EBK ORGANIC AND BIOLOGICAL CHEMISTRY
EBK ORGANIC AND BIOLOGICAL CHEMISTRY
7th Edition
ISBN: 9780100547742
Author: STOKER
Publisher: YUZU
Question
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Chapter 6, Problem 6.49EP

(a)

Interpretation Introduction

Interpretation:

Structural formula of the salt that is produced by reaction between ethylamine and HCl has to be drawn.

Concept Introduction:

Neutralization reaction is the one that takes place between an acid and a base to give salt as product.  As amines are bases due to the amino group in it, the reaction with inorganic acid or carboxylic acid gives salt as product.  The salt formed is an amine salt.  Proton is donated from the acid to the nitrogen atom which acts as a proton acceptor.  In simple words, it can be said that in an amine‑acid reaction, the acid loses a hydrogen ion and amine gains a hydrogen ion.

(b)

Interpretation Introduction

Interpretation:

Structural formula of the salt that is produced by reaction between cyclopentylamine and HCl has to be drawn.

Concept Introduction:

Neutralization reaction is the one that takes place between an acid and a base to give salt as product.  As amines are bases due to the amino group in it, the reaction with inorganic acid or carboxylic acid gives salt as product.  The salt formed is an amine salt.  Proton is donated from the acid to the nitrogen atom which acts as a proton acceptor.  In simple words, it can be said that in an amine‑acid reaction, the acid loses a hydrogen ion and amine gains a hydrogen ion.

(c)

Interpretation Introduction

Interpretation:

Structural formula of the salt that is produced by reaction between isopropylamine and HCl has to be drawn.

Concept Introduction:

Neutralization reaction is the one that takes place between an acid and a base to give salt as product.  As amines are bases due to the amino group in it, the reaction with inorganic acid or carboxylic acid gives salt as product.  The salt formed is an amine salt.  Proton is donated from the acid to the nitrogen atom which acts as a proton acceptor.  In simple words, it can be said that in an amine‑acid reaction, the acid loses a hydrogen ion and amine gains a hydrogen ion.

(d)

Interpretation Introduction

Interpretation:

Structural formula of the salt that is produced by reaction between ethylethylamine and HCl has to be drawn.

Concept Introduction:

Neutralization reaction is the one that takes place between an acid and a base to give salt as product.  As amines are bases due to the amino group in it, the reaction with inorganic acid or carboxylic acid gives salt as product.  The salt formed is an amine salt.  Proton is donated from the acid to the nitrogen atom which acts as a proton acceptor.  In simple words, it can be said that in an amine‑acid reaction, the acid loses a hydrogen ion and amine gains a hydrogen ion.

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For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3) → Give the expression for the acceptable rate. → → (A). d[N205] dt == 2k,k₂[N₂O₂] k₁+k₁₂ (B). d[N2O5] =-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³ dt (C). d[N2O5] =-k₁[N₂O] + k [NO] - k₂[NO] [NO] d[N2O5] (D). = dt = -k₁[N2O5] - k¸[NO][N₂05] dt Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3) → Give the expression for the acceptable rate. → → (A). d[N205] dt == 2k,k₂[N₂O₂] k₁+k₁₂ (B). d[N2O5] =-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³ dt (C). d[N2O5] =-k₁[N₂O] + k [NO] - k₂[NO] [NO] d[N2O5] (D). = dt = -k₁[N2O5] - k¸[NO][N₂05] dt Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
R lactam or lactone considering as weak acid or weak base and why

