You much (ME EX1) Prblm #33arrow_forward
- I'm trying to memorize VESPR Shapes to solve problems like those. I need help making circles like the second image in blue or using an x- and y-axis plane to memorize these and solve those types of problems, especially the ones given in the top/first image (180, 120, 109.5). Can you help me with this? or is their any other efficient method do soarrow_forwardCan you please explain this problems to me? I'm very confused about it. Please provide a detailed, step-by-step explanation for me! (ME EX1) Prblm 27arrow_forwardQuestion 6 of 7 (1 point) | Question Attempt: 1 of 1 = 1 ✓2 ✓ 3 ✓ 4 ✓ 5 6 ✓ 7 This organic molecule is dissolved in a basic aqueous solution: Jen ✓ ? A short time later sensitive infrared spectroscopy reveals the presence of a new C-OH stretch absorption. That is, must now be a new molecule present with at least one C- OH bond. there 18 In the drawing area below, show the detailed mechanism that could convert the molecule above into the new molecule Ar © + Click and drag to start drawing a structure. Add/Remove step Click and drawing Save For Later Submit Assignmentarrow_forward
- Can you please explain this problem to me? I'm very confused about it. Please provide a detailed, step-by-step explanation for me! (ME EX1) Prblm 22arrow_forwardCan you please explain this problems to me? I'm very confused about it. Please provide a detailed, step-by-step explanation for me! (ME EX1) Prblm 30arrow_forwardThis organic molecule is dissolved in a basic aqueous solution: O ? olo RET A short time later sensitive infrared spectroscopy reveals the presence of a new C-OH stretch absorption. That is, there Ar must now be a new molecule present with at least one C - OH bond. In the drawing area below, show the detailed mechanism that could convert the molecule above into the new molecule. $ Add/Remove steparrow_forward
- So the thing is im trying to memorize VESPR Shapes in order to be able to solve problems like so, and I need help with making circles like the second image that's in blue or using an x and y axis plane in order to memorize these and be able to solve those type of problems. Especially like the ones given in the top / first image. (180 , 120 , 109.5) Can you help me with this.arrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward2. (15 points) Draw an appropriate mechanism for the following reaction. H N. H* + H₂Oarrow_forward
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