Concept explainers
(a)
Interpretation:
Common name of the given compound has to be assigned.
Concept Introduction:
- Longest carbon chain has to be identified that is attached to nitrogen atom.
- Suffix “-e” in name of the parent chain
alkane is replaced by “-amine”. - Numbering of the carbon chain is done from the end that is near the nitrogen atom.
- Point of attachment of the nitrogen atom in the carbon chain is indicated by a number before the parent chain name.
- In case if substituents are present, then the identity and location of substituents are appended to the front in the parent chain name.
If the compound contains two amine groups, then the suffix “-e” is replaced by diamine. Tertiary and secondary
Common name for amine is given in a single word. Primary amine is named as alkylamine. Secondary amine is named as alkylalkylamine. Tertiary amine is named as alkylalkylalkylamine.
(b)
Interpretation:
Common name of the given compound has to be assigned.
Concept Introduction:
IUPAC nomenclature for amine: There are about five rules to be followed in giving IUPAC name for an amine.
- Longest carbon chain has to be identified that is attached to nitrogen atom.
- Suffix “-e” in name of the parent chain alkane is replaced by “-amine”.
- Numbering of the carbon chain is done from the end that is near the nitrogen atom.
- Point of attachment of the nitrogen atom in the carbon chain is indicated by a number before the parent chain name.
- In case if substituents are present, then the identity and location of substituents are appended to the front in the parent chain name.
If the compound contains two amine groups, then the suffix “-e” is replaced by diamine. Tertiary and secondary amines are named as N-substituted primary amines.
Common name for amine is given in a single word. Primary amine is named as alkylamine. Secondary amine is named as alkylalkylamine. Tertiary amine is named as alkylalkylalkylamine.
(c)
Interpretation:
Common name of the given compound has to be assigned.
Concept Introduction:
IUPAC nomenclature for amine: There are about five rules to be followed in giving IUPAC name for an amine.
- Longest carbon chain has to be identified that is attached to nitrogen atom.
- Suffix “-e” in name of the parent chain alkane is replaced by “-amine”.
- Numbering of the carbon chain is done from the end that is near the nitrogen atom.
- Point of attachment of the nitrogen atom in the carbon chain is indicated by a number before the parent chain name.
- In case if substituents are present, then the identity and location of substituents are appended to the front in the parent chain name.
If the compound contains two amine groups, then the suffix “-e” is replaced by diamine. Tertiary and secondary amines are named as N-substituted primary amines.
Common name for amine is given in a single word. Primary amine is named as alkylamine. Secondary amine is named as alkylalkylamine. Tertiary amine is named as alkylalkylalkylamine.
(d)
Interpretation:
Common name of the given compound has to be assigned.
Concept Introduction:
IUPAC nomenclature for amine: There are about five rules to be followed in giving IUPAC name for an amine.
- Longest carbon chain has to be identified that is attached to nitrogen atom.
- Suffix “-e” in name of the parent chain alkane is replaced by “-amine”.
- Numbering of the carbon chain is done from the end that is near the nitrogen atom.
- Point of attachment of the nitrogen atom in the carbon chain is indicated by a number before the parent chain name.
- In case if substituents are present, then the identity and location of substituents are appended to the front in the parent chain name.
If the compound contains two amine groups, then the suffix “-e” is replaced by diamine. Tertiary and secondary amines are named as N-substituted primary amines.
Common name for amine is given in a single word. Primary amine is named as alkylamine. Secondary amine is named as alkylalkylamine. Tertiary amine is named as alkylalkylalkylamine.
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Chapter 6 Solutions
EBK ORGANIC AND BIOLOGICAL CHEMISTRY
- There is an instrument in Johnson 334 that measures total-reflectance x-ray fluorescence (TXRF) to do elemental analysis (i.e., determine what elements are present in a sample). A researcher is preparing a to measure calcium content in a series of well water samples by TXRF with an internal standard of vanadium (atomic symbol: V). She has prepared a series of standard solutions to ensure a linear instrument response over the expected Ca concentration range of 40-80 ppm. The concentrations of Ca and V (ppm) and the instrument response (peak area, arbitrary units) are shown below. Also included is a sample spectrum. Equation 1 describes the response factor, K, relating the analyte signal (SA) and the standard signal (SIS) to their respective concentrations (CA and CIS). Ca, ppm V, ppm SCa, arb. units SV, arb. units 20.0 10.0 14375.11 14261.02 40.0 10.0 36182.15 17997.10 60.0 10.0 39275.74 12988.01 80.0 10.0 57530.75 14268.54 100.0…arrow_forwardA mixture of 0.568 M H₂O, 0.438 M Cl₂O, and 0.710 M HClO are enclosed in a vessel at 25 °C. H₂O(g) + C₁₂O(g) = 2 HOCl(g) K = 0.0900 at 25°C с Calculate the equilibrium concentrations of each gas at 25 °C. [H₂O]= [C₁₂O]= [HOCI]= M Σ Marrow_forwardWhat units (if any) does the response factor (K) have? Does the response factor (K) depend upon how the concentration is expressed (e.g. molarity, ppm, ppb, etc.)?arrow_forward
- Provide the structure, circle or draw, of the monomeric unit found in the biological polymeric materials given below. HO OH amylose OH OH 행 3 HO cellulose OH OH OH Ho HOarrow_forwardWhat units (if any) does K have? Does K depend upon how the concentration is expressed (e.g. molarity, ppm, ppb, etc.)? in calculating the response factorarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
- Don't used Ai solution and don't used hand raitingarrow_forwardOA. For the structure shown, rank the bond lengths (labeled a, b and c) from shortest to longest. Place your answer in the box. Only the answer in the box will be graded. (2 points) H -CH3 THe b Нarrow_forwardDon't used hand raitingarrow_forward
- Quizzes - Gen Organic & Biological Che... ☆ myd21.lcc.edu + O G screenshot on mac - Google Search savings hulu youtube google disney+ HBO zlib Homework Hel...s | bartleby cell bio book Yuzu Reader: Chemistry G periodic table - Google Search b Home | bartleby 0:33:26 remaining CHEM 120 Chapter 5_Quiz 3 Page 1: 1 > 2 > 3 > 6 ¦ 5 > 4 > 7 ¦ 1 1 10 8 ¦ 9 a ¦ -- Quiz Information silicon-27 A doctor gives a patient 0.01 mC i of beta radiation. How many beta particles would the patient receive in I minute? (1 Ci = 3.7 x 10 10 d/s) Question 5 (1 point) Saved Listen 2.22 x 107 222 x 108 3.7 x 108 2.22 x 108 none of the above Question 6 (1 point) Listen The recommended dosage of 1-131 for a test is 4.2 μCi per kg of body mass. How many millicuries should be given to a 55 kg patient? (1 mCi = 1000 μСi)? 230 mCiarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
- General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningOrganic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
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