Chapter 6 Solutions

EBK ORGANIC AND BIOLOGICAL CHEMISTRY

Ch. 6.4 - Prob. 1QQCh. 6.4 - Prob. 2QQCh. 6.5 - Prob. 1QQCh. 6.5 - Prob. 2QQCh. 6.5 - Prob. 3QQCh. 6.6 - Prob. 1QQCh. 6.6 - Prob. 2QQCh. 6.6 - Prob. 3QQCh. 6.7 - Prob. 1QQCh. 6.7 - Prob. 2QQCh. 6.7 - Prob. 3QQCh. 6.8 - Prob. 1QQCh. 6.8 - Prob. 2QQCh. 6.8 - Prob. 3QQCh. 6.8 - Prob. 4QQCh. 6.9 - Prob. 1QQCh. 6.9 - Prob. 2QQCh. 6.10 - Prob. 1QQCh. 6.10 - Prob. 2QQCh. 6.10 - Prob. 3QQCh. 6.10 - Prob. 4QQCh. 6.11 - Prob. 1QQCh. 6.11 - Prob. 2QQCh. 6.11 - Prob. 3QQCh. 6.12 - Prob. 1QQCh. 6.12 - Prob. 2QQCh. 6.12 - Prob. 3QQCh. 6.12 - Prob. 4QQCh. 6.13 - Prob. 1QQCh. 6.13 - Prob. 2QQCh. 6.13 - Prob. 3QQCh. 6.13 - Prob. 4QQCh. 6.14 - Prob. 1QQCh. 6.14 - Prob. 2QQCh. 6.14 - Prob. 3QQCh. 6.15 - Prob. 1QQCh. 6.15 - Prob. 2QQCh. 6.16 - Prob. 1QQCh. 6.16 - Prob. 2QQCh. 6.16 - Prob. 3QQCh. 6.17 - Prob. 1QQCh. 6.17 - Prob. 2QQCh. 6.17 - Prob. 3QQCh. 6.18 - Prob. 1QQCh. 6.18 - Prob. 2QQCh. 6.18 - Prob. 3QQCh. 6.19 - Prob. 1QQCh. 6.19 - Prob. 2QQCh. 6.19 - Prob. 3QQCh. 6.19 - Prob. 4QQCh. 6 - Prob. 6.1EPCh. 6 - Prob. 6.2EPCh. 6 - Prob. 6.3EPCh. 6 - Prob. 6.4EPCh. 6 - Prob. 6.5EPCh. 6 - Prob. 6.6EPCh. 6 - Prob. 6.7EPCh. 6 - Indicate whether or not each of the following...Ch. 6 - Indicate whether each of the compounds in Problem...Ch. 6 - Prob. 6.10EPCh. 6 - Prob. 6.11EPCh. 6 - Prob. 6.12EPCh. 6 - Prob. 6.13EPCh. 6 - Prob. 6.14EPCh. 6 - Prob. 6.15EPCh. 6 - Prob. 6.16EPCh. 6 - Prob. 6.17EPCh. 6 - Assign an IUPAC name to each of the following...Ch. 6 - Prob. 6.19EPCh. 6 - Prob. 6.20EPCh. 6 - Prob. 6.21EPCh. 6 - Prob. 6.22EPCh. 6 - Prob. 6.23EPCh. 6 - Prob. 6.24EPCh. 6 - Prob. 6.25EPCh. 6 - Classify each of the following compounds as a 1...Ch. 6 - Prob. 6.27EPCh. 6 - Prob. 6.28EPCh. 6 - Prob. 6.29EPCh. 6 - Prob. 6.30EPCh. 6 - Prob. 6.31EPCh. 6 - Prob. 6.32EPCh. 6 - Prob. 6.33EPCh. 6 - Prob. 6.34EPCh. 6 - Determine the maximum number of hydrogen bonds...Ch. 6 - Prob. 6.36EPCh. 6 - Although they have similar molecular masses (73...Ch. 6 - Prob. 6.38EPCh. 6 - Prob. 6.39EPCh. 6 - Prob. 6.40EPCh. 6 - Show the structures of the missing substance(s) in...Ch. 6 - Prob. 6.42EPCh. 6 - Prob. 6.43EPCh. 6 - Prob. 6.44EPCh. 6 - Prob. 6.45EPCh. 6 - Prob. 6.46EPCh. 6 - Prob. 6.47EPCh. 6 - Prob. 6.48EPCh. 6 - Prob. 6.49EPCh. 6 - Prob. 6.50EPCh. 6 - Prob. 6.51EPCh. 6 - Prob. 6.52EPCh. 6 - Prob. 6.53EPCh. 6 - Prob. 6.54EPCh. 6 - Prob. 6.55EPCh. 6 - Prob. 6.56EPCh. 6 - Prob. 6.57EPCh. 6 - Prob. 6.58EPCh. 6 - Prob. 6.59EPCh. 6 - Prob. 6.60EPCh. 6 - Prob. 6.61EPCh. 6 - Prob. 6.62EPCh. 6 - Prob. 6.63EPCh. 6 - Prob. 6.64EPCh. 6 - Prob. 6.65EPCh. 6 - Prob. 6.66EPCh. 6 - Prob. 6.67EPCh. 6 - Prob. 6.68EPCh. 6 - Prob. 6.69EPCh. 6 - Prob. 6.70EPCh. 6 - Prob. 6.71EPCh. 6 - Prob. 6.72EPCh. 6 - Prob. 6.73EPCh. 6 - Prob. 6.74EPCh. 6 - Name each of the salts in Problem 17-71. a....Ch. 6 - Prob. 6.76EPCh. 6 - Indicate whether or not each of the following...Ch. 6 - Prob. 6.78EPCh. 6 - Prob. 6.79EPCh. 6 - Prob. 6.80EPCh. 6 - Prob. 6.81EPCh. 6 - Prob. 6.82EPCh. 6 - Prob. 6.83EPCh. 6 - Prob. 6.84EPCh. 6 - Prob. 6.85EPCh. 6 - Prob. 6.86EPCh. 6 - Prob. 6.87EPCh. 6 - Prob. 6.88EPCh. 6 - Prob. 6.89EPCh. 6 - Prob. 6.90EPCh. 6 - Prob. 6.91EPCh. 6 - Indicate whether each of the following statements...Ch. 6 - Prob. 6.93EPCh. 6 - Prob. 6.94EPCh. 6 - Prob. 6.95EPCh. 6 - Prob. 6.96EPCh. 6 - Prob. 6.97EPCh. 6 - Prob. 6.98EPCh. 6 - Indicate whether or not each of the following...Ch. 6 - Prob. 6.100EPCh. 6 - Classify each of the following amides as...Ch. 6 - Classify each of the following amides as...Ch. 6 - Prob. 6.103EPCh. 6 - Prob. 6.104EPCh. 6 - Prob. 6.105EPCh. 6 - Prob. 6.106EPCh. 6 - Prob. 6.107EPCh. 6 - Assign an IUPAC name to each of the following...Ch. 6 - Prob. 6.109EPCh. 6 - Prob. 6.110EPCh. 6 - Prob. 6.111EPCh. 6 - Prob. 6.112EPCh. 6 - Prob. 6.113EPCh. 6 - Prob. 6.114EPCh. 6 - Prob. 6.115EPCh. 6 - Prob. 6.116EPCh. 6 - Prob. 6.117EPCh. 6 - Prob. 6.118EPCh. 6 - Prob. 6.119EPCh. 6 - Prob. 6.120EPCh. 6 - Prob. 6.121EPCh. 6 - Prob. 6.122EPCh. 6 - Prob. 6.123EPCh. 6 - Prob. 6.124EPCh. 6 - Prob. 6.125EPCh. 6 - Prob. 6.126EPCh. 6 - Prob. 6.127EPCh. 6 - Prob. 6.128EPCh. 6 - Prob. 6.129EPCh. 6 - Prob. 6.130EPCh. 6 - Prob. 6.131EPCh. 6 - Prob. 6.132EPCh. 6 - Prob. 6.133EPCh. 6 - Prob. 6.134EPCh. 6 - Prob. 6.135EPCh. 6 - Prob. 6.136EPCh. 6 - Prob. 6.137EPCh. 6 - Prob. 6.138EPCh. 6 - Prob. 6.139EPCh. 6 - Prob. 6.140EPCh. 6 - Prob. 6.141EPCh. 6 - Prob. 6.142EPCh. 6 - Prob. 6.143EPCh. 6 - Prob. 6.144EPCh. 6 - Prob. 6.145EPCh. 6 - Draw the structure of the nitrogen-containing...Ch. 6 - Prob. 6.147EPCh. 6 - Prob. 6.148EPCh. 6 - Prob. 6.149EPCh. 6 - Prob. 6.150EPCh. 6 - Prob. 6.151EPCh. 6 - Prob. 6.152EPCh. 6 - Prob. 6.153EPCh. 6 - Prob. 6.154EP
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